Lattice Energy Flashcards
enthalpy of atomisation
the enthalpy change when one mole of atoms is formed from its elements in their standard states under sc
lattice energy
the energy change when 1 mole ionic compound is formed from its gaseous ions under sc
1st electron affinity
the enthalpy change when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous ions with a 1 negative charge
what are the factors that affect electron affinity
- greater nuclear charge, higher the EA
- stronger attraction (affinity = attraction)
- more energy released
- the smaller the atomic radius, higher the EA
- stronger attractive force between nucleus
- the smaller electron shells, higher EA
- less shielding from nucleus and outer shell electrons
describe and explain the electron affinities of G 6 and 7
- less exothermic, lower EA, down the group
- F does not fit, such a small atomic radius
- very high electron density causes repulsion between electrons within atom
- hard for nucleus to attract other electrons
explain ionic charge and ionic radius of lattice energy
As ionic radius decreases, lattice energy (add electron) increases
=higher charge density means there is a stronger electrostatic attraction forces
As ionic charge increases, lattice energy increases
=higher charge density (with other same size) so stronger attraction
enthalpy hydration
enthalpy change when 1 mole of an gaseous ion are dissolved in sufficient water to form a dilute solution under sc / exo
enthalpy solution
energy absorbed or released when 1 mole of an ionic solid dissolves in sufficient water to form a very dilute solution under sc / exo or endo
explain ionic charge and ionic radius of enthalpy hydration
IONIC CHARGE = high charge density
-stronger ion-dipole attractions between water and ion
IONIC RADII = high charge density
-stronger ion-dipole attractions between water and ion
thermal stability (ionic radius and polarisation)
more stable down the group (harder to decompose)
- ionic radius increase down the group so can polarise better
- can weaken C-O and form CO2, decompose better
solubility and enthalpy solution (enthalpy and lattice energy)
-when ΔHsol have large positive values = insoluble
-since the lattice energy and ΔHhyd get less exo down a group
= Hess’s law shows ΔHsol is less exo
= more endo
= large positive values