Graphs – implications Flashcards

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1
Q

From what graph can speed be calculated? (name + method)

A

distance-time graph; divide given distance by time taken to travel it

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2
Q

Graph used to calculate acceleration (name + method)

A

velocity-time graph; change in velocity ÷ change in time

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3
Q

Graph used to calculate distance (name + method)

A

speed-time graph; multiply values on both axes in a precise region

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4
Q

How can the distance travelled by an object with increasing/decreasing speed be calculated from a speed-time graph?

A

Use the formula for the area of a triangle (1/2bh, b is total time, h is speed) to calculate the area below the plotted line.

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5
Q

How can the average velocity of an ever-accelerating car be calculated?

A

Divide the object’s acceleration by the time taken.

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6
Q

State how constant speed is represented on a speed-time graph.

A

A straight, horizontal line while the object maintains a specific speed

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7
Q

State how constant speed is represented on a distance-time graph.

A

A diagonal line with a positive gradient (extending to the top-right corner of the graph)

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8
Q

State how constant acceleration is represented on a velocity-time graph. (2 ways)

A

A diagonal line with a positive gradient (extending to the top-right corner of the graph)

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9
Q

How is a stationary object represented by a distance-time graph?

A

It is shown with a flat line either at zero or a set, unchanging distance extending from the y-axis to the right.

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10
Q

How is increasing/decreasing speed represented on a speed-time graph?

A

A diagonal line extending to the opposite corner, upward/downward

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11
Q

In what way is ZERO acceleration represented by a velocity-time graph?

A

It is shown via a flat line extending from the y-axis (a given velocity) to the right of the graph.

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12
Q

Explain the difference between a horizontal line on a velocity-time vs distance-time graph

A

Velocity-time graph: zero acceleration, therefore object maintains a constant (unchanging) velocity.
Distance-time graph: zero speed, therefore object is stationary.

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