Final Flashcards

1
Q

Same side of double bond

A

Z

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2
Q

Opposite side of double bond

A

E

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3
Q

RCOOR

A

Ester

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4
Q

ROR

A

Ether

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5
Q

OCNH2

A

Amide

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6
Q

Formal charge

A

(# of valence e-) - (lone pairs + 1/2 bonds)

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7
Q

Aromaticity

A

4n + 2
Conjugated
+ and - count

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8
Q

What is the hybridization of the orbital containing the unshared e- on the nitrogen atom in pyridine?

A

sp2

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9
Q

Benzene hybridization

A

sp2

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10
Q

R-CH2

Carbon hybridization

A

sp3

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11
Q

Ketone carbon (dbl bonded to the O) hybridization

A

sp2

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12
Q

R-OH

O hybridization

A

sp3

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13
Q

Most stable heat of combustion

A

Highest kJ/CH2

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14
Q

Most stable carbocations

A

R-CH

+ on the carbon closest to the benzene ring

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15
Q

Near pH 7

A

NH3+ and O-

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16
Q

Strongest base

A

R–CH2NH2

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17
Q

Carboxylate strongest base

A

CH2CH2CH2COO-

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18
Q

Strongest to weakest acid

A

OH+>NH3+>OH>NH2

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19
Q

Most acidic to least acidic

A

1 ketone and 1 COOCH > ketone> COOCH > CH3CH3

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20
Q

Greater acidity of p-nitro phenol

A
  • on both NO2 O’s and + on N
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21
Q

Most acidic proton

A

OH

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22
Q

Smallest pKa

A

Least acidic H

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23
Q

Strongest to weakest acid

A

SOOH >SOOH > COOH

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24
Q

R-CH2CH3 –H2O/H+–>

A

Add OH to the same carbon CH2CH3 is on

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25
Q

R–CH3 –1.B2H6/2.H2O2, NaOH–>

A

CH3 up and OH is added one carbon down from CH3 pointing down

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26
Q

Hg(OAc)2, H2O followed by NaBH4

A

Adds an OH where a double bond was

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27
Q

HCl

A

Adds Cl to most substituted carbon

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28
Q

Nucleophile that adds an OH to a double bond

A

H2O

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29
Q

H2O, H2SO4/HgSO4

A

Creates a ketone on the carbon that had double bonds closest to the ring

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30
Q

Propene to Propanol

A

B2H6, followed by H2O2, NaOH

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31
Q

Adding Br2 to (E)-3-hexene

A

One meso compound

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32
Q

R-CH3 –1.Hg(OAC)2, H2O/2. NaBH4–>

A

OH added to same carbon as CH3

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33
Q

Furan —Br2/CH3OH–>

A

Adds OCH3 next to O and Br next to OCH3

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34
Q
  1. R-BH/2. H2O2, NaOH
A

Adds aldehyde at the very end of the double bond

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35
Q

R-C (triple bonded)CH –> R-Ketone

A

H20,H2SO4/ HgSO4

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36
Q

A compound with two double bonds + HCl + CL2

A

Cl on each of the double bonds

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37
Q

R-CH3 –HCl–>

A

Cl adds to the same carbon as CH3

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38
Q

Double bond in a ring —> Epoxide

A

RCO3H

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39
Q

Butene —CHCl3/(CH3)3COK–>

A

Dimethyl cyclopropane with the CH3’s pointing it two different directions and 2 Cl’s at the top

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40
Q

R-CH3 —Br2/H2O–>

A

CH3 and OH on one carbon (CH3 up OH down) and Br (up) one carbon down

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41
Q

Different compounds with the same molecular formula

42
Q

Isomers that have a different atom connectivity

A

Constitutional Isomers

43
Q

Isomers that have the same connectivity but differ in the arrangement of their atoms in space

A

Stereoisomers

44
Q

Stereoisomers that are nonsuperimposible mirror reflections of each other

A

Enatiomers

45
Q

Stereoisomers that are not mirror images of each other

A

Diastereomers (two molecules switched)

46
Q

A mixture of two enantiomers in equal concetrations

A

Racemic

Optically inactive

47
Q

compound is “superposable” on its mirror image (not to be confused with superimposable, as any two objects can be superimposed over one another regardless of whether they are the same.

48
Q

Nucleophile attacks carbon bound to electronegative atom

A

Substitution Reactions

49
Q

Nucleophile can be a base and react with acidic protons of alkyl substrates

A

Elimination

50
Q

! step
Bimolecular
Rate is 1st order
Inversion occrus

51
Q

2 steps
Ionization of alkyl substrate then reacts with nucleophile
Unimolecular
sp2 tetrahedral

52
Q

NuH + X-

53
Q

compound + NuH or compound + X-

54
Q

Primary
Strong (like OH-) or Weak base (like Cl-)
Good Nucleophile

55
Q

Primary
Strong Base (like OH-)
Non-nucleophilic bases

56
Q

Secondary

Strong (like OH-) or Weak Base (like Cl-)

57
Q
Secondary
Poor Nucleophile (like H2O or HOR)
A

Sn1/E1 (slow), in polar, protic solvents

58
Q
Tertiary
Strong base (like OH-)
59
Q
Tertiary
Weak base (like Cl-)
A

Sn1/E1 in polar, protic solvents

60
Q
Tertiary
Poor Nucleophile (like H2O or ROH)
A

Sn1/E1 in polar, protic solvents

61
Q

O-H and N-H Frequency

62
Q

C-H (sp3)

63
Q

C-H (sp2)

64
Q

C-H (sp)

65
Q

C (triple bond) C and C (triple bond) N

66
Q

C=O

67
Q

C=C, aromatic C-C

68
Q

Aromatic C-C

69
Q

atom with 4 bonds

70
Q

atom with 3 bonds

71
Q

atom with 2 bonds

72
Q

atom with 1 bond

73
Q

Carbocation stability

A

Tertiary > Secondary > Primary > Vinyl

74
Q

Ranking acids

A

EN > Distance from EN molecule> No EN molecule

75
Q

pH of 12

A

Deprotonates

76
Q

Acidity

A

HI>HBR, HCl, HF

77
Q

Larger atom

A

More nucleophilic

78
Q

Allylic and Benzylic halides undergo

A

Sn2 faster

79
Q

If catalyzed by acid, and nuc = primary amine

80
Q

If catalyzed by acid and nuc = secondary amine

A

C=C enamine

81
Q

Strong basic nuc like grignard or metal halides

A

1,2 addition

82
Q

Weak basic nut like R2CuLi

A

1,4 addition

83
Q

Stability of organic radicals

A

Allylic/Benzylic > tertiary alkyl > secondary alkyl > primary alkyl > methyl > vinylic/aryl

84
Q

Initiation

A

Generates radicals

Step 1

85
Q

Propagation

A

Radical reacts with stable molecule to produce a new radical

Step 2

86
Q

Termination

A

Destroys radicals and stops the reaction

Step 3

87
Q

Hydrogen atom count decreased

88
Q

Hydrogen atom count increased

89
Q

Oxidizing agents

A

CrO3, K2Cr2O7, K2CrO4, KMnO4
Chromium used under acidic conditions
Potassium Permanganate used under basic conditions

90
Q

Oxidize only to aldehyde state

A

CrO3-2 pyridine, PCC, PDC

91
Q

Cleavage

A

HIO4 by ozone

92
Q

CH3MgBr

A

Oxidizes C=O and turns OCH3 into OH

93
Q

Hg(OAc)2, NaBH4/NaOH

A

Combines two molecules removing the double bond and the H from the OH

94
Q

NH3/H2,Pt

A

Oxidizes C=O and adds NH2

95
Q

KOH, CH2=CHCH2Br, H20 NaOH/heat

A

breaks apart two fused rings leaving only one c=c behind and adds NH2

96
Q

SoCl2/heat, NH3, Br2/NaOH

A

reduces ketone and replaces OH with NH2

97
Q

R-C(OH)HCH3

A

yellow precipitate

98
Q

NO2

A

meta directing

99
Q

Most to least reactive with NH3

A

Cl > anhydride > ester >amide

100
Q

SoCl2

A

Turns carboxylic acid to anhydride

101
Q

-OD/D2O

A

replaces only the alpha hydrogens

102
Q

NaCN

A

1,4 Addition