Integration Flashcards

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1
Q

What are the expressions for x and y in polar coordinates?

A
x = rcos(θ)
y = rsin(θ)
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2
Q

What is the area element dA equal to in polar coordinates?

A

dA = r dr dθ

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3
Q

How many dimensions are polar coordinates?

A

2 dimensions

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4
Q

What are cylindrical coordinates?

A

Polar coordinates extended into 3 dimensions, adding the cartesian z coordinate.

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5
Q

What are the expressions for x, y and z in cylindrical coordinates?

A
x = rcos(θ)
y = rsin(θ)
z = z
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6
Q

What is the volume element dV in cylindrical coordinates?

A

dV = r dθ dr dz

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7
Q

What are the 3 components in spherical coordinates and what do they represent?

A
  • r = distance from the origin
  • θ = angle away from z axis subtended by OP (clockwise between 0 and pi)
  • ϕ = angle from x axis subtended by projection of vector OP onto y axis (anticlockwise between 0 and 2pi)
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8
Q

What are the expressions for x, y and z in spherical coordinates?

A
x = rsinθcosϕ
y = rsinθsinϕ
z = rcosθ
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9
Q

What is the volume element dV in spherical coordinates?

A

dV = r^2 sinθ dr dθ dϕ

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10
Q

How do you construct a line integral?

A

Parameterise the curve r to get |dr/dλ| dλ, where |dr/dλ| is the derivatives of x, y, z etc added together and square rooted

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11
Q

How do you construct a line integral for a vector field?

A

int (F.dR) = int (Fxi + Fyj + Fzk) . (dxi + dyj + dzk)
= int (Fx dx + Fy dy + Fz dz)
If you have an equation (e.g. x = y^2) then find the derivative of the equation and then use this in the above formula. Then pick either dy or dx and integrate between the change in y or the change in x.

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12
Q

What is the surface change dS for spherical coordinates and cylindrical coordinates?

A

Spherical - dS = r^2 sinθ dθ dϕ

Cylindrical - dS = r dr dθ

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13
Q

What are surface integrals used for?

A

Calculate the surface area.

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14
Q

How do you perform surface integrals involving vectors?

A

dS (vector) = dS r(hat-vector)

Basically add an r(hat) into the integral

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15
Q

How do you calculate the gradient of a function ϕ?

A

dϕ/dx i + dϕ/dy j + dϕ/dz k

where d is a partial derivative.

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16
Q

How do you construct a surface integral as a vector product?

A

dS = (dr/dλ X dr/dμ) dλ dμ

where λ and μ are the variables in the equation