final

Question 2

given A rod, a clay is hurled at equal velocities at 3 different positions from rods (one directly at the edge of the rod, pushing it into the axis, on at a closer radius from the bottom-up, on from further away from the top down. the mass of the rod is negligible to the system, angular momentum is conserved (no ext. torques)

Answer 2

the one from the bottom up,

mVr = (I + MR^2)omega final

we know rod is negligible
thus

mVr = (MR^2) omega(f)
V = rOmegaf
V/r = final rot. speed, thus the closer the radius the higher the rot. speed

Question 3

study mvr projectile stuff

Answer 3

plz plz plz plz

Question 4

a ladybug is standing on a spinning disk. if the ladybug is walking toward the center of the disk, does it exert a torque on the disk? (disk goes from 1 rot/2.5 seconds to 1 rot/2 seconds)

Answer 4

yes, if the speed changes there HAS to be a torque applied from the perspective of the disk, there is an external torque. Though, from the perspective of the SYSTEM, there is no external torque and momentum is conserved. if we know that the disk has an external torque, then we must also assume that the ladybug creates some form of friction torque in the perpendicular direction.

Question 5

with no masses present a see-saw is balanced with its center of mass at the fulctrum. a 10 kg mass is placed a certain distance from the fulcrum of a see-saw. what info is needed to determine how far from the fulcrum the 2nd mass must be to balance the see saw in equilibrium?

mass 1 on one side, mass 2 on the other side, closer than mass 1 and more massive

Answer 5

the mass of the 2nd mass and distance from fulcrum to the 10 kg mass