exam #3 Flashcards
most common bases used in elimination reactions are
alkoxides
common bases used in dehydration
sodium hydroxide, potassium hydroxide, sodium methoxide, sodium ethoxide, potassium tert-butoxide
alkenes are classified by
number of carbon atoms bonded to the carbons of the double bond
stability of an alkene increases as the number of
R groups bonded to the double bond carbons increases
higher s character =
how much easier an atom accepts electron density
trans isomer
when R groups are on opp sides
cis isomer
when R groups are on same side
stereoisomers on C=C bond is possible when
two groups on each C must be different
what is more stable? trans or cis alkenes?
TRANS b/c groups bonded to double bond carbons are further apart (reducing steric interactions)
E2
bimolecular elimination
E1
unimolecular eliminiation
E2 and E1 differ in
timing of bond cleavage and formation (analogous to SN2 and SN1)
most common mechanism for dehydrohalogenation?
E2
rate = k[(CH3)3CBr][-OH]
all bonds are broken and formed in a single step
E2 generally has
strong, neg charged bases (-OH, -OR)
uses DBN and DBU
what are DBN and DBU?
sterically hindered nitrogen basese
base appears in (x) so rate of E2 rxn (y) as strength of (z)
rate equation
increases
base increases
when the base strength increases so does the
E2 reaction rate
the better the leaving group, the
faster the E2 rxn
polar aprotic solvents
increase E2 rxn rates
SN2 and E2 mechanisms differ in
how the R group affects the rxn rate
as the number of R groups on the carbon with the leaving group increases,
rate of E2 rxn increases
when alkyl halides have two or more different Beta-carbons,
more than one alkene product is formed
one of the product usually predominates when this happens
major product is more
STABLE (has more substituted double bond)
zaitsev rule
formation of major and minor product when alkyl halides have 2+ different beta-carbons
zaitsev rule:
the major product in beta-elimination has the more substituted double bond
regioselective:
when it yields predominantly or exclusively one constitutional isomer when more than one is
when a mixture of stereoisomers is possible from a dehydrohalogenation…
the major product is the more stable stereoisomer
stereoselective:
when rxn forms predominantly / exclusively one stereoisomer when 2+ are possible
e2 rxn is stereoselective bc
one stereoisomer is formed preferentially
rate of E1 rxn increases as
number of R groups on carbon w/ leaving group increases
strength of the base determines
whether a rxn is E1 or E2
strong bases favor
E2
weaker bases favor
E1
E1 rxns are
regioselective
- favor formation of the more substituted, more stable alkene
zaitsev’s rule applies
SN1 and E1 have the same
first step (formation of a carbocation)
SN1 and E1 differ in
what happens to the carbocation
E1 competes w/
SN1
E1 rxns of alkyl halides are much less
useful than E2 rxns
transition state of an e2 rxn consists of
four atoms from an alkyl halide
one H atom
two C atoms
leaving group (x)
all aligned in a plane
two ways for C–H and C–X to be
coplanar
syn periplanar
H and X are on same side
anti periplanar
H and X are on opp sides
E2 elimination require the
anti periplanar geometry
anti periplanar arrangement has a
staggered conformation
two electron-rich groups are far apart
PREFERRED GEOMETRY
syn periplanar arrangement has an
eclipsed formation
two electron-rich groups are close
strength of base is the
MOST important factor in determining mechanism for elimination
a single elimination rxn produces a
pi bond of an alkene
two consecutive elimination rxns produce two pi bonds of an alkene
alkynes are prepared by
two successive dehydrohalogenation rxns
two elimination rxns are needed to
remove two moles of HX from a dihalide substrate
vicinal dihalide or a geminal dehalide –>
two different starting materials can be used in elimination rxns that remove two moles of HX from a dihalide substrate
to synthesize alkenes,
stronger bases are needed
typical bases used -NH2 (amide)
good nucleophiles that are weak bases favor
substitution over eliminiation
why do good nucleophiles favors sub over elimination?
certain anions generally give products of substitution b/c they are good nucleophiles/weak bases
e.g. I-, Br-, HS-, -CN, CH3COO-
bulky non-nucleophilic bases favor
elimination over substitution