L11 - DNA replication 3 Flashcards

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1
Q

diferences in replication orogins between eukaryotes and prokaryotes

A

eukaryotes have multiple wheras prokaryotes have 1

orgogins = where unwinding occurs for DNA replication to take place

= replisome forms here

only a few orogins of replication in eukayotes will be fired

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2
Q

what can happen if timing of DNA replication is off/wrong

A

double strand breaks

= poor timing can leave unreplicated regions of DNA

motors that pull apart chromosones at kinetichores are very powerful

when chromosomes try to seprate in DNA replication

= unreplicated regions cannot seperate = ds BREAK

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3
Q

what controls the timng of firing at replication of orgins for DNA replication

A

CDKs

= cyclin dependnat kinases

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4
Q

describe the mechnaisms for the initiation of replication in G1 phase

A
  1. ORC binds to replicator sequnce in orogin with cdc26

= Orogin repcognition complex

  1. recruits Mcm helicase with cdt1
  2. same thing happens with a 2nd helicase binding
  3. everything but helicase discoaites leaving just the 2x helicases

= G1 phase

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5
Q

descibe the mechansims of initiation in S phase -

A

CDKs increase in conc as it enters S phase

= DDK + S-CDK

  1. DDK phosphprylate helicases = comformational change
  2. sld3 + cdc45 recruited
  3. S-CDK phosphorylates changing comformation AGAIN

= more proteins recruited

  1. comformational change to helicase causes them to open allowing ssDNA to bind

= polymerase binds

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6
Q

describe how the comformation of helicaes + CDKs affects the timing of replication initiation

A

Helicases can be loaded in G1 phase

BUT no helicase activation as CDK levels are low

G2,S and M phases = CDK leveles are high BUT new helicase laoding is inhibited

= prevents refiring of sites of orogin

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7
Q

names for G1 and S,G2 , M phases in replicaction initiation

A

G1 = loading phase

S,G2 and M = activation phase

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8
Q

what is the problem with finisng replication on lagging strand

A

RNA primers are removed to be filled with DNA

the final RNA primer is removed and there is nothing to add on to the 5’ end of the last nucleotide in strand

= the end of the chromosones are lost on 1 strand
= following replication again the ends of both strands will not have the ends

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9
Q

role of telomeres

A

repeated sequnces of DNA to end of chromosomes

  1. telomerase extends 3’ end of telomere
  2. strand is longer so ocazaki fragments go for longer

= still lose the end of chromosome due to RNA primer being removed and nothing to add to it

= lose a non-coding seuqnce instead of a coding sequnce

deosnt solve the problem just delays it

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10
Q

how does telomerase work/extend the 3’ strand

A

contains stuctured RNA wutha template

binds to complimnetary DNA via base pairng at end of chromosome

the RNA template in telomerase is longer than the complimnetary strand

= polymerase adds nucleotides to the 3’ end
= complimentary to the RNA sequence in telomerase

telomerase has to move along the DNA to continue to act as template

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11
Q

what can double stranded breaks cause

A

cell cycle arrest

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12
Q

what protein coats and protects telomeres sequnces from repair machinerya

A

shelterin proteins

= binds to the ssDNA 3’ strand that was extended by telomerase
= hides from cell repair

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13
Q

what happenes if telomeres get too short

A

cell can no longer divide

= would start to remove coding regions
= known as ‘Hayflick limit’

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14
Q

what controls the loadiung of the 2 DNA helicases at the orgin

A

‘ATPase switches’

= ORC for example

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