GCSE - test for ions Flashcards
Test for sulphate ions
Bacl2
Pos - formes a white ppt
Test for hydroxide ions
Test if alkaline
Pos - red litmus to blue
Test for carbonate ions
Hcl
Pos - Effifecents of co2 / turns cloudy
Test for group 2 ions
Flame test
Ca (II) - brick red
Sr (II) - red
Ba (II) - pale green
Test for ammonia ions
Ammonia released
So use red litmus paper or add naoh
Pos - Red paper to blue paper
Test fro metal hydroxides
Naoh is added
Pos - formes a ppt
test for group 2 ions (3 test)
Ammonium solution
mg ions - white ppt (mg(OH)2)
ca ions - no change observed
sr ions - no change observed
Ba - no change observed
Excess NaOH
mg ions - whute ppt
ca ions - white ppt of the hydroxide
sr ions - slightley white ppt of the hxdroxide
ba ions - no change oberved
excess sulfuric acid
mg ions - colourless solution
ca ions - slightly white ppt CaSO4
sr ions - white ppt - SrSO4
ba ions - BaSO4
test for hysroxide ions ad halide ions
halode ions - nitric acid, silver nitrate cl- white , br - cream, i- yellow
to double tes - add dilute ammon, cl- disolves, br - disolves if conc, i - just doesnt
hydroxide ions - red litmus paper - turns blue
sample must be aq to test
test for ammonia ions
warm with NaOH
test fumes produced with red litmus paper - changes to blue in presence of ammonia gas
NH4+ (aq) + OH- (aq) → NH3 (g) + H2O (l)
test for carbonate ions
small amount (around 1 cm3) of dilute hydrochloric acid should be added to a test tube
An equal amount of sodium carbonate solution should then be added to the test tube
As soon as the sodium carbonate solution is added, a bung with a delivery tube should be attached to the test tube
The delivery tube should transfer the gas which is formed into a different test tube which contains a small amount of limewater (calcium hydroxide solution)
Carbonate ions will react with hydrogen ions from the acid to produce carbon dioxide gas
Carbon dioxide gas will turn the limewater milky
test for sulphate ions
sulphate ions SO4 2- add barium chloride - white ppt firmed of BaSO4
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)