interaction of photons and matter Flashcards

1
Q

what your diagnosis?

A

broken wing

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2
Q

what are photons

A

photons include gamma rays and x-rays
-gamma rays: ejected from a nucleus (radioactive decay)
-X-rays: arise from transitions between shells of an atom or from interactions between electrons and nuclei

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3
Q

what is diagnostic and therapeutic radiation energies?

A

-diagnostic imaging involves photons with energies in the keV range (thousands of eV’s)
-radiation therapy usually involves photons with energies in the MeV range (millions of eVs)

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4
Q

as a photon beam enters matter (ex: lead sheet, patient) there are two possible outcomes for each photon:

A
  1. penetrate without interaction (no energy is deposited)
  2. undergo an interaction with atoms (energy is deposited)
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5
Q

what is the difference between transmitted and attenuated photons?

A

-when photons do not undergo an interaction they are transmitted through the matter (come out the other side)
-when photons undergo an interaction, they do not pass through the matter, resulting attenuation of the beam (reduction in intensity)

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6
Q

the transfer of energy from a photon to matter consists of 2 steps:

A
  1. interaction of the photon with an atom, causing an electron or electrons to be set in motion
  2. transfer of energy from the electron to the medium through ionization
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7
Q

do photons transfer energy directly to matter?

A

no
-first to an electron (classified as indirectly ionizing radiation)

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8
Q

what is exponential attenuation?

A

-if a photon undergoes an interaction, it is attenuated (removed from the beam)
-the attenuation is exponential, which means that for a given thickness of material a certain percentage of the photons are attenuated

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9
Q

what is an example of exponential attenuation?

A

-every 1 cm of muscle removes 10% of the photons in a 500 keV x-ray beam
-this means that 10% of the photons undergo an interaction with atoms in that 1 cm layer of muscle

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10
Q

what is the universal attenuation curve?

A

-percent transmission of intensity as a function of material thickness
-a typical x-ray beam with a spectrum of energies will not follow exponential behavior exactly (not a single value of μ because composed of a spectrum of energy)

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11
Q

what is the half-value layer?

A

-the thickness that attenuates a photon beam to 50% is called the half-value layer (HVL)
-described the beam in terms of ability to penetrate a material
-from 120 to 400 kV energy photons, HVL is described in mm Cu, for <120 kV energy photons, HVL is described in mm Al
-HVL in metals is not used to describe high energy therapy beams (MeV energy photons) because penetration in water (soft tissue), not metal, is relevant

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12
Q

what are the 3 main interactions that photons can undergo in material, resulting in their attenuation?

A

-photoelectric effect (PE)
-compton (incoherent) scattering (CS)
-pair production (PP)

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13
Q

what is the total attenuation?

A

-the sum of the individuals attenuation for each process (PE+CS+PP)
-the number of photons attenuated by each process varies in a different way with photon energy E and atomic number Z of the matter

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14
Q

when does the photoelectric interaction occur?

A

occurs when a photon’s energy is transferred to an atom and an electron (‘photoelectron’) is ejected
-photoelectrons have kinetic energy equal to the difference between the incident photon energy and the binding energy of the ejected electron
-the photon is’ absorbed’ by the atom and only an electron leaves the interaction
-electrons deposit their energy very rapidly, so only travels about 1 cm in human tissues

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15
Q

what about the empty shell in a photoelectric interaction?

A

-characteristic x-rays will be produced because an orbital electron is ejected
-because they are low energy x-rays (equal to the differences in shell energies) they are usually absorbed within the material within a very short distance, and are not considered important
-this is particularly true for soft tissue, which is composed of low Z material (H, C, O) and therefore has low K shell binding energies (H=0.14 keV, C=2.8 kev)

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16
Q

what is the likelihood of attenuation by photoelectric interaction?

A

inversely proportional to E^3 of the incoming photon
-directly proportional to Z^3 of the material
-E (incoming photon energy)
-Z (atomic number of material)

17
Q

why is photoelectric interactions important for diagnostic imaging?

A

photoelectric interactions are important at the lower energies used for diagnostic imaging (keV range)
-therefore, the likelihood of attenuation during diagnostic imaging is highly dependent on the Z of the material
-a high Z material will attenuate many more diagnostic x-rays than a low Z material

18
Q

what is the photoelectric interaction summary?

A

-the incoming photon is absorbed, and an electron (‘photoelectron’) is ejected
-the likelihood of photoelectric interaction is proportional to 1/E^3 and Z^3
-important process at lower photon energies (up to 100 keV) which are used for diagnostic imaging (ex: radiography, computed tomography)

19
Q

when does Compton (incoherent) scattering happen?

A

occurs when a photon’s energy is transferred to an atom and an electron (“Compton electron”) is ejected
-the photon is not absorbed by the atom, but also leaves the interaction (“scattered” because its direction is changed)
-the energy of the incoming photon is shared between the Compton electron and the scattered photon

20
Q

what is the likelihood of attenuation of compton scattering?

A

-inversely proportional to E
-independent of Z

21
Q

what is compton scattering used for in imaging?

A

-compton scatter (and photoelectric) occurs at the energies used for diagnostic imaging (keV range)
-compton scattering is by far the most important process at the higher energies used for radiation therapy (MeV range)

22
Q

why do we use MeV beams for radiation therapy?

A

-one of the reasons we use MeV beams for radiation therapy of people and animals with tumors is that all tissues will attenuate x-rays in a similar way, regardless of Z

23
Q

what is Compton (incoherent) scattering summary?

A

-the incoming photon is scattered and an electron is ejected
-the scattered photon and the compton electron share the energy of the incoming photon
-the scattered photons need to be considered when workers are in the room during patient radiographs
-the likelihood of compton scatter is proportional to 1/E and independent of Z
-the most important process at higher photon energies (MeV range) which are used for radiation therapy

24
Q

what the pair production interaction?

A

-an interaction between a photon and a nucleus where the energy of the photon is transformed into an electron and a positron
-the energy of the incoming photon is shared between the electron and the positron
-the photon is ‘absorbed’ by the atom

25
Q

what leaves the interaction (pair production)?

A

-the positron leaves the interaction, and when it stops, it interacts with a free electron
-the positron and electron disappear (annihilate) and two 0.511 MeV photons are created

26
Q

when is pair production very important (commonly used)?

A

only becomes important for very high energies (>10 Mev)
-pair production cannot occur unless the incoming photon has an energy > 1.022 MeV
-even though the incoming photon is absorbed by the atom, scattered photons are creates because the positron results in two photons when it annihilates
-the likelihood of pair production increases with increasing Z

27
Q

what is the relative importance of interactions in soft tissue (water) summary?

A
28
Q

what is total attenuation of a photon beam?

A

depends on Z of material and energy of photon beam
-a cobalt 60 therapy machine produces two gamma rays of 1.16 MeV and 1.33 MeV (average energy is 1.25 MeV)
-an x-ray machine produces a spectrum of photon energies, but can be roughly considered as a monoenergetic beam of peak kilovoltage E/3
-a linear accelerator produces a high energy x-ray beam and is named based on the maximum photon energy (ex: a 6 MV linac has a maximum photon energy of 6MeV and an average photon energy of 2 MeV)