HC 10 - Systems Modelling Flashcards
hoorcollege 10
Moleculaire interacties (celfunctie) en regulatie hangt af van … interactions van duizenden macromoleculen
transient
For complete picture, what is needed to judge importance of a situation?
Quantitative information
-Concentrations
-Affinities
-Kinetic behavior
For molecular interactions, what do we need to describe?
-Molecule interaction
-Catalyse reactions
-Change of molecules in time
-Gene Y promotes gene Z for example
Types of interaction
-Inhibition of geneX to geneZ > transcription repressor X inhibits expression if Z
-Promotion via activator X
Gene transcription regulation
-RNAp(olymerase) binding site within promotor
-TFs with X binding sites within the promotor
> binding to DNA
> expression gene Y
> increased transcription
The time for transcription and translation is
somewhat equal
Gene transcription regulation: activator characteristics
Activator increases rate of mRNA transcriptions when bound to promotor, it typically transits rapidly between active and inactive forms (e.g. phosphorylation state)
Repressor mechanism of action
Blocks RNAp for binding by binding the promotor
Interaction model between protein (TF) A and promotor p-x
A + p-x <=> A:p-x
kon and koff are the rate constants
Rate of complex formation and dissociation for promotor and protein
complex formation: d[A:px]/dt = kon[A][px]
complex dissociation: d[px]/dt = koff[A:px]
what is kon
Number of productive collisions per unit time per protein at a given concentration of px
[kon] and [koff]
[kon] = M^-1s^-1
[koff] = s^-1
these are different because the units on both sides of the equations must be equal.
At steady-state, the promotor model looks like
Rate of formation = rate of dissociation
kon[A][px] = koff[A:px]
[A:px] = (kon/koff) [A][px]
=K[A][px]
What does K mean in the promotor model? And K_D
K = kon/koff: association constant in M^-1
K_D = 1/D: dissociation constant in M
When there is a strong interaction between A and px, K becomes larger/smaller
larger
In general we know the amount of total px: pxT. Substitute to a equation of [A:px] at steady state
[px] = [pxT] - [A:px]
[A:px]steadystate = K[A][px]
[A:px] = (K[A]/(1+K[A]))*[pxT]
The production rate of protein X is determined by … in the promotor model
the occupancy of the promotor
bound fraction of promotor
[A:px]/[pxT] = K[A]/(1+K[A])
Transcription rate
beta * K[A]/(1+K[A])
beta: represents binding of RNAp and the steps to mRNA > transcription rate when activator is bound
Protein production rate
beta * m * K[A]/(1+K[A])
m: rate of protein made per mRNA
Protein degradation
-Degradation leads to exponential decline in protein levels
-Mean life time tau
-takes active degradation and dilution due to cell growth into account
Protein degradation rate
= [X] / tauX
concentration / life time (halfwaardetijd)
A low tau means a … degradation rate
high
d[X]/dt formula
= protein production rate - protein degradation rate
= beta m (K[A]/(1+K[A])) - ([X]/tauX)
[Xst] formula (at steadystate)
[Xst] =beta m (K[A]/(1+K[A])) tauX
> fill in zero for d[X]/dt
The faster X is degraded (smaller tau), the … time is needed to reach steady-state
less