Fields Flashcards

1
Q

Similarities and Differences between Gravitational Fields and Electric Fields

A

Similarities:
- both have inverse-square laws
-

Differences:
- masses always attract, charges can both attract and repel

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2
Q

What is a Force Field?

A

A region in which a body experiences a non-contact force

e.g the gravitational field

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3
Q

Field Lines

A
  • field lines are lines of force
  • ## field line directions are presented based on the positive charge, meaning they emanate out of positive charges and inwards for negative charges
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4
Q

State Newton’s Law of Gravitation

A
  • The force of attraction between two point masses
  • is proportional to the product of the two masses
  • and inversely proportional to the square of the distances between them

F = GMm/r^2

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5
Q

What is g?

A

The strength of a gravitational field, g, is the force per unit mass in a small test mass placed in the field

and also the acceleration of a falling object when under freefall

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6
Q
A
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7
Q

What is Gravitational Potential Energy?

A
  • the energy of an object due to its position in a gravitation field
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8
Q

What is the Gravitational Potentialv

A

The work done per unit mass to move a small object from infinity to that point

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9
Q

Equipotentials

A
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10
Q

What is a Potential Gradient?

A
  • the potential gradient at a point in a gravitational field is the change of potential per metre at that point
  • potential gradient = V/r (for small distances of r)
  • gravitational field strength is the negative of the potential gradient
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11
Q
A
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12
Q

Escape Velocity (from a planet)

A
  • the escape velocity from a planet is the minimum velocity an object must be given to escape from the planet when projected vertically from the surface
  • if an object is projected at speed v

1/2mv^2 > ΔW
1/2mv^2 > GMm/R
so v^2 > 2GM/R
so escape v = (2GM/R)^1/2
g = GM/(R^2)
∴ Vesc = (2gR)^1/2

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13
Q

Why is the gravitational field strength linear from 0-R of the earths radius?

A

At the Earth’s center, g is zero. As the point goes away from the centre, the gravitational field strength increases in proportion to the distance.

where mass = density x volume
so enclosed mass = (4 /3)pir^3

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14
Q

Satellites

A
  • Any large mass that orbits a larger mass is a satellite e.g the moon is a natural satellite of the earth
  • Geostationary/Geosynchronous satellites orbit the earth directly above the equator
    • this is because it has a time period of exactly 24HRS so if it had the same time period as the earth’s rotation
      radius of orbit can be found r^3/T^2=GM/4π^2
  • Polar Orbits
    • low orbit
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15
Q
A
  • the force of gravitational attraction between each planet and the sun is the centripetal force that keeps the planet on its orbit
  • GM/r^2 = v^2/r where M is the mass of the sun
  • v^2 = GM/r
  • v = 2πr/T
  • (2πr)^2/T^2 = GM/r
    therefore
    r^3/T^2 = GM/4π^2

and because GM/4π^2 is the same for all planets then r^3/T^2 is the same for all of the planets

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16
Q
A

KE = 1/2 mv^2 = 1/2mx GM/r = GMm/2r
V = -GM/r
Ep = mV = - GMm/r

= -GMm/r + GMm/2r = -GMm/2r

E = -GMm/2r

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17
Q

What is the Electric Field Strength?

A
  • The force per unit charge on a positive test charge placed at that point
  • units NC^1
  • F= EQ
    where E is field strength, F is force and Q is charge
  • the electric field strength is a before in the same direction as the force on a positive test charge
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18
Q
A
  • uniform
  • parallel to each other
  • at right angles to the plates
  • from the positive plate to the negative plate
19
Q

The force in a small test charge in an electric field is…

A
  • In the same direction as the electric field if the charge is positive
  • In the opposite direction to the electric field if the charge is negative
20
Q

Why must a test charge need to very much less than 1 Coulomb?

A
  • this amount if charge would affect the charges that cause the field, and so it would alter the electric field and its field strength
21
Q
A
  • For a charged metal conductor, the charge on it is spread across its surface
  • the more concentrated the charge is on the surface, the greater the strength of the electric field above the surface
22
Q

Electric potential

A
  • The work done per unit positive charge on a positive test charge when it is moved from infinity to that position in the field

where V = EPE/Q

23
Q
A
  • Equipotentials are surfaces of constant potential
  • a test charge moving along an equipotential has constant potential energy
  • no work is done by the electric field on the test charge because the force due to the field is at right angles to the equipotentials
24
Q

Potential Gradients

A
  • the potential gradient at any position in an electric field is the change in potential per unit charge of distance in a given direction
  • the closer the equipotentials are the greater the potential gradient is (at right angles to the equipotentials)
  • the electric field strength is equal to the negative of the potential gradient
25
Q
A
  • The gravitational potential in a gravitational field is always negative because it’s attractive
  • the electric potential in the electric field near a point charge Q can be both positive or negative according to whether Q is a positive or negative charge
26
Q

What is the Motor Effect?

A
  • A current-carrying wire placed at a non-zero angle to the lines of force of an external magnetic field experiences a force due to the field
  • The force is perpendicular to the wire and to the lines of force
27
Q
A
  • the magnitude of the force depends on:
    • the current
    • strength of the magnetic field
    • the length of wire
  • the force is:
  • greatest when the wire is at right angles to the magnetic field
  • zero when the wire is parallel to the magnetic field
28
Q

Couple in a coil in a magnetic field

A
  • each wire experiences BIl where l is the length of each long side
  • each long side experience a horizontal force F = (BIl)n in the opposite directions at right angles to the field lines
  • the pair of forces acting on the long sides form a couple as they are not directed along the same line
  • the torque of the couple = Fd
29
Q
A
  • the beam follows a circular path because the direction of the force on each electron is perpendicular to the direction of motion of the electron (and field direction)
30
Q
A
  • The electrons moving along the current-carrying wire are pushed to one side by the force of the field
  • the electrons being confined to a wire cause the whole wire to move downwards
31
Q
A
  • the force of the magnetic field on a moving charged particle is at right angles to the direction of motion of the particle
  • No work is done by the magnetic field on the particle as the force always acts perpendicular to the velocity of the particle
  • the kinetic energy of a particle is unchanged by the magnetic field
  • the force causes a centripetal acceleration
    -m
32
Q

How can radius of curvature for a particle under a magnetic field be used to determine the particle

A

r = mv/BQ

  • the larger the radius the greater the mass of the particle
  • the smaller the charge the smaller the radius
33
Q

How can you increase the induced EMF of a wire?

A
  • move the wire faster
  • use a stronger magnet
  • make a wire into a coil
  • pushing the magnet in or out of the coil
34
Q

How to increase Efficiency of a transformer

A
  • thick copper wire to reduce resistance due to wire
  • EMF may be induced in the iron causing eddy currents which will resist the flow of charge and emit heat, laminate the layers to prevent it

-

36
Q

Len’s Law states

A
  • the direction of the induced current is always such as to oppose the change that causes the current
37
Q

Faraday again lawl

A
  • law of electromagnetic induction states that the induced emf in a circuit is equal to the rate of change of flux linkage through the circuit
38
Q

Loaded and Unloaded Motors

A
  • An unloaded motor will spin with a high speed
  • the rate of change of flux linkage is high so the induced back EMF will be high.
  • there is small potential difference between the back EMF and EMF causing the motor to spin
  • thus the resulting current is low
  • The speed is limited by resistive forces (bearing friction and air resistance)
  • little power used
39
Q

Loaded Motors

A
  • A loaded motor will spin with a low speed
  • the rate of change of flux linkage is low
  • induced back EMF will be low
  • there is a large potential between the back EMF and the EMF
  • causing the motor to spin and the resulting current is high
  • Power is transferred from the voltage source to mechanical power in the load and wasted heat due to resistance
40
Q

Len’s Law

A
  • The induced/Back EMF will always oppose or tend to oppose the flux change produced
41
Q
A
  • When a magnet i pushed in to a coil the induced EMF opposes the motion by producing a field which repels the magnet
  • when you remove the magnet from the coil the induced emf opposes this motion by producing a field that attracts the magnet
  • in both case work must be done to move the magnet
  • this work is what transfers energy to a component
42
Q

Coil Attached to Oscilloscope (update)

A
  • A magnet is dropped through a coil that is connected to an oscilloscope

in the case below:
the emf at A is smaller than the emf at C because the magnet will be moving faster ( because the magnet is being accelerated due to gravity), so more flux linkage cut

43
Q

Faraday’s Law

A
  • EMF is proportional to the rate of change of flux linkage