Glycogen, TCA Cycle and Mitochondria (Lecture 14)

Question 1

adenine nucleotide translocase

Answer 1

a transporter that allows 1ATP to leave the matrix to drive energy requiring processes. during this process, one ADP will enter the matrix

when the ADP enters it will be phosphorylates, but a Pi must be imported in to allow for this reaction. this will generate 1ATP

this is why we add an extra proton (phosphate carrier is a symporter) per Pi

electrogenic transport, as the import of ADP and export of ATGP results inn the net charge of 1- being exported into the inter membrane space (this is easy because the IMS is more positive)

Question 2

adenine nucleotide translocate inhibitors

Answer 2

locks ANT is a position that prevents the translocation

atractyloside
carboxyatractyloside

Question 3

adenine translocation path

Answer 3

ADP in the inter membrane space can bind into the empty C-state cup

protein. undergoes a conformational switch to allow ADDP to leave

this new conformation allows ATP to bind and undergo another conformational change to induce its release

this new conformation can allow ADP to enter

Question 4

calculate the delta Go of Complex I (e- transfer)

Answer 4

NADH + H+ + Q –> NAD+ + QH2

Nernst eqn:

delta Go’ = -n F (E)

n= e-

E = reduction potential of e- acceptor- reduction potential of e- donor

CoQ- NADH

delta Go’= -69.4 kJ/mol

Question 5

calculate the delta Go of Complex II (e- transfer)

Answer 5

FADH2 + Q –> FAD+ + QH2

Nernst eqn:

delta Go’ = -n F (E)

n= e-

E = reduction potential of e- acceptor- reduction potential of e- donor

CoQ- FAD (or succinate)

delta Go’= -16.4 kJ/mol

Question 6

calculate the delta Go of Complex III (e- transfer)

Answer 6

cytochrome-ox QH2 –> Q cytochroom-redu

Nernst eqn:

delta Go’ = -n F (E)

n= e-

E = reduction potential of e- acceptor- reduction potential of e- donor

cytochrome c - CoQ

delta Go’= -36.6 kJ/mol

Question 7

calculate the delta Go of Complex IV (e- transfer)

Answer 7

cytochrome-reduced + 2H+ + 1/2 O2 –> cytochrome -ox + H20

Nernst eqn:

delta Go’ = -n F (E)

n= e-

E = reduction potential of e- acceptor- reduction potential of e- donor

O2- cytochrome c

delta Go’= -112 kJ/mol