Lecture 3-4 Flashcards
τ =
shear stress =
change in Ft / A
change in the tangential force / area
Pulling effect is —– stress
tensile
Pushing effect is —– stress
compressive
Tangential effect is —– stress
shear
When resolving the force equilibrium how do we intially set out the equation to prove that the stresses on both sides of the same body are equal?
(σ y X change in x X change in z) - (σ’ y X change in x X change in z)
+
(τ xy X change in y X change in z) - (τ’ xy X change in y X change in z)
+
(τ zy X change in x X change in y) - (τ’ zy X change in x X change in y)
= which simplifies to
(σ y - σ’ y) change in x X change in z
+
(τ xy - τ xy’) change in y X change in z
+
(τ zy - τ zy’) change in x X change in y
And as change in x/y/z tends to 0. Each σ/τ is equal to eachother
γ =
shear strain =
π / 2 - (θ’)
90 degrees intial angle - (the 90 degree angle after deformation)
F.S. =
factor of safety =
σ fail / σ allow
Hooke’s Law relationship between stress and strain
Linear relationship, directly proportional relationship
Poisson’s ratio states that elongation in one direction leads to….
a contraction in an orthogonal direction
ν =
poissons ratio =
− εy / εx
- strain in y / strain in x
Torsional deformation of a circular shaft is when…. (reference radial and longitudinal lines)
over time and wear the whole shaft twists and the longitudinal lines (lines parallel to the shaft) become twisted. Radial lines stay straight
For torsional deflection what do we use instead of young’s modulus?
Shear modulus
G =
shear modulus =
shear stress / shear strain
Φ =
angle of twist =
T L / J G
torque force X length of bar / property of the area X shear modulus