GC - Ch 4 Flashcards
2H2(g) + O2(g) -> 2H2O(g). This is an example of a combination reaction. describe what a combination reaction is.
This is an example of 2 or more molecules reacting to create a single molecule which are combination reactions.
What are the expected results of a decomposition reaction?
Decomposition reactions are chemical reactions in which a single molecule breaks down to create 2/more products. Decomposition reactions tend to be seen with the use of high frequency radiation OR electrophoresis
Contrast combustion reactions from decomposition reactions.
Decomposition reactions are reactions in which a molecule breaks down to create multiple products.
Combustion reactions are those in which oxygen is used to make oxides. These types of reactions are usually seen with the use of a hydrogen carbon fuel along with oxygen. Products typically formed always include H2O and CO2
The chemical reaction that typically requires O2 A. Incorporation reaction B. Combination reaction C. Decomposition Reaction D. Combination Reaction
D. O2 + HC fuels can also be sulfur or sugar based (because these have HC in them!)
Assess this chemical reaction: Cu(s) + Ah(NO3)2(aq) -> Aq(s) + CuNO3. defend what generic type of reaction this is in terms of atomic reaction
A single displacement reaction. You can see that Cu has replaced Ag in its bond to NO3.
Note: these reactions do tend to be further classified as redox reactions as these tend to demonstrate electron movement.
What is a metathesis reaction? describe the physical states of the products in this type of reaction?
This is a double replacement reaction where 2 compounds swap places and bind to the other’s previous molecules
Products tend to be removed from solution as a precipitate or gas. these products can also remain as electrolytes (aqueous) in solution as well
Contrast neutralization reactions from metathesis reactions.
Neutralization reactions are a special type of metathesis reactions. These types of reactions are those that specifically involve an acid or base! Where in the reaction, both cancel one another out in acidity/basicity and create a more neutral solution. Products of these types of reactions tend to be a salt and water.
Unlike the typical products from double replacement, how are products of neutralization different
Double replacement products - precipitate or leave the system as a gas.
Neutralization produces salt and water. This change is not often visible and requires an indicator!!
Describe in words what occurs when Zn(NO3)2 is dissolved in (NH4)2S
The likely product of this reaction is a double replacement where Zn-S and NH4NO3
In the reaction of Zn + AgCl, what are the products, conditions, and reaction type
Appears to be a single replacement. More specifically a prod: ZnCl + Ag (aq)
Contrast the different ways how compounds can be represented in general chemistry, organic, and inorganic chemistry
General chemistry - VESPR and Lewis Dot structure
Organic chemistry - Structural formulas - these are skeletal representation
Inorganic chemistry - Constituent atoms with NO bonds Ex: C6H12O6
Pure samples of a given compound will contain the same elements in a given identical mass ratio A. Percent composition B. Law of constant composition C. Law of conservation D. Law of conservation of mass
B. This law is defined by the question stem. Ex: Every sample of water has 2 atoms of every O atom. Therefore for every H gram of H, there are 8 grams of O. This is because H molar mass is 1g/mol. There are 2 atoms therefore there is 2 g/mol of H for every mole of O (16g/mol) therefore the ratio of H:O => 2:16
T/F - based on the law of constant composition, pure samples of a given compound will contain the same elements in an identical density ratio anywhere else in the universe
False. Law of constant composition defines the mass ratio is conserved, not that density ratios are conserved. Density is affected by gravity and therefore changes with different locations
Compare and contrast empirical and molecular formulas of compounds
Sometimes both can be one and the same for a molecule. But both are ways to represent the formula of compound. Ex: H2O
Empirical formula - this is the simplest whole-number ratio of the elements in the compound Ex: Benzene CH
Molecular formula - this is the formula which represents all of the atoms in the compound. this should be the multiple of the molecule’s empirical formula. Benzene: C6H6
The empirical formula is indicative of CH2O
A monosaccharide!
there are many monosaccharides and many of them have this empirical formula as well! Fructose, glucose, and galactose
What is the percent composition?
This quantity looks at what percent of our compound is made up of a certain element
therefore this is a mass evaluation
% = (mass in element in formula/molar mass) 100%
T/F - Percent composition can only be found based off the molecular formula and not empirical
false! Both can be used to find the percent composition as both demonstrate ratios of different elements (this is percent composition)
What is the empirical and molecular formula of a compound that contains 40.9% C, 4.58% H, and 54.52% O and has a molar mass of 264 g/mol
Just as you are able to find % composition from an empirical or molecular formula, you can use these %s to find the molecular and empirical formula too!!
S1: Find the moles each element has out of _ grams. this _ tends to be 100 as this is the easiest to work with. This step uses their % and molar mass on PT to dtm moles
C moles: 40.9g/12g/mol = 3.4 mole
H moles = 0.05g/1g/mol = 4.6 mole
O moles = 54.52g/16g/mol = 3.4 mole
S2: Using the smallest moles to divide all the other moles, this creates whole number ratios that we can all work with
C = 3.4/3.4 = 1
H = 4.6/3/4 = 1.33
O = 3.4/3.4 = 1
S3: Create an empirical formula:
C1H1.33O1 (3) => C3H4O3
S4: Find the molecular formula: Molar mass/empirical formula mass => (264g/mol)/88g = 3. Use this value to multiply this to your empirical formula to get your molecular formula. C3H4O3(3) => C9H12O9
OR
S1: multiple molar mass to the % then the divid the value by molar mass - this gives you the moles of each in the molecular formula and then simplify this molecular formula until you reach the empirical formula.
C moles = [(0.409)(2644g)] / 12g/mol = 9mol
H moles = (0.0458)(264g)/ 19mol = 12mol
etc..
Find the percent composition (by mass) of Na, Cr, and O in Sodium Carbonate (Na2CO3)
Na = 14g(2) = 28g
C = 12g
O = 16g(3) = 48g
Total 88g
Na% = 28/88 = 0.318 C% = 12/88 = 0.136 O% = 48/88 = 0.545
Experimental data from the combustion of an unknown compound indicates that it is 28.5% iron, 24.0% sulfur, and 49.7% oxygen by mass. What is its empirical formula?
Assume that there are 100g of sample, and each %composition represents a percentage of the 100g. Fe = 28.5g, S = 24g, and O = 49.7g
Next divide each number of grams by the atomic weight to determine the number of moles Fe = 28.5g / (55.8g/mol) = 0.5/0.5 = 1 S = 24g/(32g/mol) = 0.7/0.5 = 1.5 O = 48.6g/(16g/mol) = 3/0.5 = 6 => Fe1S1.5O6 (2) = Fe2S3O12
What is the definition of compounds?
This is defined as pure substance composed of 2/more elements in a fixed proportion.
Compounds can be broke down by chemical means to produce their constituent elements or other compounds
Contrast atomic weight from molecular weight
Atomic weight - this is a misnomer because it is actually a weighted average of the masses of the naturally occurring isotopes of an element.
Molecular weight - is simply the sum of the atomic weights of all the atoms in a molecule, and its units are atomic mass units (amu) per molecule
Why is it hard to define ionic compounds as true molecules? Use NaCl in your explanation
These are hard to define because of the oppositely charged ions arrange themselves in solid states.
For instance, NaCl are coordinated in lattices where Cl- ions surround the Na+ ions. This makes it rather difficult to clearly define NaCl - this is why we use formula units
What are formula units? Why are they used?
These represent the empirical formula of the compound. The use of this quantity is because ionic compounds are hard to define as a molecules (combination of 2/more atoms held together by COVALENT bonds)
What is the purpose of formula weight?
This is the sum of atomic weights of all atoms appearing in a given chemical formula. This formula weight is important for substances that do not consist of indv molecules (Ex: Ionic compound NaCl)
To calculate:
1. multiply the atomic weight of each element in a formula by the number of atoms of that element present in the formula
3. and then add all these products together
How many moles are in 9.53g MgCl2?
Molar mass: Mg = 24g/mol, Cl = 35x2 = 70g/mol. Total molar mass = 94g/mol
9.53g MgCl2 (mole/94g) = 0.101 mole
What is the molecular weight of SOCl2?
Molecular weight = sum of molar mass S = 32g/mol O = 16g/mol Cl = 35 x 2 = 70g/mol = 118g/mol
What is the gram equivalent (GEW) of sulfuric acid?
S1: Molar mass of H2SO4 S = 32g/mol H = 1x2 = 2g/mol O = 16x4 = 64g/mol Molar mass = 98g/mol
S2: Id the equivalents (n) - this is the particles of interest produced or consumed per molecule. In this case, equivalents are H+ and this value = 2
S3: Calculate the gram equivalent weight = molar mass/n
98/2 = 49g/mol of H+