Image Production- image acquisition, and evaluation Flashcards
What may be the cause of an over exposed image?
SID too low
If the KVP is increased 15 percent, how much must the mAs be reduced in order to maintain the same receptor exposure?
50 percent
What distance would produce the lease distortion?
72 in
The longer the SID, the less size distortion
A non-great exposure requires 15 mAs. How much mAs is needed if a 5:1 ratio grid is used?
30 mAs
Which of the following will occur on the tube angle is decreased?
Shape distortion will decrease
Special resolution can be improved by reducing which of the following?
Focal spot size
If the mA is set at 400 and the mAs obtained is 80, what is the exposure time?
0.2 seconds
To calculate time, divide the mAs by the mA
SID should be reduced by 1 inch for every ————— degrees or CR angle?
5
How are mA and seconds related to eachother when used to maintain receptor exposure?
Inversely proportional
The ratio of SID to SOD represents which of the following?
Magnification ratio
What is the greatest advantage of digital imaging?
Contrast resolution
What is the best method to reduce scatter radiation which causes fog?
Collimation
Spatial resolution can be improved by?
Maximum SID
What is an advantage of the air gap technique?
Eliminates the need for a grid
How will be in filtration affect the primary beam?
Make it more homogeneous