G841 Legacy Papers Flashcards
State why the equation F=ma cannot be applied to particles travelling at speeds very close to the speed of light
the MASS of particles increases (at its speed gets closer to the speed of light)
Explain why we cannot use the equation v=u+at to predict the velocity of a car at a later time even when the forward force is constant
The drag force changes with speed/ acceleration is not constant
Describe how Global Positioning System (GPS) is used to locate the position of a car on the Earth’s surface
- Several SATELLITES used
- Distance from (each) satellite is determined
- Position/distance is determined using c/speed of e.m waves and delay time
- Trilateration is used to locate the position of the car
How does greater speed affect braking distance?
distance is directly proportional to speed squared
How does a greater mass increase braking distance?
distance is directly proportional to mass
How do tyres/brakes affect braking distance?
Worn brakes/tyres implied less friction therefore greater distance
How do road conditions affect braking distances?
Wet/slippery/icy roads mean less friction therefore greater distance
Explain why the tension in a cable is different when the object is accelerating upwards
The tension would be greater than the weight
Explanation in terms of resultant/net force=ma
State why the magnitude of the resuotant velocirt of the balloon is not the sum of the speeds of the balloon and the wind
Velocity is a vector so it also has direction
A student investigates wires of the same material and same length. A is thicker than B. Explain which of these wires has a greater value of force constant
For the SAME force, A has a smaller extension
A has the greater force constant
Describe the energy changes of a spring attached to a block as it falls to the ground (and touches it)
GPE AND KE OF THE BLOCK DECREASES (not the spring as it has negligible mass)
STRAIN/EPE in spring increases (GPE and KE converted to EPE)
when touches ground, no KE, spring has MAXIMUM STRAIN/EPE
Explain the motion of a skydiver immediately after jumping
Only force is weight
Drag is 0
Net force=weight
Acceleration=g/9.81
Explain the motion of a skydiver at a time before terminal velocity is reached
Drag increases with speed (d prop. to s^2)
Net force decreases, weight>drag
Acceleration less than g
Explain the motion of the skydiver at terminal velocity
Weight=drag, net force=0
Acceleration=0, constant velocity
At terminal velocity, falls at constant speed. Kinetic energy does not change even though decreases in GPE. State what happens to this loss of GPE
transferred to heat/thermal energy