Genetic code/protein synthesis Flashcards

1
Q

How many bases code for one amino acid?

A

3

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2
Q

How many possible amino acids can the genetic code make?

A

64

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3
Q

Aug codes for?

A

Methionine and it is a start codon

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4
Q

What are the three stop codons?

A

UAA, UGA and UAG

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5
Q

Ugg codes for what amino acid?

A

trp

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6
Q

The first column is green which means they are?

A

hydrophobic

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7
Q

The yellow amino acids have what quality?

A

they are polar, have H bonds

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8
Q

the pink amino acids are?

A

charged

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9
Q

What is the most common amino acid for e. coli?

A

leucine at CUG

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10
Q

what is the most common amino acid for humans?

A

leucine for CUG

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11
Q

how many of the 64 codons make amino acids?

A

61

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12
Q

All living systems do not use the same genetic code and it is not universal.

A

FALSE IT IS UNIVERSAL

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13
Q

mitocondrial genomes show some differences, for example ____ specifies TRp rather than stop

A

UGA

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14
Q

Are prokaryotic or eukaryotic ribosomes bigger?

A

eukaryotic

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15
Q

What is found in the gap between the 50S and the 30S of the ribosome in E. coli?

A

mRNA is found

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16
Q

initiation in protein synthesis involves….?

A

binding of mRNA to the small and large ribosomal
subunits, and binding of an initiator tRNA

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17
Q

Elongation in protein synthesis involves….?

A

the formation of all peptide bonds of the growing
polypeptide chain

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18
Q

Elongation in protein synthesis involves….?

A

the formation of all peptide bonds of the growing
polypeptide chain

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19
Q

Termination in protein synthesis occurs when….?

A

Occurs when a “stop” codon is reached along the mRNA, which leads to the release of the completed polypeptide.

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20
Q

In protein synthesis, a new aminoacyl-tRNA binds to the _________ site and then the
growing polypeptide at the P (peptidyl) site is transferred to the A site with the formation
of a peptide bond.

A

A (acceptor)

21
Q

is this in eukaryotes or prokaryotes?
Small subunit (30S)
16S rRNA
21 proteins
60% RNA/ 40% protein

A

prokaryotes

22
Q

is this in eukaryotes or prokaryotes?
Large subunit (50S)
23S and 5S rRNAs
31 proteins
70% RNA

A

prokaryotes

23
Q

is this in eukaryotes or prokaryotes?

Small subunits (40S)
18S rRNA
33 proteins
50% RNA/ 50% protein

A

eukaryotic

24
Q

is this in eukaryotes or prokaryotes?
Large subunits (60S)
28S, 5.8S, and 5S rRNAs
49 proteins
65% RNA/ 35% protein

25
Rat liver ribosomes (80S) have a mass that is _____ times that of E. coli ribosomes
1.7
26
Protein synthesis has three phases: initiation, elongation, and termination.
true
27
what is initiation in protein synthesis
Involves binding of mRNA to the small and large ribosomal subunits, and then binding of an initiator tRNA
28
what is elongation in protein synthesis
Includes the formation of all peptide bonds of the growing polypeptide chain
29
what does termination do in protein synthesis
Occurs when a "stop" codon is reached along the mRNA
30
what 5 factors are needed for peptide chain initiation.
(a) mRNA (b) 30S and 50S ribosomal subunits (c) initiation factors (d) GTP (e) initiator tRNA (f-Met-tRNA)
31
what is needed for elongation in protein synthesis
(a) mRNA/ribosome/peptidyl-tRNA complex (b) aminoacyl-tRNAs (c) elongation factors (d) GTP
32
For peptide chain termination, the components include:
(a) release factors (b) GTP
33
Initiation begins with the binding of _____ and the initiator _____ (f-Met-tRNA) to the 30S ribosomal subunit. Initiation factors IF-1, IF-3, IF-2, and GTP are also required
mRNA and tRNA
34
The initiator tRNA binds to the _____ _____ on the 30S subunit, and the 50S subunit joins the 30S subunit.
P site
35
The 70S initiation complex consists of the 30S and 50S ribosomal subunits, mRNA, and the initiator tRNA bound to the P site. The mRNA and the tRNA are in the ____ _________ the two subunits
gap between
36
the _______ blocks it so no more amino acids can be added.
formyl group
37
in elongation in protein synthesis: Binding of a new aminoacyl-tRNA to the A site is brought about by elongation factor EF-___.
Tu
38
Elongation factor EF-__ recycles EF-Tu
Ts
39
in elongation______ __________ is the step that forms the peptide bond between the new amino acid and the growing polypeptide chain
Peptidyl transfer
40
in elongation: The peptidyl transferase activity is not due to a protein enzyme, but to an ______ ________ activity of the “peptidyl transferase center” of the 23S rRNA of the 50S subunit.
RNA enzyme
41
RNA enzymes are known as _________
“ribozymes”
42
in elongation: Translocation of the peptide chain back to the P site is brought about by elongation factor EF-_
G
43
In termination: The binding of ______ _____ to the A site transforms the ribosomal peptidyl transferase, that forms the peptide bond between amino acids, into a ______
release factors and hydrolase
44
in termination: The peptidyl transferase then hydrolyzes the bond linking the polypeptide to its ______ _______, thereby releasing the polypeptide
tRNA carrier
45
in termination:The presence of a _________ ______ at the A site brings about the binding of release factor RF-1 or RF-2 plus RF-3
stop codon (UAA, UAG, or UGA)
46
in termination: The binding of the release factors transforms the ribosomal ______ _______ into a hydrolase that breaks the bond between the polypeptide and its tRNA carrier
peptidyl transferase
47
The polypeptide is released, and the ____ ribosome dissociates from the mRNA
70S
48
The proper folding of newly synthesized _______in the cell may require molecular __________ such as Hsp70 and GroES/GroEL
polypeptides and chaperones