Hybridization & Resonance Flashcards

1
Q

What does hybridization mean?

A

Hybridization, kind of like a hybrid car mixing electric power and gas power, is when bound atoms mix higher & lower valence electron orbitals

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2
Q

What kind of orbitals does Carbon have (where are it’s electrons)?

–Carbon forms what kind of orbitals when sp3?

A

2 electrons in “S” orbital and 2 electrons in “P” orbital

–carbon will form 4 orbitals of equivalence energy when hybridized as sp3

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3
Q

How to determine hybridization

A

of sigma bonds + # of unbonded electron PAIRS

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4
Q

VSEPR (valence shell electron pair repulsion theory)

A

Predicts the shape of molecules depending on their repulsion of lone pairs of electrons

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5
Q

What determines shape and bond angle?

A

Hybridization!

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6
Q

sp hybridization

A

Linear (180 degrees)

e.g., CO2

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7
Q

sp2 hybridization

A
  • -Trigonal planar (no lone electrons) (e.g., SO3)

- -Bent, 120 degrees, due to one lone electron pair (e.g., SO2, O3, PbCl2)

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8
Q

sp3 hybridization

A
  • Tetrahedral (e.g., CH4, SO4^2-)
  • Trigonal pyramidal (e.g., NH3-, H3O+)
  • Bent, 109.5 degrees (e.g., H2O, SCl2)
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9
Q

sp3d hybridization

A
  • Trigonal bipyramidal (e.g., SOF4)
  • Seesaw (e.g., SF4)
  • T shaped (e.g., BrF3)
  • Linear (90 degrees/120 degrees or 180 degrees)
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10
Q

sp3d2

A
  • Octahedral
  • Square pyramidal
  • Square planar (90 degrees)
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11
Q

Resonance structure stability

A

The structure that has more possible resonance structures will be the most stable

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12
Q

Rules for resonance structures

A
  1. Follow octet rule
  2. Bond moves starting with a lone electron pair, a double bond, or a triple bond
  3. Make the formal charge the most “comfortable” if a formal charge is unavoidable
  4. Make structures without formal charges, if possible
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13
Q

How do you determine if a ring molecule is aromatic?

A

Follow Hückel’s rule: 4n + 2 pi electrons

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14
Q

Characteristics of aromatic compounds

A
  1. Conjugated, unsaturated ring system
  2. High stability due to ability to resonate (e.g., benzene)
  3. Follows Hückel’s rule: must have exactly 4n + 2 pi electrons
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