FoM:L4 - The genetic code and protein synthesis Flashcards
1
Q
How does DNA work as the genetic code?
A
- non overlapping
- degenerate
- triplets
- universal
- stop/start codons
2
Q
What is the open reading frame?
A
area between initiator and stop codon
3
Q
What is tRNA?
A
transfer RNA
- formed from longer precursors
- modified bases
- cloverleaf structure
- D, T arms and anticodon loop
4
Q
What is wobble?
A
- fewer number of tRNAs than number of codons
- 1 tRNA binds to more than 1 codon
- 3rd base in anticodon can base pair unusually
5
Q
What are modified bases?
A
- in tRNA
- non-standard nucleotides
- covalent modification after transcription
6
Q
How are amino acids activated?
A
- aminoacyl-tRNA synthetases
- ensures the correct amino acid is coupled to the correct tRNA
- requires ATP, E stored in ester bond between tRNA and aa -> E for peptide bond
7
Q
What are the 3 steps of translation?
A
1) initiation: formation of initiation complex
2) elongation: addition of further aas
3) termination: recognition of a stop codon
8
Q
What us rRNA?
A
- overall structure
- ability to position tRNAs on mRNAs
- catalytic activity
9
Q
What 3 sites are in a ribosome?
A
- aminoacyl tRNA site
- peptidyl tRNA
- exit
10
Q
Outline initiation in translation
A
- initiation factor binds (met-tRNAmet)
- complex with small subunit binds to mRNA
- proceed until AUG region
- large ribosomal subunit binds with initiator aminoacyl tRNA in P site
11
Q
Outline elongation in translation
A
- aminoacyl tRNAs picked up by elongation factors with GTP, enter A site
- anticodon is matched against codon (if not its thrown out)
- peptidyl synthetase activity links aa to polypeptide
- empty tRNA in P site, new petidyl-tRNA in A site
- moves forward 1 codon, empty tRNA moves to E, peptidyl-tRNA moves to P (GTP and elongation factor)
12
Q
Outline termination in translation
A
- stop codon with no corresponding tRNA
- release factor binds to A
- release factor releases polypeptide
- ribosome dissociates
13
Q
A