Fluids- More Pipe Losses Flashcards

1
Q

Major losses

A

A pressure (or head) loss due to frictional losses at the pipe walls

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2
Q

Minor losses

A

Due to an interruption of the smooth flow of fluid

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3
Q

Examples of causes of minor losses

A

Valves, bends, elbows, inlets, exits, enlargements and contractions. Basically pipe components.

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4
Q

What to do when finding a flow rate down a pipe

A

Can’t calculate Re so assume it is 10^5. Read off from Moody diagram in normal way to get f. Rearrange equation for pressure loss (given) to find V. Based on this V calculate the Re it suggests. If the two values of are are within 10%of each other, the assumption was right and go on to calculate volumetric flow rate. If not, second Re calculated becomes new assumption and do whole thing again.

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5
Q

Why do pipe components cause minor losses?

A

They interrupt the smooth flow of fluid and cause flow separation and induce mixing

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6
Q

What is the symbol for minor loss coefficient?

A

KL
Where L is subscript
It is a function of geometry

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7
Q

Formula for minor loss

A

Ploss=0.5KLρV^2

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8
Q

Formula for KL for sudden expansion

A

KL=(1-A1/A2)^2
Where A2>A1
The velocity used in the minor loss formula is the initial velocity, V1

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9
Q

What is the angle φ for a diffuser?

A

The inclusive angle between the walls (<180)

Equal to twice the angle one wall makes with the horizontal

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10
Q

What does KL depend on for a diffuser?

A

The angle,φ. The area ratio d/D where D>d.
Greater φ means more pressure loss so greater KL
Greater area ratio lower KL

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11
Q

What happens during sudden contraction of a fluid?

A

The flow leaves the large pipe at an angle and doesn’t fill the small pipe completely. This narrowing of the flow path is known as the vena contracta.

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12
Q

What does KL depend on for sudden contraction?

A

Area ratio d2/d1
As this ratio increases, value of KL decreases
When ratio is about 0, KL=0.5
When ratio is about 1, KL=0

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13
Q

What affects KL for a bend?

A

The angle the bend goes through and the sharpness of the bend. Value for KL increases with both

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14
Q

How does KL vary for valves open and partially closed?

A

Large head loss in partially closed valve due to irreversible deceleration, flow separation and mixing of high-velocity fluid coming from the narrow valve passage. However the head loss through a fully open valve is quite small.

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15
Q

How do KL values for different components in series combine when diameter of pipe remains constant?

A

They add up to get overall KL value

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16
Q

Formula for major losses in terms of dynamic pressure

A

hloss=f(l/d)(V^2/2g)

The V^2/2g term is dynamic pressure

17
Q

Formula for total head losses when diameter is constant

A

(fL/D+ΣKL)(V^2/2g)