Lecture 10 Flashcards
Meiosis stages
- Chromosomes become shorter and thicker; chiasmata are prominent
- Homologous chromosomes repel; they are held together by chiasmata
- Bivalents align on the metaphase plate
- Homologous chromosomes separate
- Chromosomes align on the metaphase
What happens when bivalents lack the chiasmata
They are prone to nondysjunction where you don’t get proper segregation of the chromosomes into the gametes at the end, you don’t get recombination
Why is meitotic recombination of fundamemental importance
- It generates new combinations of genotypes which is essential for adaptation/ natural selection
- Determines to what extent loci residing in different genomic locations are associated with one another (linkage)
- Crossover is critical for correct segregation of chromosomes during meiosis but its also really important for mixing genetic material between the maternal and the paternal genomes so the gametes aren’t identical to the parental genome
What is linkage disequilibrium
The extent to which the allele frequencies at two loci are correlated.
What does recombination do to LD
It breaks down LD which makes selection more efficient because it allows new and more favourable mutations to be more integrated into the population together and it allows selection to eliminate deleterious combinations
What is background selection
Selection is going to act to purge those from the population. All the black lines (chromosomes are going to be lost from the population because they have a lower fitness leaving behind deleterious mutations.
Therefore in the next generation, this means that mutations can occur and become weakly linked with the deleterious mutation.
So therefore we get fixation of this bad mutation because you can’t have recombination to shuffle the mutations between the different chromosomes in order to create a mutation free chromosome .
Mullers Rachets
there’s no recombination so there’s no shuffling of mutations between different chromosomes - what happens is there’s this stochastic loss of mutation free chromosome (purely by chance) - your population then starts to accumulate these deleterious mutations
Genetic hitchhiking
deleterious mutations along with a beneficial mutation, there’s selection for the strongly beneficial mutation (positive fitness effect) however, its in LD with a deleterious mutation so as well as the beneficial mutation getting fixed, the deleterious one also does as well - can separate that linkage between the beneficial and the deleterious mutation.
Ruby in the Rubbish
Opposite of the last where you get beneficial mutations that have been lost from the population simply because they’re linked with a really deleterious mutation that’s going to be eliminated from the population (lose those deleterious mutations)
What’s the variation of recombination rates like across species
There’s huge recombination rate variations
This is strange because recombination is fundamental so why are some species doing it more and some doing it less? This may have implications for how efficient selection
Its important that we start to measure the intensity of recombination and its evolutionary significance due to the variation
Where are the variations in recombination
Across a species
Across males and females of a species (between individuals
Across the genome
Across the chromosomes
What is the genetic distance and how is it measured
The degree of genetic linkage between two loci is measured by the frequency of recombination between two loci
- c ranges between 0
(complete linkage) to 0.5 (independent
assortment or unlinked)
– The standard unit is cM (centi-Morgan)
– 1 cM = 1% probablilty of producing a recombinant
What do we need to consider
- The genetic distance between locus A and locus B is 17cM, and so is that between locus C and locus D. (you can work out genetic distance by dividing the genetic distance by the physical distance- related but there’s no direct correlation between the two )
- But the physical distance between the the first pair of loci is 10 Mb, and that between the second pair is 50 Mb
What is the recombination rate
- Standard unit: cM/Mb (or cM Mb-1)
- A measure of recombination
propensity per genomic length unit
Example calculation for genetic distance
- Between A and B: 17cM/10Mb = 1.7cM/Mb- recombination rate is higher which makes sense because they’re closer together (not a linear correlation)
- Between C and D: 17cM/50Mb =
0.34cM/Mb - The average rate is higher between A and B