Équilibre chimique Flashcards

1
Q

Define reversible rxn

A

A reversible rxn is at dynamic chemical eqm when:
1. Rate of forward rxn = rate of backward rxn
2. Substances still react tgt though conc. of rxt & pdt remain constant (system does not undergo any observable change)

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2
Q

What is the expression for Kc and Kp for a reversible reaction aA+bB ⇌ cC+dD

A

Kc:
[C]^c [D]^d
_____________
[A]^a [B]^b

Kp:
(Pc)^c (Pd)^d
_____________
(P a)^a (Pb)^b

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3
Q

What is the formula for partial pa?

A

Partial pressure of A = nA/nT x P T

Where P T is total pressure, nA is amt of A, nT is total amt of gas

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4
Q

What do Kc values >1, = 1 and <1 mean?

A

Kc>1:
- higher prop n of pdt than rxt at eqm
- rxn proceed left to right to greater extent & form n of pdt favoured
- eqm pos n lies to the right

Kc=1:
- At eqm, conc. of both rxt & pdt abt the same

Kc<1:
- Lower prop n of pdt than rxt at eqm
- Rxn proceed right to left to greater extent & form n of rxt favoured
- eqm pos n lies to the left

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5
Q

What are properties of eqm constants?

A
  • temperature dependent.
  • A change in temp hv diff impact on exo & endo rxn.
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6
Q

What is the difference btw homogenous and heterogenous equilibria?

A

Homogenous:
All rxt, pdt in same physical state
eg all gas/all liquid
All rxt, pdt included in eqm constant expression (includes conc of water)

Heterogenous:
Not all rxt, pdt in same physical state
eg NH3(g) + H2O (l) ⇌ NH4+ (aq) + OH-(aq)
Expression no include:
- conc of water bcos it is the medium (its conc effectively constant)
- solids (bcos uniform conc)

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7
Q

What method to use to solve eqm problems?

A
  • ICE table
    (Initial, Change, Eqm amt)
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8
Q

State Le Chatelier’s Principle

A

When system in eqm subjected to change/stress which disturb eqm, system react to counteract effect of change/stress to re-establish eqm

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9
Q

How does eqm pos n change?

A

Shifts right, left or remain unchanged (meaning forward or backward rxn is favoured)

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10
Q

How is eqm pos n affected by conc change?

A
  • Increase in [rxt]/decrease in [pdt] shift eqm pos n to right
  • Decrease in [rxt]/increase in [pdt] shift eqm pos n to left
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11
Q

How is eqm pos n affected by Pa change?

A
  • Increase in Pa shift eqm pos n to decrease amt of gas
  • Decrease in Pa shift eqm pos n to increase amt of gas
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12
Q

What happens with change of amt of gas in a rxn?

A
  • change amt of gas hv same effect as change partial Pa of that gas
    (from pV=nRT, p is proportional to conc and to amt)
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13
Q

What happens with volume change of rxn vessel?

A
  • Compress n causes decrease in volume & corresponding increase in total Pa (& increase in partial Pa of each component gases in rxn)
  • Expans n of rxn vessel causes increase in volume & corresponding decrease in total Pa (& decrease in partial Pa of each component gases in rxn)
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14
Q

How does temp affect eqm pos n?

A
  • Increase temp
    eqm pos n shift towards endo rxn to absorb heat
  • Decrease temp
    eqm pos n shift towards exo rxn to release heat
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15
Q

What are 2 effects of catalyst?

A
  1. Increase both rate of forward & backward rxn to same extent, so eqm pos n is unchanged
    - thus, [rxt],[pdt] constant b4 & after add catalyst
    - Kc, Kp stay same
  2. Increase both rate of forward & reverse rxn to same extent so that dynamic eqm is established more quickly within shorter time
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16
Q

State and explain conditions used for Haber Process

A
  1. High Pa of 250atm
    too high Pa too expensive as thicker pipes needed to withstand high Pa, so 250atm is enough
  2. Moderate temp 450 C
    too low temp decrease rxn rate (not industrially viable), so moderate temp used
  3. Iron catalyst
    to increase rxn rate (does NOT affect NH3 yield)
  4. Molar ratio of N2: H2 is 1:3

(Thus, there is a compromise btw conflict demand of satisfy high yield, high rate & low cost of rxn)

17
Q

What is Gibbs Free Energy Change, dG? Explain

A
  • measure of spontaneity of rxn

dG<0: rxn spontaneous in forward rxn

dG>0: rxn not spontaneous in forward rxn, spontaneous in backward rxn

dG=0: system in eqm

18
Q

What is the eqn for standard Gibbs Free Energy Change, dGe? Explain

A

At eqm where dG=0 & Q=K,

dGe=-RT ln K

where R = 8.31, T is temp in Kelvin, K is Kc/Kp

If dGe«0, K&raquo_space;1; eqm pos n lies far to right, so rxn effectively complete. More pdt present

If dGe»0, K«1; eqm pos n lies far to left, so more rxt present