Exam 2 Flashcards
solution
a homogenous mixture made up of a solute and solvent
solvent
generally present in larger amounts and does not change shape (ex: salt water) - what is doing the dissolving
solute
present in smaller amounts and might change shape (ex salt) - what is being dissolved
aqueous solution
water is solvent and used to dissolve the solution
concentration
general term referring to relative amounts of solute and solvent
dilute
relatively small amounts of solute
molarity formula
of moles in solute/ #liters of water
chemical reaction types
- Precipitation reactions - exchange of ions (switch metals)
- acid-base reaction - transfer of a proton (H+)
- oxidation-reduction reactions - transfer of electrons
precipitate reaction table
Compound of
Li+, Na+, K+, NH4+, NO3-, CH3OO-, HCO3-, ClO3- —-> ALWAYS SOLUABLE
Cl-, Br, I- —-> insoluble with Ag+, Ag2+, Pb2+
F- —-> insoluble with Pb2+, Fe3+
SO4(-2) —-> insoluble with Ag+,Ag2(2+), Pb2+, Ba2+, Sr+
CO3(_2), PO4(-3), CrO4(-2), S(-2) —-> soluble with Li+, Na+, K+, and NH4+
HO- —> soluble with Li+, Na+, K+, NH4+ (group 1) and Ba(2+)
strong acid
completely ionizes (breaks apart) in water
weak acid
partially breaks apart in water
strong base
completely breaks apart in water to give an HO-
weak base
partially breaks apart in water to give an HO-
strong acids (7)
HCl - hydrochloric acid
HNO3 - nitric acid
H2SO4 - Sulfuric Acid
HBr - hydrobromic acid
HI - hydroiodic acid
HClO4 -perchloric acid
HClO3 - chloric acid
Weak Acids (7)
HO2C2O2H - Oxalic acid
H2SO3 - Sulfurous acid
H3PO4 - Phosphoric acid
HNO2 - Nitrous acid
C6H5COOH - Benzoic acid
CH3COOH - Acetic acid
HCOOH - Formic acid
Oxidation
loss of electrons (but getting higher in numbers)
reduction
gain of electrons (getting lower in numbers)
rules for oxidation numbers
- If element is alone then its 0
- if there’s a charge when its alone its that charge
- oxygen is -2 except in peroxide (O2(-2) its -1)
- hydrogen is 1+ w/ most nonmetals and -1 with metals
- fluorine is always -1 in its compounds
- the sum of oxidation numbers of all atoms must equal the charge on the species (zero for neutral species)
balancing- oxidation-reduction equations rules
- write 2 half reactions
- figure out oxidation numbers and oxidation/reductions
- Balance oxygen by adding H2O molecules
- Blanca hydrogen atoms by adding H+ ions
- balance the charge by adding electrons
- if needed multiply each half-reaction by the smallest possible integer
- add the half-reactions together and simplify by removing species that appear on both sides of equations
if an equation is under basic conditions
Proton cannot exist any H+ so add an OH-
concentration solving
when volume goes up concentration goes down and vice versa (mxv = your concentration)
if your give the same compound twice then find a concentration of each then divide by the final volume (m1v2+m2v2/v3)