Halogens Flashcards

1
Q

Trend in boiling points and why

A

Increase down the group because stronger van der waals forces as larger mr

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2
Q

trend in electronegativity and why

A

decreases down the group because more electron shielding so less strong attraction to the valence electrons

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3
Q

reactivity trend and why

A

less reactive down the group because halogens gain an electron when reacting and thus larger atomic radius and more electron shielding will make it harder to gain electron

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4
Q

oxidising power trend

A

less oxidising down the group

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5
Q

ionic equation of chlorine and bromine displacement reaction

A

Cl2 + 2Br- = 2Cl- + Br2

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6
Q

chlorine + potassium bromide colour change

A

colourless to orange

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7
Q

chrorine + potassium iodide colour change

A

colourless to brown solution

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8
Q

bromine water + potassium iodide colour change

A

orange to brown

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9
Q

F2 colour and state

A

pale yellow gas

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10
Q

chlorine colour and state

A

pale green gas

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11
Q

bromine colour and state

A

red/brown liquid, brown/orange gas

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12
Q

iodine colour and state

A

grey solid and purple gas

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13
Q

what happens when you mix chlorine and cold, dilute sodium hydroxide + equation

A

2NaOh + Cl2 = NaClO + NaCl + H2O
Makes bleach
disproportionation reaction as chlorine is oxidised and reduced simultaneously

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14
Q

chlorine + water equation

A

Cl2 + H2O =(reversible) HClO + HCl

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15
Q

chlorine + water in sunlight

A

2CL2 + 2H2O = 4H+ + 4Cl- + O2

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16
Q

trend in reducing power and why

A

increases down the group because more electron shielding so easier to lose electron

17
Q

NaF + sulfuric acid equation and observation

A

NaF + H2SO4 = NaHSO4 + HF misty fumes produced

18
Q

NaCl + sulfuric acid equation and observation

A

NaCl + H2SO4 = NaHSO4 + HCl misty fumes produced

19
Q

NaBr and sulfuric acid two equations and observations and explanation

A

NaBr + H2SO4 = NaHSO4 + HBr
2HBr + H2SO4 = Br2 + SO2 = 2H2O

redox equation, misty fumes first reaction, orange fumes second reaction as bromine is better reducing agent so reacts further

20
Q

NaI and sulfuric acid four equations and observations and explanation

A
NaI + H2SO4 = NaHSO4 + HI
2HI + H2SO4 = I2 + SO2 + 2H2O
6HI + H2SO4 = 3I2 + S + 4H2O
8HI + H2SO4 = 4I2 + H2S + 4H2O
gas produced and grey iodine solid
21
Q

what do you add to test for halide ions and why

A

dilute nitric acid to remove unwanted ions then add silver nitrate solution

22
Q

fluoride and silver nitrate observation

A

no precipitate

23
Q

chloride and silver nitrate

A

white precipitate

24
Q

bromide and silver nitrate

A

cream precipitate

25
Q

iodide and silver nitrate

A

yellow precipitate

26
Q

chloride and ammonia solution

A

white precipitate, dissolves in DILUTE NH3

27
Q

bromide and ammonia solution

A

cream precipitate, dissolves in CONCENTRATED NH3

28
Q

iodide and ammonia solution

A

yellow precipitate, INSOLUBLE in any ammonia solution