L13- Crystallisation Flashcards

1
Q

Crystallisation

A

Taking supersaturated material and forming solids/crystals

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2
Q

Saturated solution

A

Solution in thermodynamic equilibrium with solid phase at given temp

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3
Q

Supersaturated

A

Solution containing more dissolved solute than at equilibrium

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4
Q

Degree of supersaturation, Delta c

A

Delta c = c-c*

c = actual supersaturated concentration
c* = equilibrium concentration

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5
Q

Supersaturation ratio, S

A

S = c/c*

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6
Q

Relative supersaturation, phi

A

phi = delta c/c* = S-1

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7
Q

Crystallisation driving force

A

Supersaturation is the driving force for crystallisation;
fundamentally is the difference in chemical potential

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8
Q

Solubility-supersolubility diagram: width of metastable zone

A

delta c = (dc/dT)delta T

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9
Q

Solubility-supersolubility diagram: zones & factors affecting

A

Stable: no crystals readily form

Metastable: crystals do not form spontaneously but existing crystals would grown

Labile: crystals form since conc. above max show in supersolubility line

Depends on agitation, impurities and how got supersaturated

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10
Q

Solubility-supersolubility diagram: Moving from stable to labile (crystal growth)

A

Constant temp: saturate at metastable boundary, crystals form spontaneously at labile boundary

Cooling: saturate at metastable boundary, crystals form spontaneously at labile boundary

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11
Q

Nucleation

A

Creation of crystals within supersaturated liquor

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12
Q

Nucleation types

A

Primary: nucleation in absence of existing crystals
Homogeneous if only solute involved; heterogeneous when other substances involved or present

Secondary: nucleation in presence of existing crystals- nucleates more readily, i.e. lower supersaturation

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13
Q

Crystal growth kinetic stages

A

Diffusional stage: solute transported from bulk through solution boundary layer adjacent to crystal surface

Deposition stage: adsorbed solute deposited and integrated into crystal lattice

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14
Q

Overall mass deposition rate, RG

A

RG = KG(delta c^s) = [(6ap)/B](dr/dt) = [(6ap*u’)/B]

where particle mass, m = ap(d^3)
surface area, A = B*(d^2)
KG - overall crystal growth coefficient
s = constant between 1-2
u’ = mean linear velocity (dr/dt, m/s)

For spheres 6a/B = 1; octahedra 6a/B = 0.816

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15
Q

Crystal yield basis

A

estimated from conc. of initial solution and solubility at final temp, allowing for evaporation

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16
Q

Solvent (Water) balance

A

For solvent (usually water), the initial solvent present is equal to the sum of the final water in mother liquor + water of crystallisation within crystals and water evaporated

w1 = w2 + y[(R-1)/R] + w1E

w1, w2 = initial and final masses of solvent in liquor
y = yield of crystals
R = molecular mass of hydrate/anhydrous salt
E = mass of solvent evaporated/solvent in initial solution

17
Q

Solute balance

A

w1c1 = w2c2 + y/R

w1, w2 = initial and final masses of solvent in liquor
y = yield of crystals
R = molecular mass of hydrate/anhydrous salt

18
Q

Proof for crystal yield

A

Sub solvent balance (w2 =…) in solute balance:
w1c1 = c2{w1(1-E) - y[(R-1)/R]} + y/R

y = Rw1{[c1-c2(1-E)]/[1-c2(R-1)]}

19
Q

Crystallisation processes & equipment

A

Reaction -> Evaporator -> Crystalliser -> Filter/centrifuge -> dryer

Cooling crystalliser: allow vessel to cool over time, surfaces provided for crystal growth
Economic for small batches, but uncontrolled crystal sizes,i.e. agitated/agitated w/ circulation through external HEx

Evaporating crystalliser: used when temp not decreased enough
Increases supersaturation, i.e. steam heated