Electrochemistry Flashcards
predict products
- cation that is most easily reduced is discharged (high E⦵)
- anode that is most easily oxidised
- when molten = no H or OH
- when concentrated, no OH- for anion
SEP
the voltage produced when s standard half cell is connected to a standard hydrogen electrode under sc
SCP
the difference in standard SEP between two half cells
SHE
hydrogen gas at 101kPa with H+ ions of concentration 1.00moldm-3
Pt electrode covered Pt black in contact with hydrogen gas and H+ ions
calcualte SCP
difference between two
direction of electron flow
from negative to positive
e.g Fe = +0.77
Cu = +0.34
from Cu to Fe
feasibility
add the two values
Nernst equation
E = E⦵ + 0.059/z log([oxidised]/[reduced])
for metal ions:
E = E⦵ + 0.059/z log([oxidised])
When one half cell is diluted with water, what happenes to the voltage
more positive
-half cell less positive so the difference between voltages increase and E increases!
conc of copper ions increase, what happens to half cell
E value increase!
conc of copper ions increase, what happens to complete cell
decrease as copper is worse at gaining so going other direction
conc of copper ions increase, why does the direction not change because of the concentration increase?
When NOT under sc, if difference is greater than 0.30 V, remains unaltered.