Kinetic Theory, Thermal Physics Flashcards

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1
Q

[def] Ideal Gas

A

A gas which strictly obeys the equation of state pV=nRT (and define terms)
with exeption of very high densities, a real gas approximates well to an ideal gas

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2
Q

pV=nRT define terms

A
p= pressure
V= volume
n= number of MOLES
R= Molar gas constant
T= temp IN KELVIN
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3
Q

pV = NkT define terms

A
p= pressure
V=volume
N= number of MOLECULES
k= Boltzman constant
T= temp in KELVIN
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4
Q

Ideal gas assumptions (x5) –> inc way to remember!

A
  1. no [I]ntermolecular forces ——————[i]
  2. [V]olume of each particle is negligible -[Value]
  3. all collisions are [E]lastic ——————-[Energy]
  4. [R]andom motion ——————————[Real]
  5. negligible effect of [G]ravity ————-[Good]
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5
Q

PV graph
describe
conditions

A

ALWAYS CURVED DOWN
Constant mass, constant temp
higher temps = on top

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6
Q

P- 1/V graph

A

Straight lines

higher tempts = steeper grad

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7
Q

Kinetic Theory

A

random distribution of energy amongst molecules

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8
Q

Why gas exerts pressure? (X4)

A
Molecular movement 
=more collisions
=more Δ momentum (per collision AND per unit time)
= greater force (Δmv = Ft)
= greater pressure
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9
Q

rms meaning

A

root mean square

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10
Q

switch (Nm)/V to density

A

density ρ = mass/ volume * for all molecules N

Use in equations given for pressure
P=1⁄3(Nm)/V (c squared bar, rms)
P=1⁄3
ρ
(c squared bar, rms)

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11
Q

P=1⁄3*(Nm)/V *(c squared bar, rms) derivation

first 4 steps

A
  1. momentum = m*(Vin x direction)
  2. Elastic collision with wall Δ momentum after = -2m*(Vin x direction)
  3. Force per unit time ON PARTICLE Ft= -2m*(Vinx dir)
  4. Force on Wall F= (2m(Vinx))/t
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12
Q

P=1⁄3*(Nm)/V *(c squared bar, rms) derivation
time between collisions on wall (step 5)
step 6 step 7

A
  1. time between collisions on this wall
    t= (2l)/(Vinx dir)
  2. combine with step 4
  3. multiply for N molecules
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13
Q

P=1⁄3*(Nm)/V *(c squared bar, rms) derivation
Consider average Vinx direction (step 8)
Why?
How?

A
  1. because molecules moving at different speeds

split velocity into 3 components
c= Vinx + Viny +Vinz
c^2 = Vinx^2 + Viny^2 +Vinz^2

AND Vinx^2 = Viny^2 = Vinz^2 Or else box would drift away!

avg c^2 = 3(Vinx^2)
Vinx^2 = (avg c^2)/3

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14
Q

P=1⁄3*(Nm)/V *(c squared bar, rms) derivation

steps 9, 10, 11

A
  1. combine steps 8 and 7
    F= (Nm(c^2avg))/3L
  2. P=F/A divide by area

L^3 = volume

P=1⁄3(Nm)/V (c squared bar, rms)
PV= 1⁄3
(Nm)
(c squared bar, rms)

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15
Q

[def] Avogadro Constant, Na

A

Number of particles per mole

6.02 x10^23

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16
Q

[def] mole

A

SI unit for “amount of a substance”: it is the amount containing as many particles as there are ATOMS in 12g of Carbon-12

17
Q

Moles equation

A

total mass(in GRAMS) / molar mass

18
Q

what IS boltzman constant?

A

k = R/Na

19
Q

KE per mole

KE per molecule

A

KE PER MOLE = 3/2 * RT

KE PER MOLECULE = 3/2 * kT

20
Q

[def] Internal energy of a system, U

A

Sum of the kinetic and potential energies of the particles of a system

21
Q

[def] Absolute Zero

A

temp of a system when it has minimum internal energy

0Kelvin = -273 degC

22
Q

What does equation
U = (3/2)nRT = (3/2)pV
mean?

A

Internal energy on an IDEAL MONATOMIC GAS

–>because only KINETIC

23
Q

[def] Heat, Q

A

Energy FLOW from a hot object to a cold object
when they are in THERMAL CONTACT

–> heat either going in or out ~(in transit)~ not “contained”

24
Q

Temperature

A

Measure of the average KE of particles in a system

25
Q

Thermal Equilibrium

A

When no heat flows between systems in contact therefore same temp

26
Q

[def] Work, W

A

Work is energy in transit from or to a system

W=pΔV = pressure * increase in volume WHEN AT CONSTANT PRESSURE
–> W= area under PV graph, even at non constant pressure

27
Q

Work gas equation derivation (x3 steps)

A

W=Fx
W=PAx
W=PV

ASSUMES PRESSURE IS CONSTANT

28
Q

[Def] First Law of Thermodynamics

A

Conservation of energy in the system

Q = ΔU + W

29
Q

Q = ΔU + W
what is meant by +ve Q?
what is meant by +ve U?
what is meant by +ve W?

A

Q = ΔU + W
increasing Q = +ve
Increasing U = +ve

work done BY gas = +ve W
work done ON gas = -ve W

30
Q

Conditions when W is can be ignored in first law of thermodynamics

A

For a SOLID (or LIQUID)
W is usually negligible
so
Q = ΔU

31
Q

[def] Specific heat capacity, c

A

Amount of energy required to raise 1kg of a substance by 1K

UNIT: J kg-1 K-1