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kimia > Konsentrasi > Flashcards

Konsentrasi Flashcards

1
Q

konsentrasi

A

banyaknya zat terlarut dalam satu larutan

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2
Q

Molaritas

A

banyaknya mol tiap 1 larutan

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3
Q

jumlah mol zat terlarut dalam 1 kg

A

molalitas

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4
Q

fraksi mol

A

jumlah mol suatu zat (pelarut atau terlarut) dalam jumlah ml total larutan

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5
Q

%massa

A

berapa persen masssa zat larutan terlarut dari larutan total

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6
Q

berapa persen volume zat terlarut dari volume total

A

%volume

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7
Q

Molaritas (dalam liter)

A

M=mol/volume (l)

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8
Q

Molaritas (mililiter)

A

M= mol.1000/volume (ml)

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9
Q

Molalitas (kg)

A

m= mol terlarut/massa pelarut (kg)

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10
Q

Molalitas [gram]

A

m= mol terlarut . 1000/ massa pelarut (gram)

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11
Q

mol

A

gram/Mr

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12
Q

Xt [fraksi mol terlarut]

A

nt/nt+np

n=mol

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13
Q

Xp [ fraksi mol pelarut]

A

np/nt+np

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14
Q

Xp+Xt

A

nt/nt+np + np/nt+np
= nt+np/nt+np
=1

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15
Q

pengenceran larutan satu dan larutan dua

A

mol L1 = mol L2

V1.M1=V2.M2

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16
Q

pencampuran larutan 1 dengan larutan dua

A

mol L1+ mol L2 = mol L3
V1.M1+V2.M2=V3.M3
V1+V2=V3

17
Q

kemolalan suatu larutan 20% massa c2h3oh? (dimisalkan massa larutan)

A

dimisalkan massa larutan 100g
m= nt. 1000/massa pelarut
nt= gr/Mr

18
Q

100 gram larutan NaOH (mr=40) mempunyai konsentrasi 5 molal. massa NaOH…

A

dimisalkan massa larutan, dan massa terlarut disimbolkan x
m= nt.1000/mp
nt= gr/mr

19
Q

Molaritas NaOH dalam air jika fraksi mol NaOH= 1/21 dan massa jenisnya 1 gr/mL

A

Xt= nt/nt+np
nt/p= gr/mr
jumlahn massa larutan

massa jenis= massa/volume
volume= m larutan/ massa jenis
M= nt.1000/v

20
Q

larutan urea (mr=60) dengan massa terlarut 36% dan massa jenis larutan 1g/mL. ubah ke
m?
Xt?
M?

A

misalkan massa larutan sebagai 100g
massa larutan = massa terlarut + massa pelarut

molalitas= nt. 1000 / mp

xr= nt/nt+np

V= m/massa jenis

M= nt.1000/V

kimia (2 decks)

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