Fluorescence Microscopy Flashcards
Using the Jablonski diagram and the principles of the Stokes shift, explain fluorescence.
Fluorescence is a natural property of certain molecules, where they emit light of certain wavelength after absorbing light energy of a lower wavelength (and thus higher frequency and energy). This emitted light can be observed using fluorescence microscopy. The jablonski dg shows the ground state of electrons (S0), and as it absorbs the excitation (light) energy, the electrons are excited to a higher level temporarily. It loses some energy (in forms other than light), known as the non-radiative energy, before falling back into the ground state. As the electron falls back into ground state, the energy it has is released in the form of light, but since some energy is lost, the light has a lower frequency (and thus higher wavelength). On microscopy, this shows up as a different colour of higher wavelength (and the difference in wavelength is the Stokes shift).
What is the Stokes shift?
It is the distance between the peaks of the absorbance and the emission spectrum of the light wavelength
What is a common structure of fluorescent molecules (fluorophores)?
Aromatic rings
Outline the parts of the fluorescent microscope.
Light source (Arc lamp): high intensity, short wavelength
Excitation diaphragm: controls the amount of light passing through
Excitation filter: only allows light of a certain wavelength through, making it monochromatic
dichroic filter: allows light to pass through to the Objective, but reflects the returning light towards the emission filter and Ocular
Objective
Emission Filter: only allows light of certain wavelength through
Ocular
Outline the common problems and challenges experienced in fluorescence MS.
- Bleedthrough: when a fluorescent molecule emits with a broad emission peak (or when there is broad collection parameters), the peak can cross over into another peak, and 1 fluorophore can be picked up by 2 channels.
- Blur: out-of-focus light decreases resolution
- Bleaching: excited fluorophores react to become non-fluorescent
- Phototoxicity: light can harm cells
- Background/autofluorescence: intrinsic fluorescence of cells
How do you counter fluorescence bleedthrough?
By labelling with only 1 fluorophore and check to see how bad the bleedthrough is in the 2nd channel
Define photobleaching and outline the methods to counter this effect.
It is the irreversible destruction of an excited fluorophore.
Counter by: (think how to minimise damage by the light)
Scan for shorter time
Use high resolution, ie high NA (numerical aperture) objective: high NA allows more focused light, therefore smaller area illuminated leading to higher focus and resolution, and therefore less damage
Use wide emission filters (filters out more light?)
Reduce excitation intensity
Use anti-fade reagents (not compatible with viable cells)
Outline the 4 approaches in removing Blurs
- Optically: mechanically, basically using better equipment: confocal, 2-photon fluorescence excitation etc
- Computationally: using computer to process stack; Deconvolution (using mathematics)
- Hybrid: Require both approach
- Combination: combine optical and computational approaches
Explain the differences between a normal (wide-field) fluorescence ms and a confocal ms by contrasting the parts on the equipments.
Wide-field fluorescence ms floods the entire specimen evenly with the light source, and all parts of the specimen are excited, causing fluorescence (FL), and the resulting FL picked up by the photodetector/camera includes a large unfocused background. However, the confocal ms uses a laser (inst of arc lamp), an Excitation Pinhole instead of a Diaphragm to create a point illumination, has an Emission Pinhole along with the filter (only filter in widefield), to filter out non-specific wavelengths, and has a PMT instead of an Ocular. Therefore only FL close to the focal plane can be detected, and the optical resolution is therefore high. To create a 3D image, it needs to take various sections (optical sectioning). The downside is that it blocks out much of the light at the pinhole, therefore FL signal is decreased, therefore longer exposure time needed.
List the uses of fluorophores.
Conjugated Ab Organelle labelling DNA/RNA labelling and quantification Physiological measurements Analysis of fast dynamic processes Molecular interaction studies (FRET)
What is the excitation and emission spectra of the GFP?
Excitation = 395 and 470 nm Emission = 509nm (peak)
Explain FRAP.
Fluorescence Recovery After Photobleaching.
It’s a technique that measures cellular kinetics, ie the rate at which cellular mechanisms work.
It uses a laser to bleach an area of the cell, and measures the rate at which fluorescence recurs (due to redistribution of fluorescent molecules). Measures the diffusion coefficient and the mobile fraction
Explain the concept of FRET.
Fluorescence/Forster Resonance Energy Transfer.
It’s a method used to analyse molecular interactions.
Requires that the molecules to be very close together 10-100 Angstroms.
The absorbance peak of acceptor must match emission peak of donor, ie there has to be significance spectral overlap
We basically use specific wavelength light to excite donor molecule. If there is interaction between donor and acceptor molecules, the emission energy of the donor will be absorbed by the acceptor, and in turn emitted as a higher wavelength (donor transfers non-radiatively to the acceptor). If this wavelength light is seen, then we can confirm interaction between the molecules.
Outline the uses of confocal/2-photon microscopy in neuroscience
Axon pathfinding in embryogenesis and regeneration
Signal transduction in growing axons
Analysis of brain cytoarchitecture
Intravital imaging of neuronal signalling
Explain the principle of Two-photon Excitation.
Using normal excitation wavelengths (high intensity, low wavelength) eg UV, it may cause damage to live cells. We therefore use Two-photon excitation to create the same effect, by using 2 photons of half the excitation energy needed (therefore double the wavelength). We illuminate sample with light of twice the wavelength, and only if the two photons are absorbed simultaneously will it excite the fluorophore. Emission of 2nd harmonic is at half the wavelength of excitation.