Integration (P1.13 & 2.11) Flashcards

1
Q

∫ x^n dx =

A

x^n+1 / n+1 + c

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2
Q

indefinite vs definite integrals

A

indefinite: + c - produces a function
definite: integral b/w 2 limits - produces a value

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3
Q

describe how to find the constant of integration, c

A

integrate the function
substitute the values (x,y) of a point on the curve into the integrated function
solve the equation to find c

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4
Q

describe how to find the definite integral

A

[f(x)]ba = f(b) - f(a)

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5
Q

describe how to find area under curve

A

definite integral

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6
Q

for areas under the x-axis,

A

integral gives negative answer

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7
Q

areas b/w curves & lines

A

practice

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8
Q

∫ 1/x dx =

A

ln|x| + c

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9
Q

∫ e^kx dx =

A

1/k e^kx + c

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10
Q

∫ cosx dx =

A

sinx + c

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11
Q

∫ sinx dx =

A

-cosx + c

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12
Q

describe integration by substitution

A

substitute a value for u
du/dx =
dx =
cancel out any x’s left
integrate
sub value back into u

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13
Q

∫ f’(ax+b) dx =

A

1/a f(ax+b) + c
reverse chain rule
only works for single powers of x

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14
Q

∫ k f’(x)/f(x) dx =

A

ln|f(x)| & adjust any constant
if integrating a fraction with no trig., look for bottom differentiating to top –> ln

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15
Q

tips for integration by parts

A

∫ uv’ dx = uv - ∫ vu’ dx

u should be a function which becomes simpler after differentiation
it must be possible to integrate v’ to find v
always make lnx term = u
sometimes you need to use integration by parts twice
if vu’ is a product of functions, you have used the wrong u & v (or need to do it twice)

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16
Q

practice integration using trig. identities

A
17
Q

integrate expressions in the form kf’(x)(f(x))^n

A

f(x))n + 1 & adjust constant

18
Q

practice integration with partial fractions

A
19
Q

describe Y2 finding areas

A

the area bounded by 2 curves can be found using integration
R = ∫ba f(x) -g(x) dx
= ∫bc f(x) dx - ∫ba g(x) dx
make sure area under x-axis is made positive before finding total area (to ensure the values for area don’t cancel out)

20
Q

practice exam-style integration questions with transformations

A

see OneNote

21
Q

tips for trapezium rule

A

n = # of strips/trapezia
for a convex curve, trapezium rule gives an overestimate for the area
for a concave area, trapezium rule gives an underestimate for the area

22
Q

explain the value for h in the trapezium rule

A

h = b-a / n
state # of trapezia & each has a height of h
# trapezia x h = b-a

23
Q

explain why trapezium rule is an overestimate of the area under the curve

A

curve is convex
so lines connecting the 2 endpoints would be above the curve
so it is an overestimate

24
Q

explain why trapezium rule is an underestimate of the area under the curve

A

curve is concave
so lines connecting the 2 endpoints would be below the curve
so it is an underestimate

25
Q

how is the accuracy of the trapezium rule be improved?

A

more strips used
decreased width of each strip as more values are used

26
Q

practice trapezium rule

A
27
Q

describe how to solve differential equations

A

form differential equation: dy/dx =
separation of variables: put all y terms on the LHS & all x terms & #s on the RHS
see OneNote

28
Q

how do you find the particular solution to a first-order differential equation?

A

if you know one point on the curve
= boundary condition
practice

29
Q

modelling with differential equations

A
30
Q

describe integration as the limit of a sum

A

∫ba f(x) dx = limδ->0 Σb,x=a f(x) δx

you can approximate the area under a curve as a # of thin rectangular strips
as the strips get thinner, the approximation becomes more accurate
limit notation formalises the idea of a definite integral as the limit of a sum of areas of these rectangular strips

how transformations affect area under curve

pg 329 P2 textbook