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Biophysical & Physical > Lecture 1 > Flashcards

Lecture 1 Flashcards

1
Q

Celsius to Fahrenheit

A

F=1.8C+32

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2
Q

Celsius to Kelvin

A

K=C+273

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3
Q

2^-1

A

2^-1=1/(2^-1)=1/2

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4
Q

g/cm^3

A

g/cm^3=g • cm^-3

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5
Q

10^3 • 10^-4

A

When powers are multiplied, the exponents are added.

10^3 • 10^-4 = 10^-1

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6
Q

cm^3/cm

A

When powers are divided, the exponents are subtracted

cm^3/cm= cm^2

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7
Q

Express in scientific notation

11,000,000

A

1.1 x 10^7

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8
Q

Express in scientific notation

0.0000000045

A

4.5 x 10^-9

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9
Q

Express in a regular number

1.02 x 10^-3

A

0.00102

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10
Q

Express in a regular number

4.26 x 10^4

A

42600

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11
Q

Express in a regular number

6.02 x 10^23

A

602000000000000000000000

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12
Q

(4.8 x 10^-6)/(1.2 x 10^3)(2.0 x 10^-8)

A

2.0 x 10^ -1 or 0.2

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13
Q

Water boils

A

212F or 100C

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14
Q

Water freezes

A

32F or 0C

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15
Q

Charles Law

A

V/T=k

Volume or gas is directly proportional to the temperature (when pressure is constant

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16
Q

Boyles law

A

Volume and pressure are inversely proportional when temperature is constant
PV=k

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17
Q

Physical properties

A

A physical property can be observed or measured without changing the chemical make up of a substance

A physical change occurs without producing a new chemical substance

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18
Q

Precision

A

The consistency and reproducibility of a test (reliability)

Increased precision = decreased standard deviation

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19
Q

Accuracy

A

The trueness of test measurements (validity)

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20
Q

Improving accuracy

A

Improved by making replicate measurements and taking the average

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21
Q

Percent error

A

Accuracy is assessed by calculating the percent error

%error=( (measured value-“true” value)/(“true” value) )x 100%

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22
Q

Improving precision?

A

Improved by careful lab technique and or using instruments with more significant figures. More significant figures imply greater precision

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23
Q

Standard deviation

A

Precision is quantified by standard deviation

Standard deviation= £(measurements-average of measurement)^2/(number of measurements - 1)

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24
Q

Length

A

Meter (m)

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25
Q

Mass

A

Gram (g)

26
Q

Temperature

A

Kelvin (K)

27
Q

Amount of material

A

Mole (mol)

28
Q

Volume

A

Liter (L)

29
Q

Liter

A

1000cc

30
Q

Tetra

A

T

10^12

31
Q

Giga

A

G

10^9

32
Q

Mega

A

M

10^6

33
Q

Kilo

A

k

10^3

34
Q

Hecto

A

h

10^2

35
Q

Deca

A

da

10^1

36
Q

Deci

A

d

10^-1

37
Q

Centi

A

c

10^-2

38
Q

Milli

A

m

10^-3

39
Q

Micro

A

u with a tail

10^-6

40
Q

Nano

A

n with long tail

10^-9

41
Q

Pico

A

p

10^-12

42
Q

Coldest possible temperature

A

Absolute zero
Kelvin scale begins at absolute zero
0K=absolute zero=-273.15C
Kelvin is the same degree as 1 degree C

43
Q

1 inch

A

2.54 cm

44
Q

1 cm

A

0.4 inches

45
Q

1 kg

A

2.2046 lbs

46
Q

1 lb

A

0.454 kg

47
Q

1 mile to km

A

1.609 km

48
Q

1 mile to ft

A

5280 ft

49
Q

1 pound to ounces

A

16 ounces

50
Q

1 ounce to grams

A

28.35 g

51
Q

1 grain to mg

A

64.80 mg

52
Q

1 L to dm^3 (decimeter)

A

1 dm^3

53
Q

1 gal into liters

A

3.79 L

54
Q

1 ml to cm^3

A

1 cm^3

55
Q

1 cc to cm^3

A

1 cm^3

56
Q

Density

A

D=m/v
Most common is g/mL
Density of water is 1.0g/mL
Density of mercury is 13.6g/mL

57
Q

Bone density test to diagnose?

A

Osteoporosis

58
Q

Specific gravity

A

Specific gravity = density of object/density of water

Ratio of objects density to density of water

59
Q

Specific gravity of urine

A

1.005 to 1.030

60
Q

Low specific gravity

A

Hyposthenuria: indicates dilute urine, which may be caused by

  • diabetes insipidus (can be as low as 1.001)
  • drinking excessive amounts of liquid
  • pyelonephritis, glomerulonrphritis
  • diuretics
61
Q

High specific gravity

A

Hypersthenuria: indicates very concentrated urine, which may be caused by

  1. Dehydration
  2. Diabetes Mellitus
  3. Adrenal Insufficiency
  4. Toximea if pregnancy (protein in the urine)

Biophysical & Physical (2 decks)

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