Lab 1 Anaemia Flashcards

1
Q

Haemoglobin estimation test

A

Drabkins method
Drabkins fluid contains potassium cyanide + potassium ferrocyanide
Haemoglobin contains ferrous ions (Fe2+) which is converted to cyanmethaemoglobin by Drabkins solution.
This is a stable red complex which can be measured spectrometry at 540nm.

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2
Q

What does drabkins method measure and how?

A

Haemoglobin concentration.
Measures amount of cyanmethaemoglobin (stable red complex) produced after mixing drabkins solution with haemoglobin and measuring at 540nm.

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3
Q

What is the reaction in drabkins methods

A

Drabkins solution contains potassium cyanide and potassium ferrocyanide which reacts with ferrous ions in haemoglobin to produce cyanmethaemoglobin (stable red complex) - measured with spectrometer at 540nm.

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4
Q

What is the procedure for measuring Hb concentration?

A

Drabkins method.
*Standard curve has to be created using Hb standard with known concentration. Make up to 2000uL (2ml)
(e.g. Hb standard = 100g/L -> Hb conc =0g/L = 0uL + 2000uL (drabkins sol.), Hb conc = 20g/L (1/5)= 400 Hb + 1600uL Drabkins solution, Hb conc = 80g/L (4/5) = 1600ul Hb + 400uL Drabkins sol.).
*Make up patient samples in microcuvettes (in duplicate).
*Incubate at room temp for 5 mins.
* Read absorbance at 540nm.
* Draw standard curve (Hb conc = x, abs = y)
* Use average of patient values to find conc on curve.

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5
Q

What is requirements for blood sample for Haemoglobin estimation using drabkins method

A

EDTA-anticoagulated blood <24hrs old.
Also need Hb reference standard to make standard curve.

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6
Q

How is haematocrit measured?

A

3/4 fill capillary tube with blood sample (EDTA-anticoagulated)
Seal end of tube and place in centrifuge with sealed end facing away from centre.
Centrifuge for 5 mins at 12000g.
Read Hct % with reader provides.

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7
Q

What can a MCHC over 370g/L indicate?

A

Blood sample may contain cold agglutinins which causes RBCs to clump together. Analyzer incorrectly reports low number of very dense RBCs but high Hb.
Corrective methods:
1. Remix EDTA tube
2. Warm blood to 37C
3. Check for autoantibodies (DAT)
4. Check slide for spherocytosis

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8
Q

How to differentiate between anaemia of chronic disease and IDA

A

ACD = Low serum iron, low TIBC, high ferritin, typically normocytic (but can be microcytic)
IDA = low serum iron, HIGH TIBC, LOW ferritin.

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9
Q

Microcytic hypochromic anaemia

A

IDA
Thalassaemia
Anaemia of chronic disease
Sideroblastic anaemia

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10
Q

FBC sample acceptance criteria

A

EDTA anticoagulated blood
<24hrs

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11
Q

Blood film sample acceptance

A

EDTA anticoagulated blood
<8hrs old.

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12
Q

What is reticulocyte count an indicator of?

A

Erythropoietic activity in bone marrow

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13
Q

%retic count vs ABC in anemaia patients

A

%retic count can be misleading due to RBCs being depleted in some anaemia leading to a falsely elevated %retic.

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14
Q

what does retic count help to differentiate between?

A

Differentiate between anaemia caused by
*low RBC production (low retic count due to BM problem)
e.g. IDA, ACD, B12 deficiency
and
*Increased RBC destruction (high retic count - bone marrow responding well)
e.g. haemolysis, acute blood loss, thalassaemia)

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15
Q

How many cells to count for % retic

A

At least 112
112 x 9 = 1000 RBCs in total
Usually 4/5 field of view

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16
Q

%Retic formula

A

reticulocytes (big square)

————————————— x 100 = __%
#RBCs (small square) x 9
(at least 112)

17
Q

RBCs are ___cytic in IDA because

A

Microcytic bc Iron availability is decreased => haemoglobin production decreased -> new RBCs contain less Hb = smaller and paler.

18
Q

Thalassaemia RBCs are ____cytic because

A

Microcytic = genetic defect in globin chain production leading to imbalanced Hb synthesis = RBCs contain less Hb.

19
Q

RBCs are ___cytic in anaemia of chronic disease because

A

First normocytic and can develop to microcytic = 1. Increased hepcidin production (due to inflammatory cytokines IL-6 produced in liver) leading to iron sequestration. Hepcidin blocks ferroportin preventing iron release -> less iron reaches developing RBCs in BM leading to defective Hb synthesis.
2. Decreased erythropoiesis = inflammation suppresses EPO production reducing RBCs -> to maintain Hb concentration, developing RBCs undergo extra divisions, resulting in smaller cells.

20
Q

Microcytic anaemia (4)

A
  1. IDA
  2. ACD
  3. Thalassaemias
  4. Sideroblastic anaemia
21
Q

Normocytic anaemia (5)

A
  1. Acute blood loss
  2. Early IDA
  3. Early ACD
  4. Increased destruction of RBCs
  5. Bone marrow disorder
22
Q

Macrocytic anaemia (4)

A
  1. Liver disease/alcohol injury
  2. Metabolic disorder (VitB12/folate deficiency)
  3. Bone Marrow disorder
  4. Megaloblastic anaemia
23
Q

IDA red cell distribution width

A

HIGH
anisocytosis + poikilocytosis (elliptocytes, targetcells, dacrocytes)

24
Q

Thalassaemia + Anaemia of CD RDW

A

Normal
No variation in size and shape

25
Q

% reticulocyte count in anaemia patients

A

Misleading because it can be falsely elevated due to patients RBCs being depleted.
%retic is #retic as percentage of # RBCs.

26
Q

Why is retic count HIGH in thalassaemia?

A

*In thalassaemia, there is genetic defect in globin chain synthesis leading to ineffective erythropoiesis
*However bone marrow is hyperactive and tries to compensate for defective RBCs by producing more reticulocytes

27
Q

WHy is retic count LOW in IDA?

A
  • in IDA there is not enough iron available for Hb synthesis so RBC production is limited.
    *Cannot increase retic production due to lack of iron.
28
Q

Why is retic count LOW in ACD?

A
  • In ACD, inflammatory cytokines (IL-6) increase hepcidin which traps iron in macrophages + enterocytes, blocking its release leading to reduced RBC production.
  • Inflammation also suppresses erythropoitin (EPO) reducing BM activity.
29
Q

Absolute reticulocyte count formula

A

%reticulocyte/100 x RBCs
= ___ x10^9/L.