Haloalkanes Flashcards

1
Q

In an elimination mechanism, what does the -OH act as?

A

Base (proton acceptor)

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2
Q

Elimination mechanism with 2-bromopropane to an alkene?

A
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3
Q

Why are there different rates of hydrolysis?

A

As the bond enthalpy decreases, it is easier to break the C—Halogen bond so rate of reaction increases

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4
Q

What is the method for testing the rate of substitution (hydrolysis) with haloalkane? (5)

A

1) Place measured sample of each haloalkane into separate test tubes
2) Place in water bath at 50 degrees
3) Into another test tube, place ethanol, water + aqueous silver nitrate in water bath
4) Once equal temperature, add equal volumes of ethanol mixture + haloalkane together
5) Time how long it takes for precipitate to form

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5
Q

Nucleophilic substitution of ammonia with bromoethane?

A
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6
Q

What are the following for elimination to alkene:

  • Reagent
  • Conditions
A
  • NaOH, KOH
  • Hot ethanolic + concentrated solvent
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7
Q

What are the following for nucleophillic substitution for NH3:

  • Reagent
  • Conditions
  • Type of product
A
  • NH3 (ammonia)
  • Excess ammonia (high heat + pressure)
  • Amine
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8
Q

Nucleophillic substitution by CN- (nitrile/cyanide) with bromoethane?

A
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9
Q

For nucleophillic substitution by CN-, what is the:

  • Reagent
  • Conditions
  • Type of product
A
  • KCN
  • Aqueous + ethanolic solvent
  • Nitrile
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10
Q

With nucleophilic substitution by -OH to alcohol, what is the:

  • Reagent
  • Conditions
A
  • NaOH or KOH
  • Aqueous solvent
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11
Q

Nucleophilic subsitution by -OH with bromoethane to alcohol?

A
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12
Q

What do curly arrows show?

A

Show the movement of a pair of electrons

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13
Q

Why are CFCs damagaging to the ozone layer?

A

Cl. is regenerated in the final propagation step which causes a chain reaction in decompostion of the ozone

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14
Q

Explain why CF3CH3 doesn’t lead to the depletion of the ozone? (2)

A
  • Doesn’t contain Cl
  • C—-F bonds are strong + don’t break
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15
Q

Write 3 equations to show how CCl3F is involved in damaging the ozone layer?

A
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16
Q

Free-radical subsitution reaction between methane + chlorine?

A

INITIATION —–> Cl2 –-U.V–> 2Cl∙

PROPOGATION —–> Cl∙ + CH4–> ∙CH3 + HCl

          -----> ∙CH3 + Cl2--> CH3Cl + Cl∙

TERMINATION —–>Cl∙ + ∙CH3 –> CH3Cl

         -----> ∙CH3 + ∙CH3 --> C2H6

            -----> Cl∙ + Cl∙ --> Cl2
17
Q

Description of termination in free-radical substitution?

A
  • TERMINATION - 2 free-radicals combine
18
Q

Description of propogation in free-radical substitution? (2)

A

STEP 1 - free-radical produced takes a H from alkane, which turns into free-radical + produces a hydrogen halide

STEP 2 - alykyl radical produced takes halogen atom from molecule, which forms haloalkane and Cl. acts as a catalyst

19
Q

Description of initiation in free-radical substitution?

A

INITITATION - halogen molecule splits into 2 free-radicals, breaking the halogen—halogen bond called homolytic fission

20
Q

What is a free-radical?

Conditions for free-radical substitution?

A

A species with an unpaired electron (very reactive)

UV light - provides energy required to break halogen—halogen bond + start reaction

21
Q

How can haloalkanes be classified? (3)

A
  • Primary - C atom bonded to halogen which is only bonded to 1 other C
  • Secondary - C atom bonded to halogen which is bonded to 2 other C
  • Tertiary - C atom bonded to halogen which is bonded to 3 other C
22
Q

Suggest why water is not a suitable solvent for nucleophilic substitution?

A

Compound will be insoluble as water would act as the nucleophile