Exam 2 Flashcards

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1
Q

So far, we have assumed that all that’s required for learning are contiguous pairing of stimuli which are arranged in a specified order (temporal relationship).
Question: will any arrangement do?
List the six arrangements.

A
  1. Delay conditioning;
  2. Trace conditioning;
  3. Simultaneous conditioning;
  4. Backward conditioning;
  5. Inhibition of delay;
  6. Temporal conditioning.
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2
Q

Explain delay conditioning.

A

Delay between CS onset and US onset and CS offset is never before US onset.
- Never a time gap between CS & US.
CS______——-______
US__________—–___

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3
Q

Explain trace conditioning.

A

CS offset before US onset. The neurological firing peters out after CS and before US. )
CS_______——-__________
US_________________——-_____
“Trace” refers to the neurological firing caused by the CS

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4
Q

What is simultaneous conditioning?

A

CS onset = US onset and CS offset = US offset. (CSUS)
CS______——_______
US______——_______

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5
Q

What is backward conditioning?

A

CS onset is after US onset. (US/CS)
CS__________——_____
US_______——________
According to Pavlov, the stimulus that becomes an effective CS+ is the one creating afferent activity (neurological activity) immediately prior to US onset.
Therefore, according to Pavlov, delayed conditioning should be more effective than trace conditioning, & neither simultaneous no backward conditioning should be effective at creating a CS+. He’s NOT saying that there is no learning, just no excitatory learning. By and large, the studies support Pavlov’s predictions.

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6
Q

What is inhibition of delay?

A

Special kind of delay conditioning, it is a delay conditioning with a long duration CS.
CS____—————_____
US____________——-__
Rs_____))))))))))))))))))))))))))_____ < early
Rs__________))))))))))))))_____ < later

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7
Q

What is temporal conditioning?

A

US alone (US).
US________——–_______
Rs______)))))))))))))))_______ < late in conditioning
CR^ ^UR
Looks like animal can tell time? CONTEXT is always there
It can be argued that the context (not time) becomes the effective CS+
In this way, it is similar to the inhibition of delay, such that the context is a long duration CS.

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8
Q

What is learned during Classical conditioning? In other words, what associations are being made? i.e., what kind of association is learned? What are the two possibilities?

A

S-S association - S-S Theory (association made between the CS and the US)
S-R association - S-R Theory (association made between the CS and the UR)

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9
Q

Explain S-R Theory.

A

Forward CS/US parings ensure that a particular response, the UR, always occurs shortly after the CS.
Events:
CS_______——______
US_______——______
UR_______)))))))______
This results in a contiguous temporal relationship between the CS and the UR (i.e., CS/UR)
Argued that the CS & UR become associated.
Therefore, presentation of the CS evokes a memory of the UR.
This CS elicited Response is called the CR.

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10
Q

How do we determine if learning is the result of S-R or S-S association?

A

A variety of investigative strategies.

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11
Q

Explain Strategy A for S-R/S-S theory

A

Prevent the occurrence of one of the postulated elements of the association and see how that affects learning (conditioning). In other words, prevent either CS or UR. It doesn’t make sense to prevent the CS, therefore we must focus on the UR.
We can prevent the UR a number of different ways: surgery, drugs, or procedural changes.
Therefore, we have the following situation: CS –> US –> ur (there is no UR). Because the CS - UR association is prevented, S-R theory predicts no learning.

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12
Q

Explain an experiment for strategy A for investigating S-R Theory using drugs

A
  • Use the drug Atropine to block saliva UR
  • Phase 1: drugged dogs get forward CStone/USfood training. There is no UR saliva, therefore no CS-UR association can form.
    After training the drug wears off.
  • Phase 2: Recovered dogs get CStone alone test trials.

Result: dogs salivate to the CStone (CR saliva). i.e., even though the CS-UR association was prevented, the CS elicits CRs. i.e., the dogs learned.
This result DOES NOT support S-R theory, as S-R theor would predict no learning (because an S-R association couldn’t have formed).

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13
Q

Explain an experiment for strategy A for investigating S-R theory using procedural changes to prevent CS-UR association.

A
Procedure we are going to use is called "sensory preconditioning". (First two phases are sensor preconditioning).  First two phases trained to asymptote.
- Phase 1: forward CS1 CS2 trials
CS2(tone)\_\_\_\_----\_\_\_\_\_\_\_\_
CS1(light)\_\_\_\_\_\_\_-----\_\_\_\_\_
Rs\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_
  • Phase 2: animals
    CS(light)_________—–_______
    US(food)____________—–____
    Rs______________))))))))))))____

Phase 3: Test
CS2(tone)____________——____
we have procedurally prevented a contiguous relationship between CS2 and the UR.
S-R theory predicts no learning in this situation, because the CS2-UR association was prevented procedurally.
Result:
Phase 3:
CS2(tone)____________——-______
Rs__________________))))))______
CR^
Conclude: Learning has occurred. This conclusion does not support S-R theory.

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14
Q

Show another way of notating Strategy A for investigation S-R theory using procedural changes to prevent CS-UR association.

A
(First two phases trained to asymptote)
Phase 1: CS2/CS1
Phase 2: CS1/USfood
Phase 3: CS 2 alone trials
Phase 3 we see CRs, therefore, does not support S-R theory.
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15
Q

Explain strategy B in investigating S-R theory.

A

Alter the value of the US AFTER conditioning and see if the behaviour to the CS is affected. (It shouldn’t be according to S-R theory).

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16
Q

Explain the experiment used to evaluate strategy B for S-R theory.

A

Phase 1:
Forward CStone/USfood pairings trained to asymptote.
CStone —> USfood —> URsaliva
……> CRsaliva

Phase 2:
Change vale of US.
USfood –> Lithium injection –> animal vomits
1 forward USfood/Lithium(vomit) trial
This changes the value from appetitive to aversive, but the previous CStone - URsaliva association is unaffected because the CS and vomiting are not presented together.

Phase 3:
CStone alone test trials
If an S-R association is earned, then this association sould be intact. Therefore, S-R theory predicts we should get CR saliva.
Result: No CR saliva
Does not support S-R theory.
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17
Q

What is S-S (Stimulus - Substitution) theory?

A

Argued that CS - US associations are formed.
How can this generate behaviour?
Pavlov came up with Stimulus Substitution theory:
- Used to explain how stim stim can result in behaviour
- Pavlov argued that the CS gets associated with the US node in the brain.
-How does this work? The CS activates the US node in the brain. Activation of the US node causes (elicits) a particular set of Responses, called URs
REFER TO NOTES

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18
Q

Explain the sensory preconditioning experiment for S-S theory.

A

Uses the sensory preconditioning procedure to prevent the CS-UR association procedurally.

Phase 1: CS2/CS1
Phase 2: CS1/USfood
Phase 3: CS2
Result: CR saliva to CS2

Conclude: During phase 1, an association between CS2 & CS1 formed. During phase 2, an association between CS1 and the US forms, so in phase 3, the CS2 activates the CS1 node, the CS1 node activates the US node, and activation of the US node causes a response.

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19
Q

Explain the experiment where we change the status of the US after conditioning.

A

Phase 1: CStone/USfood trials
Phase 2: USfood/Lithium injection (animal vomits, 1 trial learning).
Phase 3: CStone alone trials
Result: No CR saliva
Conclude: Support S-S theory. During phse 1, an association between the CStone and the USfood. Therefore, CS willl activate the USfood node in the brain –> USfood node activates tLithium node –> no saliva.

20
Q

What is higher order conditioning?

A
Taking neighbors dog for a walk example:
CS4Phone ringing/CS3Robin
CS3Robin/CS2leash
CS2leash/CS1open door
CS1open door/USwalk

i.e., you can’t say the word “walk” in the house because the dog will get excited, this is higher order conditioning.

21
Q

Give the horse training example for higher order conditioning

A

CS4/CS3 - looking where you’re going (1 oz of pressure) - 4th order CS
CS3/CS2 - Straightening posture (2 oz of pressure) - 3rd order CS
CS2/CS1 - Squeeze buttocks (3 oz of pressure) - Second order CS
CS1/US - Squeeze legs together (4 oz of pressure) - First order CS

22
Q

Explain the second order conditioning & Change CS1 status experiment

A

Phase 1:
CS1light_________——_______
USfood____________—_____
Rs______________))))))))_____ (Saliva)

Phase 2: 
CS2tone\_\_\_\_\_\_\_\_-----\_\_\_\_\_\_\_ 
CS1light\_\_\_\_\_\_\_\_\_\_\_\_------\_\_\_
Rs\_\_\_\_\_\_\_\_\_\_\_\_\_\_)))))))))))))\_\_\_
CS2tone becomes a second order CS

Phases 1 & 2 is second order conditioning because we went as high as the second order CS.

Phase 3:
CS1light________——_______
USshock___________—-____
Rs______________)))))))))____ <– leg flexion

Phase 4:
CS2tone_______—–_____
R_____________)))))_____ saliva

Result: CR saliva
S-S theory predicts leg flexion, but we see CR saliva. This supports S-R theory.

Evidence of S-R associations is quite common in second and higher order conditioning studies.

23
Q

What is learned in classical conditioning?

A

Stimulus response and stimulus substitution associations.

24
Q

What is behaviour inhibition?

A

The active suppression of a response.

25
Q

What are the two categories of behavioural inhibition that Pavlov delineated?

A

a) external inhibition

b) internal inhibition

26
Q

Explain External Inhibition

A

Refers to the presentation of a novel stimulus shortly before o during a CS+. The novel stimulus “inhibits” the CR normally elicited by the CS+.

Does not require past experience with the novel stimulus. Therefore called unconditioned inhibition (i.e., it’s not learned).

27
Q

Explain internal inhibition.

A

Does require past experience with the stimulus. Therefore called learned or associative inhibition.

Why not call it conditioned inhibition? Because someone named a procedure “conditioned inhibition”.

Learned inhibition requires past experience with the Stimulus.\Past experiences: antecedent conditions. Thought to be necessary for a stimulus to become an associative inhibitor (CS-)

28
Q

Describe Extinction

A

CS+ alone trials

29
Q

Describe inhibition of delay

A

Delay conditioning with a long duration CS. Or, long duration CS/US trials.

30
Q

Describe Differential conditioning

A

2 types of trials that are randomly presented over training.

i) CS1/US trials
ii) CS2 alone trials (the CS2 is the putative CS-. Thought that the CS2 will become an associative inhibitor.

Daycare analogy:
i) kid 1 –> grabs a toy from kid 2 –> kid 2 shouts “no!”
over time, kid 2 will shout “no” when kid 1 comes over.
ii) Kid 3 (who never grabs a toy away from kid 2)

31
Q

Describe conditioned inhibition procedure

A

2 types of trials that are randomly presented over training.

i) CS1/US trials
ii) CS1CS2 trials (i.e., simultaneous CS1CS2 alone trials) - a compound CS alone trial.

Daycare analogy:

i) Kid 1 –> grabs toy from kid 2 –> kid 2 shouts “no!”
ii) Kid 1 with daycare worker ) compound CS

Believed that CS2 (the daycare worker becomes a CS- (the putative inhibitor)

32
Q

Describe the unpaired procedure

A

2 types of trials randomly presented to the organism over training.
i) CS alone trials
ii) US alone trials
It is believed that the CS is thought to acquire associative inhibitory properties (putative CS-)

Daycare analogy

i) Daycare worker is in view (CS)
ii) daycare worker is never in view when the toy is grabbed

33
Q

Describe backward conditioning

A

US/CS trials
The CS is thought to acquire associative inhibitory properties (putative CS-)

Daycare analogy:
Kid 2 sees daycare worker, immediately after toy has been grabbed but never before the toy has been grabbed.

Note: we expect no responding for a CS-. But also expect no responding to an ineffective CS.
- Need to be able to distinguish a CS- from an ineffective CS.

34
Q

what are the three criteria for a CS-?

A
  1. The CS- must be a discrete stimulus or stimulus complex.
  2. The actions of the CS- must be specific to the US employed.
    3a. The actions of the CS- must be opposite to the excitatory actions (effects of the US) But not all responses have an opposite.
    3b. Responding in the presence of the CS- must be less than responding in its absence.
35
Q

What are the results of four of the experiments for behavioural inhibition.

A

Unpaired = Strong CS-
Backward = moderately strong CS-
Differential 1 = Moderately strong CS-
Conditioned inhibition procedure = No CS-

36
Q

What is stimulus generalization?

A

Little Albert example:
Conditioned to fear white rat. Also was afraid of white rabbits, santa clause beard, etc. This is stimulus generalization.

37
Q

How do we know that contiguity alone is not sufficient to understand learning?

A

The blocking (aka overshadowing) experiment.
Phase 1. CSnoise/USshock
Phase 2. CSnoiseCSlight/USshock
Phase 3. CSlight

Result: No CRs to CSlight even though the light and the shock were contiguous. Uh oh!
Blocking demonstrates that contiguity is not sufficient for learning It may be necessary for learning, but it is not sufficient (handout on necessary and sufficient).

38
Q

If contiguity is not sufficient for learning, what is?

A

Rescorla suggested Contingency
i.e., that learning required some dependency between stimuli.
But, blocking experiment:
Phase 1. CS1CS2/US presentation of the US is entirely contingent on the CS2 being presented.
Phase 3. CS2

No CRs to CS2 in Phase 3. So, the blocking experiment demonstrated that neither contiguity nor contingency is sufficient for learning. Both are necessary for learning, but not sufficient.

ENTER RESCORLA-WAGNER THEORY

39
Q

What is Rescorla-Wagner theory?

A

A linear model of association formation.

ChangeVA = alpha x beta (lambda - Vbar)

40
Q

In the linear model of association formation, what does V stand for?

A

Association strength

41
Q

In the linear model of association formation, what does triangleVA stand for?

A

The change (triangle) in associative strength incurred by CS(A) on a given trial

42
Q

In the linear model of association formation, what does alpha stand for?

A

the learning rate parameter for the CS
- reflects CS intensity. Ranges between 0 (lowest) and 1 (highest possible intensity).
Note: if a CS is not presented on a given trial, no value for alpha is given.

43
Q

In the linear model of association formation, what does beta stand for?

A

The learning rate parameter for the US
Reflects US intensity
Ranges from 0 (lowest possible intensity) and 1 (highest intensity possible)
If a US is not presented on a given trial, no value is given for Beta for that trial.

44
Q

In the linear model of association formation, what does Lambda stand for?

A

The level of conditioning that a US will support. i.e., asymptote. If a US is not presented Lambda = 0 No US, Lambda still gets a value (0).

45
Q

In the linear model of association formation, what does Vbar stand for?

A

The summed associative strength of all the CSs presented on a given trial.

46
Q

If Lambda minus Vbar is a positive value (number)…

A

Then the associative strength of all the CSs that were presented on that trial is incremental.
If the net associative strength of a CS is positive, the CS is excitatory with respect to the US (i.e., is a CS+)

47
Q

If Lambda minus Vbar is a negative value (number)…

A

Then the associative strength of all the CSs that were presented on that trial is decremental.
If the net associative strength of a CS is negative, the CS is inhibitory with respect to the US (i.e., a CS-)