Lecture 21 Flashcards

1
Q

progeria = mutation in lamin-encoding gene

A

3 genes encode lamin proteins
LMNA LMNB1 and LMNB2

progeria = mutations in LMNA
exons are also spliced,

some aa are also lost, so protein is now shorter.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

processing normally vs w progeria

A

normal
there is lamin protein
a lipid molec is added to C terminal
= farnesylation
2. methylation
3. cut = protein loses the added lipid molecule

w progeria
about 50 aa are deleted including the signal on where to cut
so when the lipid is added
and methylation happens
the signal for the cut, to lose the lipid is missing
lipid stays in strucutre

problem = instead of indv proteins int w e/o, they stick to mb = become lipid linked proteins
- nuclear envelope loses shape/activity( like gene repair) = mutation accumulate
cell can’t function, tissues can’t fn, deathd

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

different type of mutations, what it is

A

silent mutations = a nucleotide was changes but bc of redundancy of genetic code, same aa was coded for, neutral

missesne = nucleotide was changed, new aa , diff structure, diff fn

nonsense = nucleotide was changeed = new codon in stop codon. stops translation

loss of stop = nucleotide was changes = stop codon became an aa

frameshift = 1 base added/removed = the reading frame changes, everything is ruined from that point on.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

consequences of each mutaton

A

silent = nothing

missense = if new aa is similar = not a problem
but for ex. if new aa can’t be phos, but old needed to be, = problem

nonsense= if early : big problem (short protein) non functional
if later = some fn could be perserved

loss of stop = addition of more aa than needed
if size is imp = big problem,
if not, = prolly not too bad

frameshift= if early; becomes completely diff protein = big problem
if end = might not be imp

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

loss/gain of function mutations

A

loss of function = codes for a nonfunctional protein

gain of function = codes for a protein w a new function

Loss = Need 2 copies of those mutation to completely lose the function inside the cells
Gain = Just 1 allele with that mutation is enough to get new function is enough

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

mutations occurring during DNA rep

A

bases could be misfired ,, but DNA poly has proof reading ability

if uncorrected could lead to permanent mutations in the next round of DNA rep.

in DNA rep each strand is a template.
one strand = all is good
other strand = put AG tog. = mismatch

if not watched, second round of DNA rep,
all good
one strand = AT
2 strand = CG

but now, instead of having GC in 2 daughter molecs like parents,
we have one right base pair and one wrong = mutation in 2nd

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

if DNA poly doesn’t catch mistake, all is lost?

A

no, there is a mismatch repair mechanism that also scans for errors
(look for mismatch = easy to find bc bases aren’t properly paired)

reco the mismatch and removes the wrong base, puts right one.

now, higher accuracy

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

mutations can occur spontaneously by ___ and ____, 2nd source mutations

why dangerous

A

depurination and deamination

depreciation = a nucleotide loses its base = becomes abasic (happens to G A)

deamination = C loses amino group, O takes place, becomes U

deprivation = problematic
of nucleotide has lost its base = dna rep happens, but when DNA poly sees no base, it doesn’t know what to do and moves on = frameshift error

deamination = problematic
C becomes U, C was binding G, U can’t bind G, if rep happens w/o repair, we get one pair GC, and other UA

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

modified base examples

A

oxidation, deprivation, deamination

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

BER- base excision repair mechanism

A

removes modified bases

steps
1. reco of modified bases
2. excision of the modified bases
3. removal of the same nucleotide
4. add missing nucleotide
5. ligase binds 2 adj nucleotides

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

UV induced mutations

A

UV damages DNA, covalently links 2 adjacent nucleotides with T bases

2 adj T nucletifes usually make H bonds not covalent bonds

usually linked by sugars not bases

problem = bc when DNA rep happens, DNA poly doesn’t know what to do with a T dimer, gets stuck/stops, DNA will break = damage to DNA

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

repairing a Thymine dimer

A

prepared by a nucleotide excision repair (NER) mechanism

reco of T dumers (proteins reco the covalent bond, bends the DNA sp cell knows which is the damaged cell
excision of damaged strand
DNA poly replaces gap
ligase binds together

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

radiation induced mutations

A

x rays cause single and double stranded breaks in DNA,
bc of their higher energy radiation,
instead of linking two T’s, they break strands of DNA

if left and not repaired quick, chromosomes rearrangement happens and may lose parts of chromosomes

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

chromosomal rearrangements

A

deletion of a chromosome segment

duplication 2 homologous chromosomes break at diff points, one chromosomes loses CD segments, other now has 2 CD segments, for ex.

inversion
2 cuts at either side of CDE, gets puts back but in EDC order

Reciprocal translocation
non homologous chromosomes change segments. now info of chromosome 5 is next to info of chromosome 2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

repair of double strand DNA breaks , 2 types

A

non homologous
sloppy repair after break
just take 2 ends of molecs nad link using ligase,
we could lose DNA, could link 2 diff segments that shouldn’t have been linked

homologous
more proper, we don’t lose anything
lets say, we have 1 chromosome w 2 strands broken, in this situation, the homologous chromosome is near.
used as a template

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

mutations induced by chemical reagents

A

alkylating agents
add methyl and ethyl groups to bases, bind 2 strands of DNA covalently together, binds 2 bases together, makes DNA poly make mistakes, breaks DNA/damages it

Proflavin inserts itself bn bases of one strand, makes DNA poly confused, doesn’t know how to rep this strand = frameshift mutation.