Lattice Energy Flashcards

1
Q

enthalpy of atomisation

A

the enthalpy change when one mole of atoms is formed from its elements in their standard states under sc

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2
Q

lattice energy

A

the energy change when 1 mole ionic compound is formed from its gaseous ions under sc

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3
Q

1st electron affinity

A

the enthalpy change when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous ions with a 1 negative charge

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4
Q

what are the factors that affect electron affinity

A
  • greater nuclear charge, higher the EA
    • stronger attraction (affinity = attraction)
    • more energy released
  • the smaller the atomic radius, higher the EA
  • stronger attractive force between nucleus
  • the smaller electron shells, higher EA
  • less shielding from nucleus and outer shell electrons
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5
Q

describe and explain the electron affinities of G 6 and 7

A
  • less exothermic, lower EA, down the group
  • F does not fit, such a small atomic radius
  • very high electron density causes repulsion between electrons within atom
  • hard for nucleus to attract other electrons
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6
Q

explain ionic charge and ionic radius of lattice energy

A

As ionic radius decreases, lattice energy (add electron) increases
=higher charge density means there is a stronger electrostatic attraction forces

As ionic charge increases, lattice energy increases
=higher charge density (with other same size) so stronger attraction

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7
Q

enthalpy hydration

A

enthalpy change when 1 mole of an gaseous ion are dissolved in sufficient water to form a dilute solution under sc / exo

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8
Q

enthalpy solution

A

energy absorbed or released when 1 mole of an ionic solid dissolves in sufficient water to form a very dilute solution under sc / exo or endo

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9
Q

explain ionic charge and ionic radius of enthalpy hydration

A

IONIC CHARGE = high charge density
-stronger ion-dipole attractions between water and ion

IONIC RADII = high charge density
-stronger ion-dipole attractions between water and ion

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10
Q

thermal stability (ionic radius and polarisation)

A

more stable down the group (harder to decompose)

  • ionic radius increase down the group so can polarise better
  • can weaken C-O and form CO2, decompose better
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11
Q

solubility and enthalpy solution (enthalpy and lattice energy)

A

-when ΔHsol have large positive values = insoluble
-since the lattice energy and ΔHhyd get less exo down a group
= Hess’s law shows ΔHsol is less exo
= more endo
= large positive values

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