L10 - DNA replication 2 Flashcards

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1
Q

how many origins of replication does E Coli have and why

A

1

circular genome = 2 replication forks

1 clockwise + 1 anticlockwise

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2
Q

describe e.colis replisome - complex of proteins fro DNA synthesis

A

sliding clamp ascociated with 2x DNA polymerases held on template strands

= 1 works clockwise the other anticlockwise round circular genome
= 2x repliaction forks

helicase unwinds strand with help of DNA gyrase - supecoiling modifier

primase produces short RNA primers for lagging strand

single stranded binding proteins (SSBs) bind to open ssDNA to protect them

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3
Q

what is DNA polymerase 3 holoenzyme and the componenets

A

main enzyme complex for DNA replication in prokaryotes

  • 2-3x core DNA polymerases
  • sliding clamp (b subunit)
  • clamp loader (y complex)
  • flexible linkers (t proteins)
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4
Q

describe the componets of the holoenzyme in prokaryotes -polymerases,clamp,clamp loader and flexible linkers

A

DNA pol 3:
hand shaped enzyme with 3 subunits - alpha,epsilon and O

clamp loader - y:
uses ATP as energy to open beta clamp onto DNA at primer-template junction

sliding clamp - b:
donut shaped protein that cicles DNA tethering polymerase

flexible linkers - t:
link each core polymerase to clamp loader , very flexible

= allow binding of polymerases

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5
Q

describe DNA polymerase 3 core subunits

A

alpha:
catalytic subunit for polymerase activity

epsilon:
proofreading mechanisms with 3’-5’ exonuclease activity

O:
stimulates epsilon subunit

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6
Q

describe the sliding clamp

A

ring/donut shaped protein that surround dsDNA

pore in the middle with a layer of water mooecules inside

= easy slding of DNA

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7
Q

descibe mechansism of clamp loader to load clamp onto DNA

A

claw like pentamer protein

  1. ATP binds opening claw with high affinity to beta-clamp
  2. protein interactions with loader opens sliding clamp = No ATP required
  3. complex has high affinity for junction/meeting point of single + dsDNA = replication fork
  4. ATP hydrolysis on clampmloader releases slidng clamp + loader discociates
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8
Q

describe the trombone model of DNA replication in E.coli

A
  1. dsDNA is unwound by helicase
  2. leading strand has 3’ open ready to be added to
  3. lagging strand (bottom of trombone) is added to by RNA primers coming out of the helicase
  4. loading clamp loads sliding clamp + polymerase onto RNA primer (clamp binds with high affinity to ds-ss junctiuon)
  5. pol works BACKWARDS extending the ‘trombone’ with ocazaki fragments on RNA primer

= extending area of dsDNA being newly syntheised and the ssDNA just been unwound between pol 3 + helicase

  1. once fragment completed polymerase discociates from clamp
  2. new clamp at clamp-loader is loaded onto the next RNA primer = trombone retracts
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9
Q

what if DNA polymerase maes an undeited mistake

A

incorrect base pairng in one of the 2 dsDNA helices produced

2nd round of replication adds base pairng to the wrongly added base

= forms a natural base pair
= apart of the genome now and impossible to know what was a mutation and what wasn’t

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10
Q

name the complex in E.coli that recognises mismtached bases - mismatch repair

A

MutS

= homodimer with DNA binding domain at bottom
= scans for distortions

doesnt directly read bases detctes structural changes

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11
Q

mechanism of mismatch repair in E.coli - MutS

A
  1. MutS detcts mismcth by distortions in dsDNA
  2. binds via DNA binding domain
  3. recruits MutL + MutH
  4. nick created in newly synthesised daughter strand
  5. endonuclease cuts strand TOWARDS MutS + fragment removed
  6. 3’ is left to be acted on by polymerase + correct bases added
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12
Q

how does mismatch repair mechansism/proteins know whether to cut in the template strand or the newly synthesied strand that contains the mismatched base

A

methylation patterns

= all adenines in DNA are methyltated

newly synthesied stsrands have short period whete A is unemthylated

MutH recgonsies lack of methyl on A

= cuts nick in strand

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