EXAM QS Flashcards

1
Q

is the experimental method valid?

2019 VCAA 5b

A
  • The method is valid as data is consistent for standard solutions of different concentrations
    made up from pure sucrose.
  • The conditions used in the HPLC were consistent across all the standards and the soft drink
    solution.
  • Peak areas for the standard solutions and the diluted soft drink sample were recorded at the
    same retention time (of sucrose).
  • The method is invalid because not enough points were established from zero glucose through
    to 0.80 g L–1 glucose.
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2
Q

fators that would limit the life of the zinc-cerium cell

VCAA 2018 7f

A

loss/breakdown/oxidation/corrosion of the Zn electrode
* side reactions at the electrodes
* electrolysis of water during recharging
* (-) 2H+
(aq) + 2e– → H2(g) ; (+) 2H2O(l) → O2(g) + 4H+
(aq) + 4e–
* significant temperature change
* build-up of gases around electrode.

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3
Q

which chemical analysis is most useful in determining whether a compound has a stereoisomer

VCAA 2019 MCQ12

A

NMR - peak area and splitting patterns are diff

misconception - chose infrared bc uv light causes clockwise /anticlockwise BUT infrared is infrared radiation

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4
Q

one factor that would limit life of ZINC cerium cell

2019 VCAA Q7f

A
  • corrosion of ZN electrode
  • side reactions at electrode
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5
Q

safety risk w chemical in experiment

2019 VCAA 9bi

A
  • products that form
  • hydrogen gas is flammable
  • ensure no ignition sources are present
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6
Q

state change to experimental design do they can achieve their aim of measuring current efficiency

2019 VCAA 9G

A
  • use higher or borader range of NaCl
  • hi8gher conc most likely to prouce chlrine gas
  • 2 diff oxidation reactions occurring
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7
Q

aspects of electrolysis experiment included in discussion section

2019 VCAA 9h

A

whether the data supports or refutes the aim/hypothesis
* comparison of expected to actual results
* analysis experimental design and errors
* relating to earlier work/theory (e.g. electrochemical series and its use in predicting electrode
half-equations).

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8
Q

potential safety hazards of MG-NA hybrid cell

2021 vcaa 2b

A
  • battery may overheat
  • Mg relatively reactive so may react in body
  • leakage of products/reactants
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9
Q

amylose and cellulose similarities and differences in structure

2021 vcaa 3e

A
  • glucose monomers
  • straight chain unbranched polmers
  • glycosidic links
  • difference: CH2Oh group in amulose remains on same side of polymer
  • in cellulose it alternates
  • alpha glucose for amylose and beta glucose for cellulose
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10
Q

explain why potassium bromide or potassium iodide could not replace KCL as electrolyte to produce KOH

A

KI as electrolyte would produce I2(s) which would contaminate the solution / react with OH-
 KBr as electrolyte would produce Br2(l) which would contaminate the solution / react with
OH-
 Using KCl leads to production of Cl2(g) which would bubble off from the solution

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11
Q

evaluate the env impact of reacting methane w water and the electrolysis of water

A

Method 1 – impact depends on the source of methane
 If the source of CH4 is biogas generated from waste, the environmental impact is low
because CO2 is a less harmful greenhouse gas than methane.
 If the source of methane is fossil-fuel-based (or high temperatures are generated using
fossil fuels) the environmental impact is significant because CO2 produced adds to overall
greenhouse gas levels.
Method 2 – impact depends on source of electrical energy

 If the electrical energy source is renewable (e.g. wind/solar/hydro), there is no
environmental impact because no CO2 is produced.
 If the electrical energy source is coal or gas, the environmental impact is significant
because CO2 produced during combustion of the fossil fuel adds to overall greenhouse
gas levels

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12
Q

reversible vs irreversible reactions

A

reversible reaction, there is continuous interconversion between the chemicals on either side of the reaction equation.
In anirreversible reaction, the reactants are converted to products, but the products cannot be converted back to reactants.

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13
Q

explain what happens when an enzyme catalyses the hydrolysis of a protein

A
  • enzyme allows access to active site for protein via lock and key
  • enzyme binds the protein (substrate) to the active site so the peptide links react with water(hydrolyses)
  • enzyme lowers Ea for hydrolysis of peptide links or acts as a catalyst for hydrolysis of peptide links
  • enzyme retains shape after reaction.
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14
Q

the oxidation of wich chemical is the primary carbohydrate source

A
  • glucose is oxidised
  • glycerol is hydrolysed to glucose first
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15
Q

calibration graphs

A
  • if there is a bump when heating stops but then it stabilises, you take the stabilised value as it means the calorimeter is insulated
  • the stirring makes the temp more even
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16
Q

semistructural formula

A
  • if there is a central carbon and four groups attached to it that aren’t hydrogens
  • write it as C (CH3)3Cl etc…
17
Q

energy efficiency

A
  • energy released in a 55% energy efficient calorimeter
  • means u have to divide by .55 to find the actual amount fo energy released by combustion
18
Q

determine whether same quanitty of gas is produced at each anode

2024 sample q6

A
  • no. electrons entering and exiting the cell are equal
  • the current/passage of electrons is consistent throutout the circuit
  • the mole of electrong flowing to each anode is equal
19
Q

use integration curves to verify a peak has 2 equivalent H

A
  • specify the ratio of the curves
  • integration curve is double the height etc….
20
Q

why is an aq solution of CuSO4 used as the electrolyte

A

Cu2+ migrates to the cathode where reduction occurs as Cu2+ is the strongest oxidant.
The migration of Cu2+ to the cathode (-) and sulfate ions to the anode (+) prevents the build-up of charge at
each electrode.
Copper (II) sulfate contains Cu2+(aq), which is involved in the two half-reactions, and sulfate ions which do
not react under the reaction conditions.

21
Q

identify and explain one factor that may affect the useful life of Na-S test cell

A
  • If discharge product is not in contact with the electrode battery life/efficiency is reduced because the
    battery cannot be recharged, and reactions cannot be reversed.
  • Side reactions reduce the efficiency of the cell by reducing the amount of useful product that can be
    recharged.
  • High temperatures increase the possibility of increasing side reactions.
  • Low temperatures increase the possibility of crystallisation
22
Q

effect of temp on viscosity

A

As temperature increases, the viscosity decreases / time decreases.
At higher temperatures, the average kinetic energy of the molecules is higher. This increases the frequency
of collisions between molecules and weakens the intermolecular forces, causing lower viscosity.

23
Q

why do the two half cells need to be separated

A
  • The half-cells need to be separated so that electrons can travel between the two half-cells in connecting wires (through the load) and the electrical energy harnessed.
  • The bacteria are anaerobic, and the oxygen needs to be excluded from the oxidation half-cell; if the half-cells are not separated, electricity will not be produced.
  • If there was no separation of the two half-cells, oxidation and reduction would occur together and electrons would not move through the external circuit.
24
Q

give one reason why the moderate intake of fat is necessary

A
  • provides essential fatty acids that the body can’t produce
25
Q

types of enzyme catalysed chemical reactions involving proline in the human body

A
  • undergo condensation reactions to form proteins/enzymes
  • be formed from hydrolysis reactions of proteins/enzymes
  • undergo oxidation reactions as it is broken down into smaller molecules
26
Q

how the polarity of the electrodes is established during recharge to allow the recharge to occur

A
  • the recognition that the electrode polarity does not change when the system is changed from discharge to recharge. The relative reductive and oxidative strength of the chemicals present in the galvanic cell is what determines the polarity, and this is fixed for both the discharge and recharge processes.
  • the recognition that the external power source causes the process to change at each electrode. This means that during the recharge the positive electrode becomes the anode and oxidation occurs here. This reversal of processes means that the original chemicals can be re-formed and hence the cell is recharged.
27
Q

how does the increase in temp affect the value of the equilibirum constant (exothermic reaction)

4 marks

A
  • stating that the equilibrium constant decreases.
  • recognising that the forward reaction is exothermic or the back reaction is endothermic.
  • establishing that the increase in temperature causes the system to partially oppose this stress by causing a shift in the reverse direction, or by stating that the increase in temperature increases the rate of the back reaction more than the rate of the forward reaction.
  • establishing that the [reactants] increases and the [products] decreases.

have to say both conc of reactants and products change and state the changes