lecture 11 Flashcards

1
Q

what does a progress curve measure

A

measures the appearance of product ( or disappearance of substrate) with time

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2
Q

what is the shape of the graph when there is excess substrate and why

A

it is linear as the amount of E is increased, the rate of reaction increases

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3
Q

what is the shape of the graph where there is fixed enzyme and we increase S and why

A

a rectangular hyperbola, as we increase S the active sites become full the reaction rate tapers off

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4
Q

what is Vo

A

the initial rate of the enzymatic reaction

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5
Q

what does Vo depend on so what order is it

A

first order kinetics as it depends on [S]

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6
Q

what is Vmax when does it occur

A

the maximum reaction velocity of an enzyme, it occurs when the enzyme conc is saturated

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7
Q

what is Km, what does it measyre

A

the substrate conc at which V= Vmax / 2, its a measure as the affinity for the enzyme to a particular substrate.

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8
Q

Km can also be called what

A

the michaelis constant

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9
Q

whats the michaelis-mentin equation

A

V = (Vm x [S])/(Km + [S])

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10
Q

what does a low Km value mean

A

An enzyme with low Km reaches half max velocity at a low amount of substrate. Low Km means the enzyme is efficient at getting substrate and reacting.

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11
Q

what assumptions is the michaelis menten equation based on

A

1: a product is not converted back to substrate
2:Haeldanes steady state assumption, the rate of ES formation = the rate of ES breakdown
3:by measuring initial rate, we assume [S] does not change over time.

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12
Q

what is the lineweaver-burk plot and whys it used

A

its a plot of 1/V vs 1/S. it is used because the hyperbolic V vs S can be difficult to determine Vmax. but lineweaver burk gives a linear graph

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13
Q

whats the equation for Km

A

Km = ( (k-1) -1 )/ (k1)

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14
Q

why is Km important

A

it characterises the interactio between one enzyme substrate pair, if an enzyme can bind many substrate there will be different Km values.
Km is [S] needed to reach half Vmax

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15
Q

units for Km

A

they are concentration units

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16
Q

on a linweaver burk what is the Y intercept

A

1/Vmax

17
Q

on lineweaver burk what is x intercept

A

-1/Km

18
Q

whats the slope of the lineweaver burk plot

A

Km/Vmax

19
Q

in the cell, for a particular substrate, [S] is less than the conc needed to reach Km, what does this mean

A

half V max wont be achieved. this also allows effective rate control of reactions.

20
Q

what is kcat

A

the turnover number, the number of substrate molecules converted to product per unit of time when Enzyme is saturated with substrate

21
Q

what does kcat equal

A

kcat= (Vmax)/[E]

22
Q

what is kcat/Km

A

it is a measure of enzyme efficiency

23
Q

what does low Km means
what does high Kcat mean

A

high kcat so it can turn over lots of substrate per second, and a low Km so they have high affinity for each other.

24
Q

what limits the value of Kcat/Km

A

diffusion rates of substrate to the enzyme

25
Q

whats the upper limit of Kcat/Km

A

10^9 s-1 m-1.

26
Q
A