IR plastics Flashcards

1
Q

Why does C-O have a higher wavenumber than C-Cl?

A

C-Cl has a larger mass, and mass is inversely proportional to wavenumber. Therefore the large mass = low wavenumber

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2
Q

Why does C=O have a larger wavenumber than C-O?

A

Higher bond order means higher energy, energy is proportional to wavenumber

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3
Q

Wavenumber is proportional to

A

Energy, frequency, dipole moment

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4
Q

Wavenumber is inversely proportional to

A

wavelength and mass

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5
Q

All materials are

A

different in their atomic, molecular, and bonding compositions

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6
Q

What are polymers

A

macromolecules (large molecules) made up of monomers

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7
Q

what are monomers?

A

repeating units

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8
Q

what does n mean?

A

the number of monomers in a polymer

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9
Q

PETE

A

Polyethylene Terephthalate

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10
Q

HDPE

A

High Density Polyethylene

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11
Q

PVC/V

A

Polyvinyl chloride

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12
Q

LDPE

A

Low Density Polyethylene

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13
Q

PP

A

Polypropylene

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14
Q

PS

A

Polystyrene

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15
Q

Types of molecular vibrations

A

Stretches and bends

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16
Q

Types of stretches

A

Asymmetric and Symmetric

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17
Q

Types of bends

A

In or out of plane and scissor

18
Q

Mixture of different polymers

A

Polymer blend

19
Q

X-Ray Photoelectron Spectroscopy (XPS)

A

identifies the surface chemistry of different plastics including colour and width.

ie. a black plastic would be indecipherable in IR

20
Q

Infrared Spectroscopy (IR)

A

identifies the functional groups of polymers, meaning it can differentiate between plastics of the same family (Polyethylene)

21
Q

If a peak is found at a higher wavenumber what does that mean?

A

that it represents a higher energy dipole bond

22
Q

What does the wavenumber of absorbed light depend on?

A

the atom’s bonding environment (dipoles, bond order, vibration, type of atoms etc)

23
Q

IR light detects what?

A

wavelengths that are absorbed and or transmitted

24
Q

Region left of the peak

A

the functional group region, useful to analyzing specific bonds in unknown structures

25
Q

Region right of the peak

A

the fingerprint region, unique to every molecule

26
Q

sp², C-H stretch

A

3000-3100

27
Q

sp³, C-H stretch

A

2840-3000

28
Q

CH3 Bend

A

1350-1475

29
Q

CH2 bend

A

1450-1475

30
Q

C=O stretch

A

1650-1770

30
Q

C=C ring pair stretch

A

1400-1500 and 1585-1600

31
Q

C-O stretch

A

1200-1310

32
Q

C-Cl stretch

A

550-850

33
Q

O-H stretch

A

3000 - 3300

usually very broad and weak

34
Q

Type of IR used during this experiment

A

ATR-IR

35
Q

How do you calculate the amount of light absorbed

A

measuring intensity of light entering crystal and intensity of light reaching the detector

36
Q

Why does a sp³ occur at lower wavenumbers than sp²?

A

The double bond of the sigma framework of sp2 requires more energy to break/vibrate bc it has more s character which leads to shorter and stronger bonds.

37
Q

Why does the acetate ion only have a peak at 1400?

A

Because of the C-H bend that is there (sp^3), because the acetate ion looses the H ion that allows it to vibrate so it vibrates less and the C-O bond is completely eliminated

38
Q

Can IR distinguish well between LDPE and HDPE?

A

To a certain extent bc one certain peak, but there are other ways that do it better

differential scanning calorimetry (DCS) works better because they use physical properties

39
Q

Difference between LDPE and HDPE

A

LDPE has an “R” group, limiting its bonds with other monomers, leading to a linear structure that is flexible

HDPE is a long branching chain of monomers that can pack together, making it firmer and rigid.