Equilibrium

Question 0

Properties of the eq constant (Keq)

Answer 0

(s) and (l) don’t appear in the expression
Keq changes with temp
Keq»> 1 than the eq favours the products
Keq«< 1 ‘’ ‘’ reactants
Keq close to 1 then about = amounts of products and reactants

Question 1

The Law of Mass Action

Answer 1

Keq = each rate constant (k1,k2,k3/k-1,k-2,k-3) will equal
[C]^c[D]^d
———— for the reaction aA + bB cC + dD
[A]^a[B]^b

Question 2

Increasing the pressure of the system favors?
Decreasing ‘’ ‘’?
N2(g) + 3 H2 (g) 2NH3 (g)

Answer 2

increasing the pressure favors the side of the eq with fewer moles.
decreasing the pressure favors the side with more moles.
N2(g) + 3 H2 (g) 2NH3 (g)
increasing pressure = more NH3
decreasing pressure = more N2 and H2

Question 3

Qsp > Ksp
Qsp < Ksp
Qsp = Ksp

Answer 3

Qsp > Ksp the solution is supersaturated and a decrease in temp forms a percipitate
Qsp < Ksp the solution is unsaturated and no solution will form
Qsp = Ksp the solution is saturated

Question 4

Keq = 0.16

A catalyst is added. Does the value of Keq increase or decrease?

Answer 4

Neither. Keq is not affected by catalysts. A equilibrium will not shift in the presence of a catalyst, because it has all ready reached equilibrium…

Question 5

Common Ion Effect

Answer 5

Reduces the solubility of certain ions in solution. Does not change Ksp. See youtube video/p501 for ex questions.