Intro to Calculus Flashcards
Given the ODE
dy/dx + p(x)y = q(x)
What is the integrating factor I(x)?
I(x) = e^∫p(x) dx
What is the complementary function to an ODE?
The solution to the homogeneous equation
Second order linear ODEs:
given the auxillary equation
am² + bm + c
What is the solution to the ode when b² - 4ac < 0?
Roots = a +- bi
y = eᵃˣ( Acosbx + Bsinbx )
Second order linear ODEs:
given the auxillary equation
am² + bm + c
What is the solution to the ode when b² - 4ac = 0?
Root = a
y = (A + Bx)eᵃˣ
Second order linear ODEs:
given the auxillary equation
am² + bm + c
What is the solution to the ode when b² - 4ac > 0?
Roots = a, b
y = Aeᵃˣ + Beᵇˣ
What is the form of the particular solution given
ODE = eˣ(sinx)?
yₚ(x) = eˣ(asinx + bcosx)
What is the form of the particular solution given
ODE = sin²x?
yₚ(x) = a + bcos2x + csin2x
∂f/∂xᵢ (p₁, …, pₙ) = ???
∂f/∂xᵢ (p₁, …, pₙ) = lim(h→0) (f(p₁, …, pᵢ₋₁, pᵢ + h, pᵢ₊₁, …, pₙ) - f(p₁, …, pₙ))/h
Given F(x, y) = f(u(x, y), v(x, y)) what is ∂F/∂x?
∂F/∂x = (∂f/∂u)(∂u/∂x) + (∂f/∂v)(∂v/∂x)
Let F(t) = f(u(t), v(t)) with u and v differentiable and f being continuously differentiable in each variable. Then dF/dt = ??
(∂f/∂u)(du/dt) + (∂f/∂v)(dv/dt)
Notice the ds and ∂s
What is the general solution to the PDE:
∂²f/∂y∂x = 0
f(x, y) = P(x) + Q(y),
What is the general solution to the PDE:
∂²f/∂x² = 0
f(x, y) = xp(y) + q(y)
What is the general solution to the PDE:
uₓₓ − u = 0
Since there are no derivatives with respect to y, we can solve the associated ODE
d²u/dx²− u = 0,
where u is treated as being a function of x only. This ODE has solution u(x) = C₁eˣ + C₂e⁻ˣ,
where C₁ and C₂ are constants, and so the solution to the original PDE is
u(x, y) = A(y)eˣ + B(y)e⁻ˣ,
where A and B are arbitrary functions of y only
Find all solutions of the form T(x, t) = A(x)B(t) to the one-dimensional heat/diffusion
equation
∂T/∂t = κ ∂²T/∂x²
where κ is a positive constant, called the thermal diffusivity.
If we substitute
T(x, t) = A(x)B(t)
into the heat equation we find
A(x)B’(t) = κA′′(x)B(t).
Be very careful with the prime here; it denotes the derivative with respect to the independent
variable in question, so that A′(x) denotes dA/dx and B′(t) denotes dB/dt, etc
If we separate the variables we obtain
A′′(x)/A(x) = B′(t)/κB(t) = c, where we assume A ≠ 0 and B ≠ 0
c must be a constant
{ C₁e^(√(c)x) + D₁e^(-√(c)x) c > 0
A(x) = { C₂x + D₂ c = 0
{ C₃cos(√(-c)x) + D₃sin(√(-c)x) c < 0
What is the Jacobian ∂(x, y)/∂(u, v)?
|∂x/∂u ∂x/∂v|
|∂y/∂u ∂y/∂v|
If A is a domain in the xy-plane mapped one to one and onto a domain B in the uv-plane then
∫ₐ f(x, y) dx dy = ???
∫ₐ f(x, y) dx dy = ∫ᵦ f(x(u, v), y(u, v)) |∂(x, y)/∂(u, v)| du dv
( uₓ uᵧ)⁻¹ = ??
vₓ vᵧ
( uₓ uᵧ)⁻¹ = ( xᵤ xᵥ )
vₓ vᵧ) ( yᵤ yᵥ
Let R ⊂ R². Then we define the area of R to be
A(R) =
A(R) = ∫∫₍ₓ,ᵧ₎∈ᵣ dx dy
Let f : R → S be a bijection between two regions of R², and write (u, v) = f(x, y).
A(S) = ∫∫₍ᵤ,ᵥ₎∈ₛ du dv = ???
A(R) = ∫∫₍ₓ,ᵧ₎∈ᵣ dx dy = ??
A(S) = ∫∫₍ᵤ,ᵥ₎∈ₛ du dv = ∫∫₍ₓ,ᵧ₎∈ᵣ |∂(u, v)/∂(x, y)| dx dy
A(R) = ∫∫₍ₓ,ᵧ₎∈ᵣ dx dy = ∫∫₍ᵤ,ᵥ₎∈ₛ |∂(x, y)/∂(u, v)| du dv
What is the equation of a Circle?
What is the parametrisation?
Area?
x² + y² = a²
parametrisation (x, y) = (a cos θ, a sin θ); area πa²
What is the equation of an Ellipse? What is the parametrisation? Eccentricity? Foci? Directrices? Area?
x²/a² + y²/b² = 1 (b < a) parametrisation (x, y) = (a cos θ, b sin θ); eccentricity e =√ (1 − b²/a²); foci (±ae, 0); directrices x = ±a/e; area πab