GLUCOSE STRUCTURE Flashcards

1
Q

What is the molecular formula of glucose?

A

C₆H₁₂O₆

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2
Q

What happens when glucose is heated with HI?

A

It forms n-hexane, suggesting all six carbon atoms are in a straight chain.

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3
Q

What reactions confirm the presence of a carbonyl group (>C=O) in glucose?

A

Formation of oxime with hydroxylamine and cyanohydrin with HCN.

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4
Q

What indicates that the carbonyl group in glucose is an aldehyde?

A

Oxidation with bromine water forms gluconic acid (a six-carbon carboxylic acid).

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5
Q

What does acetylation of glucose with acetic anhydride confirm?

A

The presence of five –OH groups in glucose, forming glucose pentaacetate.

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6
Q

What happens when glucose or gluconic acid is oxidized with nitric acid?

A

Both yield a dicarboxylic acid, saccharic acid, indicating the presence of a primary alcoholic (–OH) group in glucose.

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7
Q

What does the ‘D’ in D(+)-glucose represent?

A

It represents the configuration of glucose relative to D-glyceraldehyde.

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8
Q

What does the ‘(+)’ in D(+)-glucose indicate?

A

It indicates that glucose is dextrorotatory (rotates plane-polarized light to the right).

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9
Q

Do ‘D’ and ‘L’ notations indicate optical activity?

A

No, ‘D’ and ‘L’ indicate relative configuration, not optical activity, and are unrelated to ‘d’ and ‘l’ (which denote actual optical rotation).

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10
Q

What do the ‘D’ and ‘L’ notations indicate in carbohydrates?

A

They indicate the relative configuration of a stereoisomer in relation to D- or L-glyceraldehyde.

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11
Q

What is the reference compound used to determine the D- or L-configuration of carbohydrates?

A

Glyceraldehyde, which has one asymmetric carbon and exists in two enantiomeric forms.

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12
Q

How do D- and L-glyceraldehyde differ?

A

They are mirror-image enantiomers; D-glyceraldehyde has the –OH group on the right, while L-glyceraldehyde has it on the left.

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13
Q

What determines whether a compound has a D- or L-configuration?

A

If it can be chemically correlated to D-(+)-glyceraldehyde, it has a D-configuration; if correlated to L-(–)-glyceraldehyde, it has an L-configuration.

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14
Q

How is the D-configuration identified in glyceraldehyde?

A

The –OH group is on the right when written using standard conventions.

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15
Q

How is the L-configuration identified in glyceraldehyde?

A

The –OH group is on the left when written using standard conventions.

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16
Q

Which carbon atom is used to determine the D- or L-configuration in glucose?

A

The lowest asymmetric carbon atom (farthest from the most oxidized carbon, –CHO).

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17
Q

Why is D-(+)-glucose assigned the D-configuration?

A

Because the –OH group on its lowest asymmetric carbon is on the right, similar to D-(+)-glyceraldehyde.

18
Q

How should the structure of glucose be written for configuration comparison?

A

With the most oxidized carbon (–CHO) at the top.

19
Q

Why doesn’t glucose give Schiff’s test?

A

Because glucose exists predominantly in its cyclic hemiacetal form, reducing the availability of the free aldehyde group.

20
Q

Why doesn’t glucose form a hydrogensulphite addition product with NaHSO₃?

A

The aldehyde group in glucose is not freely available due to its predominant cyclic structure.

21
Q

What does the pentaacetate of glucose not reacting with hydroxylamine indicate?

A

It indicates the absence of a free –CHO (aldehyde) group, confirming glucose exists in a protected cyclic form.

22
Q

What are the two crystalline forms of glucose?

A

α-glucose and β-glucose.

23
Q

How is α-glucose obtained?

A

By crystallization from a concentrated glucose solution at 303 K (melting point: 419 K).

24
Q

How is β-glucose obtained?

A

By crystallization from a hot, saturated aqueous solution at 371 K (melting point: 423 K).

25
Front
Back
26
Why can't the open-chain structure explain glucose's behavior?
Because glucose forms a cyclic hemiacetal structure by the addition of an —OH group to the —CHO group.
27
Which hydroxyl group is involved in glucose's ring formation?
The —OH group at C-5.
28
What happens to the —CHO group in glucose upon cyclization?
It is converted into a hemiacetal, eliminating the free aldehyde group.
29
What are anomers?
Isomers that differ in the configuration of the hydroxyl group at the anomeric carbon (C1).
30
What are the two cyclic forms of glucose called?
α-form and β-form.
31
Why is the six-membered ring structure of glucose called pyranose?
Because it resembles pyran, a six-membered ring with one oxygen atom.
32
What is the correct representation of glucose's cyclic structure?
The Haworth structure.
33
What is the anomeric carbon in glucose?
The carbon that was part of the aldehyde group (C1) before cyclization.
34
How do α-glucose and β-glucose differ?
In α-glucose, the —OH group at C1 is down (opposite to CH₂OH at C5), while in β-glucose, it is up (same side as CH₂OH at C5).
35
What type of reaction leads to the formation of glucose's cyclic structure?
Intramolecular hemiacetal formation.
36
What is the main driving force for glucose to adopt a cyclic structure?
The stability of the six-membered ring and the formation of a stable hemiacetal.
37
In solution, how do the cyclic and open-chain forms of glucose behave?
They exist in equilibrium, interconverting through mutarotation.
38
What is mutarotation?
The process by which α- and β-forms of glucose interconvert in aqueous solution through the open-chain form.
39
What is pyran?
A six-membered ring compound with one oxygen and five carbon atoms.
40
Why is the Haworth structure preferred for representing glucose?
It provides a clearer depiction of the spatial arrangement of atoms in the cyclic form.
41
What kind of isomerism do α- and β-glucose exhibit?
Anomerism, a type of stereoisomerism.