Is there life on mars? Questions Flashcards

1
Q

Show that, with a surface gravity of 3.7 N/kg and a mass of 6.4 x 10²³ kg, Mars has a radius of about 3400km
G = 6.67 * 10^-11 Nm²/kg²

A

g = (-) GM/r²
so r² = GM/g
= 6.67 x 10⁻¹¹ x 6.4 x 10²³ / 3.7
= 1.15 x 10¹³
r = 3397 km
r ≈ 3400 km

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2
Q

Calculate the gravitational potential at the surface of Mars, taking the radius to be 3390 km
M = 6.4 x 10²³ kg

A

V = (-) GM/r
= 6.67 x 10⁻¹¹ x 6.4 x 10²³/(3390 x 10³)
= 1.259233…x 10⁷
= 1.26 x 10⁷ J/kg

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3
Q

Calculate the gravitational potential energy needed to lift a 2500 kg Mars lander back into orbit at 280 km
G = 6.67 * 10^-11 Nm²/kg²
M = 6.4 x 10²³ kg

A

E = (-) GmM/r²
= 6.67 x 10⁻¹¹ x 6.4 x 10²³ x 2500/(280 x 10³)²
= 1.3612… x 10⁶
= 1.36 x 10⁶

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4
Q

Calculate the kinetic energy needed to lift a 2500 kg Mars lander back into orbit at 280 km

A

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5
Q

A day on Mars is 24 hours 40 minutes. Show that the altitude of an areostationary orbit is about 17,000 km

A

r = (h + rₘ)
mv²/r = GmM/r²
r = GM/v²
v=s/t
s = 2rπ
v = 2rπ / (246060 + 40*60)
2r²π = GMt
r² = 6.03 x 10¹⁷
r = 7.77 x 10 ⁸
h = 7.77 x 10 ⁸ - 3390 x 10³
????????

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6
Q

Assuming the image of Mars is 500 x 500 pixels at 24 bit per pixel:
Calculate the resolution of the image

A

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7
Q

Assuming the image of Mars is 500 x 500 pixels at 24 bit per pixel:
Calculate the amount of information in the image

A

500 x 500 x 24 = 6 Mbits

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8
Q

Assuming the image of Mars is 500 x 500 pixels at 24 bit per pixel:
Calculate the number of alternative colours that the image can contain

A

2^24 = 16,777,216
= 16,800,000 alternatives
(??)

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9
Q

Assuming the image of Mars is 500 x 500 pixels at 24 bit per pixel:
Calculate the data transfer rate needed to transmit the image in 2 1/2 minutes

A

500 x 500 x 24 = 6 Mbits
6,000,000/(2.5*60)
= 40,000 bits/s

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10
Q

Assuming the image of Mars is 500 x 500 pixels at 24 bit per pixel:
Describe how each of the following image processing techniques could improve the image of Mars:
Very brightness
Very contrast
Reduce noise
Detect edges
False colour

A

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11
Q

The orbital radius of Mars’ orbit is 2.3×10¹¹ m and that of earth is 1.5×10¹¹ m:
Use Kepler’s 3rd law T² ∝ r³ to show that the time for Mars to orbit the Sun is about 687 Earth days

A

(2.3×10¹¹ / 1.5×10¹¹)³/² = T / 365
1.89869… x 365 = T
T = 693.02… days
T ≈ 687 days (??)

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12
Q

The orbital radius of miles is orbit is 2.3×10¹¹ m and that of earth is 1.5×10¹¹ m:
Calculate i) The orbital velocity and ii)The centripetal acceleration due to Mars’s orbit around the Sun

A

v²= GM/r
v² = 6.67 x 10⁻¹¹ x 6.4 x 10²³ / (3390 x 10³)
v² = 12.6 x 10⁶
v = 3549 m/s = 3500 m/s (2sf)

a = v²/r = 12.6 x 10⁶ / (3390 x 10³)
= 3.71455…m/s²
= 3.7 m/s² (2sf)

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13
Q

The orbital radius of miles is orbit is 2.3×10¹¹ m and that of earth is 1.5×10¹¹ m:
Calculate the maximum and minimum times for a radio signal to travel from Earth to Mars and back

A

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14
Q

The mean surface temperature on Mars is 210 K:
Show that the root mean square speed of a gas molecule of mass m is given by cᵣₘₛ = √(3kT/m)

A

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15
Q

The mean surface temperature on Mars is 210 K:
Calculate the root mean square speed of i) CO₂ molecules ii) N₂ molecules

A

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16
Q

The mean surface temperature on Mars is 210 K:
So that the escape velocity for a gas molecule at the surface of a planet is given by v = √(2GM/r)

A

0.5mv² = GmM/r
v² =2GM/r
v = √(2GM/r)

17
Q

The mean surface temperature on Mars is 210 K:
Calculate the escape velocity for Mars

18
Q

Use the Boltzman factor to calculate the ratio of N₂ : CO₂ Molecules which have a enough kinetic energy to escape from Mars’s gravity at the mean surface temperature of 210 K. What can you conclude from your answer?

19
Q

By considering the energy required to move a gas molecules to a height h above the surface of a planet use the Boltzmann factor to show that p = p₀ e⁽⁻ᵐᵍʰ/ᵏᵀ⁾ where p₀ is the surface pressure, p is the pressure at height h

20
Q

Calculate the pressure at the top of Mars’s largest extinct volcano Olympus Mons which is at a height of 22 km. you can assume that Mars’s atmosphere is 100% CO2

21
Q

The background radiation level at the surface of Mars is on average 80mSv per year although it can reach as high as 20mSv in one day during a solar proton event. A dose equivalent of 1mSv gives a probability of developing cancer of 3% in an individual.
Calculate the risk of developing cancer due to a single solar proton event

22
Q

The background radiation level at the surface of Mars is on average 80mSv per year although it can reach as high as 20mSv in one day during a solar proton event. A dose equivalent of 1mSv gives a probability of developing cancer of 3% in an individual.
If a colony of 500 individuals were to be established on Mars calculate an estimate of how many would be expected to develop a radiation induced cancer after a 20 year period on Mars

23
Q

The distance from Mars go its L1 point is 320 times the radius of Mars. Solar protons can have energies up to 10keV:
Calculate the speed of 10keV solar protons

A

cᵣₘₛ = √(3kT/m)
=√ (3 x 10 x 1000 x 1.6 x 10⁻¹⁹ / (1.673 x 10⁻²⁷) )
= 1.69384… x 10⁶ m/s
= 1.7 x 10⁶ m/s (2sf)

24
Q

The distance from Mars go its L1 point is 320 times the radius of Mars. Solar protons can have energies up to 10keV:
Calculate the maximum angle through which solar protons must be deflected at L1 in order to miss Mars

25
The distance from Mars go its L1 point is 320 times the radius of Mars. Solar protons can have energies up to 10keV: Calculate the distance that a 10keV solar proton would have to travel in a 2.0 μT uniform magnetic field at L1 in order to be deflected by enough to miss Mars
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