FINALS 25 SET A

Question 1

Conversion. 127.2310 to binary is?
a. 111111. 11100
b. 111111. 00111
c. 1111111.11100
d. 1111111.00111

Answer 1

d. 1111111.00111

Question 2

Conversion: 47.1248 to base 9 is?
a. 43.14250
b. 43.05241
c. 44.14250
d. 44.05241

Answer 2

a. 43.14250

Question 3

Conversion: BAD.0011 in base 8 is?
a. 5566.104000
b. 5655.104000
c. 5655.000104
d. 5566.000104

Answer 3

c. 5655.000104

Question 4

The 9’s complement of 546700 is ______.
a. 453299
b. 453300
c. 992345
d. 002345

Answer 4

a. 453299

Question 5

The 2’s complement of the BCD (8421) code of -6 is?
a. 1011
b. 1010
c. 1100
d. 0101

Answer 5

b. 1010

Question 6

It is used in applications to eliminate the errors of ambiguity during the transition of binary numbers.
a. 2s complement
b. 1s complement
c. 2-4-2-1 code
d. Gray code

Answer 6

d. Gray code

Question 7

The 2-4-2-1 code of 7 is ______.
a. 1100
b. 1101
c. 1110
d. 0001

Answer 7

b. 1101

Question 8

A logic gate that outputs logic 1 when the two inputs are different.
a. XOR
b. XNOR
c. NAND
d. AND

Answer 8

a. XOR

Question 9

A logic gate that outputs logic 1 when all inputs are logic 1.
a. OR
b. AND
c. XOR
d. NAND

Answer 9

b. AND

Question 10

These are used in digital computers to simplify the subtraction operation and for logical manipulation.
a. Gray code
b. Complementation
c. 2-4-2-1 code
d. Binary codes

Answer 10

b. Complementation

Question 11

(-7) + 15 is equal to?
a. 11000
b. 0000 1000
c. 1000 1000
d. 1100 0100

Answer 11

b. 0000 1000

Question 12

(-12) + 15 is equal to?
a. 0000 0011
b. 0000 1100
c. 1000 0011
d. 1111 00 11

Answer 12

a. 0000 0011

Question 13

Using 10’s complement, subtract 83477 – 3474.
a. 199997
b. 19997
c. 80003
d. 180003

Answer 13

c. 80003

Question 14

Figure 1
What is the algebra of L?
a. x + y + z
b. xyz
c. (x+y+z)(xyz)
d. xy + z

Answer 14

b. xyz

Question 15

Figure 1
What is the algebra of O?
a. (xyz)(a)
b. (x+y+z)+(a’)
c. (xyz)(a’)
d. (xyz)+(a’)

Answer 15

c. (xyz)(a’)

Question 16

Figure 1
What is the algebra of M?
a. ((xyz)(a’)) + (xyz)’(y)
b. ((xyza’) + (y) + (xyz))
c. ((xyza’) + (y)(xyz))
d. ((xyza’)(y)(xyz))

Answer 16

b. ((xyza’) + (y) + (xyz))

Question 17

Figure 1
What is the logic value of L?
a. 1
b. 0
c. 01
d. 10

Answer 17

b. 0

Question 18

Figure 1
What is the logic value of M?
a. 1
b. 0
c. 01
d. 10

Answer 18

b. 0

Question 19

Implement the expression: xy + yz using the universal NAND gate.
a. ((xy)(yz))’
b. ((x+y)’(y+z)’))
c. ((xy)’(yz)’))
d. ((xy)’(yz)’)’

Answer 19

d. ((xy)’(yz)’)’

Question 20

What is the equivalent boolean expression of xy + wyz using the universal NOR gate?
a. (((x’+y’)’ + (w’+y’+z’)’)’)’
b. (((x’+y’) + (w’+y’+z’))’)’
c. ((x’+y’)’ + (w’+y’+z’)’)’
d. (((x+y)’ + (w+y+z)’)’)’

Answer 20

a. (((x’+y’)’ + (w’+y’+z’)’)’)’

Question 21

Simplify the Boolean expression: xz’ + xyz + x’y’z
a. x + y + z
b. xy’ + xz + xy’z’
c. xyz + xy + xz’
d. xy + xz’ + x’y’z

Answer 21

d. xy + xz’ + x’y’z

Question 22

Simplify the Boolean expression: xy + x’z + yz
a. xz + x’z
b. xy + x’z
c. x’y + x’z
d. xy’ + x’z

Answer 22

b. xy + x’z

Question 23

Simplify the Boolean expression: xyz’ + x’yz + xyz + x’yz’
a. 0
b. 1
c. X
d. Y

Answer 23

d. Y

Question 24

Figure 2
Get the Boolean expression out of the given K-map.
a. x’y + xy + z
b. xy’ + xy + z
c. xy’ + x’y + z
d. xy’ + x’y + z

Answer 24

d. xy’ + x’y + z

Question 25

Figure 3
Get the Boolean expression out of the given K-map.
a. w + x + y + z
b. w’ + x’ + y’ + z
c. wx’ + w’y + x’y + xz’
d. wx’ + x’y + y’z + xz’

Answer 25

b. w’ + x’ + y’ + z