Half-life Flashcards

1
Q

What is half-life?

in terms of nuclei

A

The time it takes for the number of nuclei of the isotope in a sample to decrease by half

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2
Q

What is half-life?

in terms of count rate/activity

A

The time it takes for the count rate/activity
from a sample containing the isotope to decrease by half of its initial level

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3
Q

What is count rate?

A

The number of decays per second recorded by a detector (e.g. Geiger-muller tube)

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4
Q

What are the units of count rate?

A

Bq

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5
Q

What is activity?

A

The number of decays per second

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6
Q

What are the units for count rate?

A

Bq

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7
Q

A radioactive isotope has a half-life of 15 days and an initial count rate of 200Bq.

Determine the count rate after 45 days

A
  1. Calculate how many HALF-LIVES are involved

1 hl= 15
45/15 = 3
= 3 half-lives

  1. Do the count rate divided by 2 for how many half-lives it is

= 3 half lives
so…

1) 200/2= 100
2) 100/2=50
3) 50/2=25

=25 Bq

Answer = 25Bq

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8
Q

What is the half-life of a sample where the activity drops from 1,200 Bq to 300Bq in 10 days?

A

1.Find out how many half-lives are involved

Original activity = 1200
1)1200/2=600
2)600/2=300

=2 half lives

  1. Calculate the number of days using this information

If this occurs in 10 days, then 10 days = 2 half lifes

so…

= 5 days = 1 half life (10/2=5)

Answer = 5 days

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9
Q

What is the net decline expressed as a ratio?

A

The o.g number of nuclei: remaining number of nuclei

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10
Q

The half-life of cobalt-60 is 5 years.

If there are 100 grams of coalt-60 how many grams will remain in 15 years

A

So this is asking about the net decline (the fraction of radioactive nuclei remaining)

So to find the ratio (the factor you multiply it by) you 1/2 to the power of the number of half lives

= 1 half-life = 5 years
15/5=3
so it’s 3 half lives

(1/2)3= 1/8 of the cobalt-60 will be left

100 x 1/8 = 12.5g

= 12.5g of cobalt-60 remaining
(as ratio, thats 1:0.125)

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11
Q

How do you calculate the net decline in a radioactive emission after a given number of half-lives?

A

1) find the factor by doing 1/2 (the half-life) to the power of how many half-lives
2) Multiply the factor by the original number, this will get you the remaining number of radioactive nuclei left
3) Write the answer as a ratio of og:remaining

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12
Q

Radioactive decay is a [blank] process

fill in the blank

A

Radioactive decya is a random process

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13
Q

A sample of caesium-137 is initially 40kBq

How long will it take for the activity of the sample to fall BY 30kBq?

(1 half life of the isotope= 30 years)

A

The question is NOT asking how long it will take for it to fall TO 30kBq but how long it willtake for it to fall BY 30kBq- it’s trying to CATCH YOU OUT

It’s really asking how long it will take for the activity to get to 40-30= 10 SO 10kBq

so it’s
1) 40/2= 20
2) 20/2=10
= 2 half lives

1 h-l = 30
so 2 h-l = 60

= 60 years

Answer = 60 years

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14
Q

Americium-241 is an alpha-emitting isotope with a half-life of 432 years

Calculate the fraction of americim-241 remaining after 1,296 years

A

This question is asking about the ✨net-decline✨!!
we know how to do this 😉

1 half-life = 432 years

1296/432 = 3 half-lives

= (1/2)3= 1/8
since they only want the fraction of what’s remaining, we don’t need to multply it by the o.g. (even though there is no o.g. given)

=1/8th of Americium-241 will be remaining

Answer = 1/8 remaining

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15
Q

Why aren’t the activity and countrate of an isotope the saame?

A

The count-rate is the decays per second recorded by a detector so italso detects decays produced by background radiation

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16
Q

How do you calculate the correct half-life of an isotope?

A

Count rate = Total count rate - Background count rate