Enzyme kinetics Flashcards

1
Q

Velocity versus substrate concentration

A

Initial reaction velocity only depends on the RDS which is K2, so as substrate concentration increases so does velocity.

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2
Q

Equation for velocity

A

v + d[P]/dt = K2*[ES]

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3
Q

Michaelis Menten equation

A

Hyperbolic
v = (Vmax*[S])/(Km+[S])

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4
Q

Michaelis constant

A

Km = (K-1+K2)/K1
describes the enzyme’s affinity for a substrate.

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5
Q

Equation for Vmax

A

Vmax = K2*[E]total

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6
Q

Kcat

A

The catalytic rate constant (turnover number) when the enzyme is saturated with S. Determines how quickly the enzyme acts in mechanistic terms.

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7
Q

Enzyme efficiency

A

is measured by Kcat/Km

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8
Q

Kcat/Km also indicates the preferred ______ of an enzyme.

A

Substrate

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9
Q

Lineweaver-Burk plot

A

Takes the reciprocal of the Michaelis-Menten data where slope = Km/Vmax, and y-int = 1/Vmax.

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10
Q

If a mutation to an enzyme decreases Kcat but does not affect Km, what does this reflect of the mutated amino acid?

A

The mutated amino must be important in the catalytic mechanism of the enzyme.

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11
Q

Irreversible enzyme inhibitors

A

Irreversible bind covalently to the enzyme active site so that it cannot perform catalysis. Decrease in a max due to decrease in available enzymes, but no change to Km.

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12
Q

Reversible enzyme inhibition

A

Inhibitors bind non-covalently and usually resemble the transition state. Distinguished by enzyme kinetics.

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13
Q

Classes of reversible enzyme inhibitors

A

Competitive
Non-competitive
Uncompetitive
Mixed

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14
Q

Competitive inhibitors

A

Bind to the active site such that a substrate-enzyme complex cannot form. Increases Km, but does not change Vmax.

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15
Q

Non-competitive inhibitors

A

Bind to the allosteric site to decrease the mechanistic efficiency of the enzyme. Decreases the Vmax and Kcat.

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16
Q

Mixed inhibitors

A

Bind to a more distant site that modifies both Vmax (decreases), and Km (increases).

17
Q

Exceptions to the Michaelis-Menten kinetics

A

It is only valid for the simple 2-step enzymes reactions, many others involve several substrates, products, and multiple steps. Km is a complicated function of many rate constants.

18
Q

Allosteric enzymes

A

Have multiple subunits that bind to substrates in a cooperative fashion that can either be positive or negative.

19
Q

Regulation by substrate availability

A

Effector - substrate
Result - change velocity
Time - immediate

20
Q

Regulation by product inhibition

A

Effector - product
Result - change Vmax/Km
Time - immediate

21
Q

Regulation by allosteric control

A

Effector - end product
Result - change Vmax/Km
Time - immediate

22
Q

Regulation by covalent modification

A

Effector - another enzyme
Result - change in Vmax/Km
Time - immediate to minutes

23
Q

Regulation by localisation

A

Effector - another enzyme
Result - change in cellular location
Time - immediate to minutes

24
Q

Regulation by enzyme synthesis/degradation

A

Effector - hormone/metabolite
Result - change in enzyme level
Time - hours to days

25
Regulation often involves an ____ and/or ________ sep in the metabolic pathway
early; commited