Equations Flashcards
Standard temp and pressure
0ºC (273.15 K) and 1 atm
Standard conditions
25ºC (298.15 K)
Boyle’s Law
pressure is inversely proportional to volume @ constant temp
P1V1=P2V2
*as pressure increases volume decreases @ constant temp (isothermal)
Charles Law
Volume is directly proportional to temperature @ constant pressure
V1 / T1 = V2 / T2
Combined Gas Law
P1V1 / T1 = P2V2 / T2
Avagadro’s law of Molar Volume
n (number of moles) is directly proportional to volume (V)
n1 / V1 = n2 / V2
if gases at equal volumes have the same pressure and temp, are equal in number of moles/particles/molecules
Under STP conditions ( 0C, 1 atm) 1 mole of any gas shall…
have a volume of 22.4 Liters
1 mole = 22.4 L @ STP
if gases at equal volumes have the same pressure and temp, are equal in number of moles/particles/molecules
Ideal gas law
PV = nRT
R= 0.0823 atm • L/ mol•K
molecular mass from ideal gas law
Molecular mass = nRT / PV = g / mol
(p) density = P • mr / RT = g / liters
Dalton’s law
Ptotal = PA + PB + PC
PV=nRT, therefore
PT = nA (RT/V) + nB (RT/V) +…
= nA + nB + nC (RT/V)
= ntotal(RT/V)
mole fraction (Xa)
XA = nA / nA + nB + nC = nA / ntotal
PA = XA • PT
graham’s law of effusion
rate of effusion of gas A / rate of effusion of gas B = ( mr of gas B)1/2/ (mr of gas A)1/2