Kinetics and Equilibria Flashcards

1
Q

Describe what is meant by collision theory

A

For a collision to be successful, particles have to collide with sufficient energy and the correct orientation

The rate of a chemical reaction can be explained by using collision theory

Collision theory has three main parts

In order for particles to react, they must collide (if particles do not collide, then they cannot react

Secondly, when particles react, chemical bonds must be broken
(breaking chemical bonds requires energy- called Ea)
collide with enough energy to start breaking the chemical bonds in the reactants

In order for a reaction to take place, particles must collide in the correct orientation

e.g. green atoms must collide for a reaction to happen
if particles are in the incorrect orientation - the collision would be ineffective and a reaction will not take place

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2
Q

What is the rate of reaction proportional to

A

The rate of a reaction is proportional to the number of effective collisions per second/frequency of effective collisions

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3
Q

Use collision theory to explain the effect of reactant concentration and gas pressure on the rate of a reaction

A

One way to increase the rate of a reaction is to increase the conc. of the reactants

At a higher concentration, there are more reactant particles in the same volume

Because the reactant particles are closer together, there is an increased chance of collisions taking place

There will be an increased frequency of collision

Some of these collisions will be effective, leading to a reaction

This means that the rate of reaction will increase

We can also increase the rate of reaction by increasing the gas pressure
Increasing the pressure, makes the particles closer together
This increases the frequency of collisions leading to an increased rate of reaction

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4
Q

What is the activation energy

A

activation energy - the minimum amount of energy that particles must have for a collision to result in a reaction

the minimum energy particles must have in order to start a reaction by breaking chemical bonds

Ea - the enthalpy difference between the reactants and the highest point on the curve

Reactions can only occur when collisions take place
between particles having sufficient energy.

This energy is called the activation energy.

activation energy - the minimum amount of energy that particles must have for a collision to result in a reaction

in order for a reaction to happen, particles must collide with enough energy to start breaking the chemical bonds
if collision does not have enough energy - then particles cannot react = simply bounce of each other

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5
Q
A

when we measure the rate of a cheimcal reaction - we can either measure how quickly the amount of a reactant decreases or how quickly the amount of product is formed

this depends on which is easier to measure
accurately

e.g. if in a reaction you are making CO2 - measuring the volume of a gas is straight forward

One way is to catch the gas in an upturned measuring cylinder filled with water

A more accurate method is to use a gas syringe

in either case - we can read the volume of gas at regular time intervals from the scale and plot the volume of gas against time

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6
Q

explain the shape of the rate graph - products formed / time

A

Initially we get a lot of product formed rapidly
This tells us that the rate of reaction is fast
This is because we have a high conc. of reactants and a high frequency of effective collisions

Over time, the reaction slows down
This is because HCL is reacting - so the conc. of HCL is decreasing

Since HCL is the limiting reactant
Limiting reactant is running out

Because of this, the frequency of effective collisions is reduced

Eventually, the reaction stops and no more product is formed

This is because all of the HCL has reacted and there are no more effective collisions

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7
Q

Describe how to measure reaction rate from the gradient of a graph

measure the rate of reaction at any point by drawing a tangent

A

to measure the initialrate - draw a tangent from the zero time point

measure the gradient of tangent

construct a right angled triangle using the tangent

measure the y component (vol of co2) and x component (time)

to calculate the rate divide the volume of gas by time taken

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8
Q

rate of reaction - use a balance to measure mass of co2 released

A

start with 0
to negative

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9
Q

Describe why reactions with low activation energies will have a higher rate than reactions with high Ea

A

Reaction has a low Ea
So this reaction could take place quite rapidly at room temp.

This is because, at room temp. , a relatively large proportion of reactant molecules will collide with enough energy to cross the Ea barrier and react

Reactions with high Ea
At room temperature, this reaction should be relatively slow as only a small proportion of reactant molecules will collide with enough energy to cross the Ea barrier

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10
Q

Define catalyst

A

A catalyst is a substance that increases the rate of a
chemical reaction without being changed in chemical
composition or amount.
Catalysts work by providing an alternative reaction route
of lower activation energy.

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11
Q

Describe and explain the effect of catalysts on the rate of a reaction

A

One way to increase the rate of chemical reactions is to use a catalyst

Catalysts allow a reaction to take place via an alternative pathway with a lower Ea than the uncatalyzed reaction

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12
Q

Describe the economic and environmental benefits of using catalysts

A

Catalysts are not used up in a reaction and are not permanently changed

So that means that catalysts can be reused

By using catalysts, we can make reactions take place rapidly even at relatively low temperatures

This reduces the amount of energy needed by the chemical industry which in turn reduces the need to burn fossil fuels to provide this energy

This saves money, providing an economic benefit

It also reduces CO2 emissions, making the chemical industry more sustainable

However some catalysts are toxic, so this negative aspect needs to be weighed against the benefits

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13
Q

Describe the Maxwell-Boltzmann curve of particle energies

Maxwell–Boltzmann distribution of molecular energies in
gases.

A

Shows the distribution of energies amongst molecules in a reaction

If we measure the energy of all the molecules in a gas, a liquid or a solution, we get a curve

This curve is called the Maxwell-Boltzmann distribution

The curve starts at the origin (0 - 0)
This means that there are no molecules with zero energy

Secondly, some molecules have a very high energy
The curve does not touch the x axis at high energies
This tells us that there is no maximum energy that molecules could have

Lastly, the area under the curve tells us the total number of molecules in the system (reactants)

The most probable energy is directly under the peak of the curve (mode)

The mean energy is slightly to the right of this
That is because particles at very high energies skew the mean to the right

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14
Q

Use the Maxwell-Boltzmann curve to explain the effect of catalysts on the rate of chemical reactions

A

In order to collide effectively and react, molecules must have at least this energy
These molecules are represented by the area under the curve to the right of the Ea (after Ea)

The activation energy in the presence of a catalyst - will be more left
All of the molecules which now have at least this energy can collide
effectively and react
these molecules - area under the curve
This is a much greater number of molecules than for the uncatalyzed reaction

This explains why the rate of reaction increases in the presence of a catalyst

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15
Q

Use the Maxwell-Boltzmann curve to explain the effect of temperature on the rate of chemical reactions

A

Another way to increase the rate of reaction is to increase the temperature.

The effect of increasing the temperature on the Maxwell-Boltzmann distribution curve

At higher temperatures, there are more particles with very high energies

That the most probable energy increases, but the number of particles with the most probable energy falls

The area under the curve represents the total number of molecules
The number of molecules has not changed

Temperature has only increased
So the area under the curve cannot change when we increase the temp.

Therefore at higher temperatures, the curve shifts to the right, but the height of the peak falls

There are two effects to increasing the temperature

Firstly, the molecules are moving faster so the frequency of all collisions increases

Secondly at higher temperatures, we can see that the number of molecules with at least the activation energy has increased substantially

Now, a much greater proportion of the collisions are effective and result in a reaction

This increase in effective collisions explains why the rate of reaction increases at higher temperatures

a small rise in temp gives a large increase in rate

The curve broadens and flattens due to a greater spread of values
the area under the two curves is the same (same no. of molecules)

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16
Q

Define rate of reaction

A

The rate of reaction is typically measured as the change in concentration of the reactants of products per unit time

17
Q

Explain the effect of increasing temp on rate

A

Increasing temp

increases the Ek of particles

leading to a greater frequency of successful collisions

18
Q

explain the effect of increasing pressure/conc. on rate

A

Increasing pressure/conc. results in more particles per unit volume

leading to a greater frequency of successful collisions

19
Q

effect of increasing SA on rate

A

Increasing surface area exposes more particles

leading to a greater frequency of successful collisions

20
Q

state whether the combustion of methane is reversible or irreversible and explain why

A

methane + oxygen -> co2 + h2o - irreversible/one way reaction
co2 and h2o are stable and will not react together to form ch4 and o2

an irreversible reaction is shown with a single headed arrow

21
Q

Describe what is meant by a reversible reaction

A

Nitrogen + hydrogen ⇌ ammonia
This is the Haber process - which is used to make ammonia

In a reversible reaction, the products can convert back to the reactants
We illustrate a reversible reaction using a double arrow

Double arrow - means a reversible reaction that can reach equilibrium

22
Q

Describe what is meant by dynamic equilibrium

A

When the reactants convert to products - called the forward reaction

When the products convert back to the reactants - called the reverse reaction

At the start of the reaction, we have a high conc. of reactants and no products
Because we have a high conc. of reactants, the rate of the forward reaction is very high
Since there are no products present, the reverse reaction has a rate of 0

As the forward reaction proceeds, the conc. of reactants decreases and conc. of products increases

Because the conc. of reactants decreases, the rate of the forward reaction also decreases
Because the conc. of products increases, the rate of the reverse reaction also increases

Eventually, there comes a point when both the forward and reverse reactions are taking place at the same rate

At this point, the conc. of both the reactants and the products remain constant - they stop changing

Scientists say that the reaction has reached equilibrium

When we reach equilibrium - the forward and reverse reactions have not stopped - both are still taking place but at the same rate - this is why the conc. of both the reactants and products are now constant

Because both the forward and reverse reactions are still taking place - this is called a dynamic equilibrium

At equilbrium - the concentrations of both the reactants and the products are no longer changing
This does not mean that the concentration of the reactants is the same as the conc. of the products - you could have greater reactants than products or vice versa at equilibrium - or concentrations could be the same

point where lines plateau /level off - where equilibrium has been achieved z
https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcT4vFCFcrlXD6ZQUtTzC-bxf9pkvrp-RcguqA&s

https://www.chemistrylearner.com/wp-content/uploads/2021/07/Dynamic-Equilibrium.jpg

https://images.nagwa.com/figures/explainers/713126106326/10.svg

23
Q

Describe what is meant by a closed system

A

Placing reactants in a sealed container
sealed container - example of a closed system

In a closed system - no atoms can enter or leave the system

23
Q

Four conditions which apply to all equilibrium

A

A closed system - the reactants and products can’t escape

It can be approached from either direction

It is dynamic - the rates of the forward and backward reactions, going on at the same time, are equal + the concentration of the reactants and products are constant but not necessarily the same

The macroscopic properties - e.g. density, concentration, colour, pressure) of the system do not change with time

24
What happens if we approach equilibrium from the other side
We can approach the equilibrium from either side starting with all products no reactants and keep all other conditions the same reaction would reach same equilibrium point - with reactants and products having the same relative conc. as if we started with reactants/approached equilibrium from other side
25
What does the position of equilibrium tell us
The position of equilibrium tells us whether the equilibrium lies towards the reactants or towards the products e.g. at equilibrium we may have a greater proportion of reactants than products We would say that this equilibrium lies towards the left or towards the reactants if we have equal proportions of reactants and products, we would say that this equilibrium lies in the centre
26
Describe what is meant by Le Chatelier's Principle
If a system is at equilibrium and a change is made in any of the conditions, then the equilibrium shifts to counteract the change as much as possible When an external change is applied to a system at equilibrium, the equilibrium moves in the direction that reduces the effect of that change we can change the position of equilibrium by changing the conditions effect of changing conditions is described the principle above
27
Apply Le Chatelier's Principle to describe how the position of equilibrium is affected by changing the conc.
A + B ⇌ C + D reversible reaction at equilibrium In this reaction, two reactants react to form two products If we increase the conc. of reactant A Because we now have molecules of A, we have applied an external change to our system Le Chatelier's principle predicts that equilibrium will move in the direction that reduces the effect of this change Since we have increased the conc. of A Rate of forward reaction is now greater than reverse reaction Means that more A and B now react, forming more C and D So the effect of this is to reduce the conc. of A and B and increase the conc. of C and D Eventually, the rates of the forward and reverse reactions will be the same and a new equilibrium would be reached when we increase conc. of A equilibrium moved to reduce the conc. of A since we now form more products we can say that the equilibrium has shifted towards the right
28
Use Le Chatelier's Principle to predict the effect of changing pressure on reversible reactions at equilibrium nitrogen + hydrogen ⇌ ammonia increasing pressure
How Le Chatelier's principle can be applied to reversible reactions involving gases reaction for haber process - reversible reaction nitrogen + hydrogen ⇌ ammonia all are gases ammonia can also convert back to n2 and h2 with reactions involving gases, we can change the position of the equilibrium by changing the pressure Gas pressure is proportional to the no. of moles of gas present 1:3:2 ratio if equilibrium was entirely on the left - (just reactants), the pressure would be twice as great as if the equilibrium was entirely on the right (just products) If we increase the pressure, this means that the equilibrium will move in the direction that reduces the pressure The right hand side of the equation has fewer moles than the left hand side That means that in order to reduce the pressure, the equilibrium will move towards the right
29
N2O4 ⇌ 2NO2 dinitrogen tetroxide In this reaction, the gas N204 is colourless This forms the gas NO2 which is brown what will happen to position of equilibrium if we increase the pressure
If we increase the pressure, then the equlibrium will move in the direction that reduces the pressure On the left hand side, we have 1 mole of N204 On the right hand side we have 2 moles of NO2 If we increase the pressure, the equilibrium will move towards the left to reduce the pressure The reaction mix will become less brown as NO2 converts to N2O4
30
H2 + Br2 ⇌ 2HBr what will happen to position of equilibrium if we increase the pressure
The position of equilibrium is only affected by pressure, If the total no. of moles is different on either side of the equation# one the left hand side, we have 2 moles of gas on the right we have 2 moles of gas This means that changing the pressure has no effect on the position of equilibrium of this reaction
31
Use Le Chatelier's principle to predict the effects of changing the temperature on reversible reactions at equilibrium N2 + H2 ⇌ NH3 delta H = -92 kJ mol-1 equation for the Haber process - used to produce ammonia
The enthalpy change for the forward reaction is 92 kJ mol-1 Since the enthalpy change has a negative sign - tells us that the forward reaction is exothermic This means that if the reaction, moves in the forward direction - energy is released This release of energy would cause the temperature of the system to increase if Forward reaction - exothermic Reverse reaction must be - endothermic if reaction moves in reverse direction - energy is taken in - causing the temp. of the system to decrease if reaction reaches equlibrium position of equilibrium if temp is increased? increasing temp - means we've applied an external change If we increase the temp. the equilibrium will move in the direction that reduces the temp. - increase in temp will move the equilibrium position This is because the left Because the reverse reaction is endothermic - the reaction will take in in energy and the temp. will decrease
32
Describe the effect of catalysts on the position of equilibrium
Catalysts increase the rate of both the forward and reverse reactions by the same amount That means that catalysts have no effect on the position of equilibrium Using a catalyst simply means that the reaction reaches equilibrium faster, than if we did not use a catalyst
33
Calculate the equilibrium constant Kc
greater conc./proportion of products than reactants - equilibrium lies towards the products/in the centre We can quantify the position of equilibrium, by calculating the equilibrium constant or Kc aA + bB + ⇌ cC + dD Kc = [C]^c x [D]^d / [A]^a x [B] ^b [] = concentration in mol dm-3 put units into the equation = and see that they all cancel out Kc - reaction reach equilibrium at a certain temp. equilibrium constant can have no units - in certain reactions or moldm-3
34
What do equilibrium constants depend on
The equilibrium constants depend on the temperature If you see this reaction with a different equilibrium constant, then the temperature used in that reaction will have been different to the one used in the this reaction
35
Describe what the value of Kc tells us about the position of equilibrium
Kc is different for different reactions Only temperature affect of the value of Kc (changing concentration/adding a catalyst has no effect) The units of Kc vary depending on the reaction Changing temp. will change the value of Kc If temp increases - favours endothermic /back reaction equilibrium shifts to oppose the change Value of Kc decreases since value of denominator increases and value of numerator decreases The size of the equilibrium constant gives us an idea of the relative proportions of reactants and products at equilibrium If the equilibrium constant is one, then the equilibrium lies midway between reactants and products If the equilibrium constant is less than one then the equilibrium lies towards the reactants If the equilibrium constant is greater than one then the equilibrium lies towards the products
36
What are reactions where all species are in the same phase called
In this reaction, all reactants and products are gases. They are in the same phase. These reactions are called a homogenous equilibrium
37
What happens to Kc when concentration changes
When concentration is changed, the equilibrium shifts in such a way the ratio of products to reactants is maintained e.g. if one is increased Kc is changed for the moment Equilibrium will shift to oppose/counteract the change Concentrations of reactants/products will decrease/increase Kc returns to orignial value