Evolution 7 - Hardy-Weinberg Principle Flashcards

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1
Q

What are the 5 agents of evolutionary change?

A

-Mutation
-Gene Flow
-Non-Random Mating
-Genetic Drift
-Selection

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2
Q

What is a population?

A

A population is a localized group of interbreeding individuals.

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3
Q

What is a gene pool?

A

A gene pool is a collection of alleles in a particular population.

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4
Q

What is the difference between alleles and genes?

A
  • Genes are DNA sections that code for specific proteins or functional RNA, which play a crucial part in biological functions.
  • Alleles, however, are variations of these genes, leading to diverse traits such as eye or hair color.
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5
Q

What is allele frequency?

A

How common that allele is in the population (how many of A or a in whole population).

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6
Q

What does it mean when a population evolves?

A
  • Evolution is a change in allele frequencies in a population.
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7
Q

What conditions would cause allele frequencies not to change? (1 point, 5 subpoints)

A
  • In a non-evolving population, you would need to remove all agents of evolutionary change.
    1. Very large population size (No genetic drift)
    2. No migration (No gene flow in or out)
    3. No mutation (No genetic change)
    4. Random mating (No sexual selection)
    5. No natural selection (Everyone is equally fit)
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8
Q

In a non-evolving population, what are preserved? (2 points with 2 subpoints)

A

-Allele frequencies are preserved, and they are said to be in Hardy-Weinberg equilibrium.
-But:
1. Natural populations are rarely in Hardy-Weinberg equilibrium.
2. However it provides a useful model to measure if evolutionary forces are acting on a population.

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9
Q

How do you count Alleles? (Hardy-Weinberg Theory)

A
  • Assume 2 alleles = B, b
  • Frequency of dominant allele (B) = p
  • Frequency of recessive allele (b) = q
  • Frequencies must add up to 1 (100%), so:
    p + q = 1
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10
Q

How do you count Genotypes? (Hardy-Weinberg Theory)

A

-Frequency of homozygous dominant: p x p = p^2
-Frequency of homozygous recessive: q x q = q^2
-Frequency of heterozygotes: (p x q) + (q x p) = 2pq
-Frequencies of all individuals must add to 1 (100%), so:
p^2 + 2pq + q^2 = 1

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11
Q

What are the Hardy-Weinberg formulas?

A

-Alleles (B and b): p + q = 1
-Genotypes (BB, Bb, and bb): p^2 + 2pq + q^2 = 1

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12
Q

In the part of the formula, (p+q)^2, where can I find information about the frequency of allele types?

A

p = Frequency of allele B
q = Frequency of allele b

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13
Q

In the part of the formula, p^2 + 2pq + q^2, where can I find information about the frequency of allele combinations?

A

-p^2 = Frequency of BB (homozygous dominant)
-2pq = Frequency of Bb (heterozygous)
-q^2 = Frequency of bb (homozygous recessive)

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14
Q

What is the part of the formula that tells us the frequency of the allele combination BB in a population?

A

p^2

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15
Q

What is the part of the formula that tells us the frequency of the allele combination Bb in a population?

A

Add “Bb” and “Bb” together to get 2pq

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16
Q

What is the part of the formula that tells us the frequency of the allele combination bb in a population?

A

q^2

17
Q

What are the steps to solving Hardy-Weinberg problems?

A
  • Remember to use proportions in your calculations, not percentages!
    1. Examine question to determine what information is given; In most cases this is the frequency of the homozygous recessive phenotype q^2 or the allele q.
    2. Take the square root of q^2 to find q or multiply q to find q^2
    3. Find p by subtracting q from 1 (p = 1 – q)
    4. Find p^2 by multiplying it by itself (p2^2= p x p)
    5. Find 2pq by multiplying p x q x 2
    6. Check that your calculations are correct by adding values for p^2 + q^2 + 2pq
18
Q

What does the Hardy Weinberg principle show?

A

It shows that In a non-evolving population, allele frequencies are preserved (they are said to be in Hardy-Weinberg equilibrium).

19
Q

Why do we use the Hardy Weinberg principle?

A

We use it to measure if evolutionary forces are acting on a population.

20
Q

What are the criteria that must be met? (5 points)

A
  • Very large population size (no genetic drift)
  • No migration (no gene flow in or out)
  • No mutation (no genetic change)
  • Random mating (no sexual selection)
  • No natural selection (everyone is equally fit)
21
Q

A population of mice has a gene consisting of 90% B alleles (black fur) and 10% b alleles (gray fur). Determine the proportion of offspring that will be black and the proportion that will be gray.

A

Recessive allele q = 0.1 Given
Dominant allele p = 0.9 1 – q = p 1 – 0.1 = 0.9
Recessive phenotype q2 = 0.01 q x q = q2 0.1 x 0.1 = 0.01
Homozygous dominant p2 = 0.81 p x p = p2 0.9 x 0.9 = 0.81
Heterozygous 2pq = 0.18 2 x p x q = 2pq 2 x 0.9 x 0.1 = 0.18
Check q2 + p2 + 2pq = 1 0.01 + 0.81 + 0.18 = 1
Black: 0.99
0.81 + 0.18 = 0.99
Gray: 0.01

22
Q

A population of 134 lizards has 81 individuals with green skin and a gg genotype. The remaining 53 individuals have yellow skin and therefore have either the GG or Gg genotype. What proportion of the population are homozygous dominant?

A

Recessive allele q = 0.77 √0.60 = 0.77
Dominant allele p = 0.23 1 - 0.77 = 0.23
Recessive phenotype q2 = 0.60 81/134 = 0.60
Homozygous dominant p2 = 0.05 0.23 x 0.23 = 0.05
Heterozygous 2pq = 0.35 2 x 0.77 x 0.23 = 0.35
0.60 + 0.05 + 0.35 = 1