Enzyme Kinetics Flashcards

1
Q

What is the simple model mechanism (pathway) used to examine enzyme kinetics?

A

A single substrate and product, with no inhibiters.
Where:
E represents the enzyme
S represents the substrate
ES = substrate-enzyme complex
P= product

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2
Q

What is the steady state?

A

concentration of enzyme-substarte complex remains relatively constant. Occurs because the rate of ES formation equals the rate of its breakdown

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3
Q

What is the km?

A

Michaelis Constant. It represents the substrate concentration at which the reaction velocity is half of Vmax. It is an approximate measure of the substrate’s binding affinity for the enzyme. higher km= weaker binding affinity
lower km= stronger binding affinity

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4
Q

What is kcat?

A

Turnover number
-reflects catalytic efficiency of enzyme
- how much substrate molecules are converted to product /enzyme moelcule/second when the zyme is saturated with substrate

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5
Q

How is the Michaelis-Menten equation related to the fraction of sites bound by a ligand?

A

there is a mathematical similarity. It highlights the connection between substrate binding and enzyme activity. If V0 / Vmax, then [S]/km + [S].
suggesting Km is analogous to Kf, and relfects the enzyme’s affinity for the substrate. Both Km and Kd represent the concentartion of a molcule at which half of the binding sites are occupied

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6
Q

What happens to the equation when there is very low [S]? Very high [S]? Is this consistent
with the kinetic curve, and why

A

very low [S]«Km
simplified to V0 = Vmax/Km. Reaction velocity is directly proportional to [S]

Very high [S]» Km simplifies to V0= Vmax. reaction becomes independent of [S] and reaches its maximum rate.

This is consistent with the typical hyperbolic kinetic curve for enzymes, where the initial velocity increases rapidly at low [S] and plateaus at high [S]

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7
Q

What is the enzyme specificity constant?

A

Kcat/Km It measures the catalytic efficiency of an enzyme. It represents how efficiently an enzyme converts a substrate into product

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8
Q

What does a high enzyme specificity value indicate?

A

It indicates high enzyme efficiency. Max value is limited by rate of diffusion of the substrate to the enzyme’s active site.

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9
Q

How is the equation for a Lineweaver-Burk plot determined?

A

obtained by taking the reciprocal of both sides of the Michaelis-Menten equation and rearranging the terms

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10
Q

What are the benefits of a Lineweaver-Burk plot with respect to determining kinetic
parameters of an enzyme?

A

linearizes the Michaelis-Menten relationship, allowing for easier determination of kinetic parameters such as Km and Vmax. It is particularly useful for analyzing:
○Two-substrate data
○Enzyme inhibition patterns

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11
Q

What is the slope of Lineweaver-Burk Plot?

A

Km/Vmax

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12
Q

What is the y axis of Lineweaver-Burk Plot?

A

1/V0

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13
Q

What is the x axis of the Lineweaver-Burk Plot?

A

=1/[S]

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14
Q

What is the y-intercept of Lineweaver-Burk Plot?

A

1/Vmax

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15
Q

What is the X-intercept of Lineweaver-Burk Plot?

A

-1/Km

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16
Q

What is the sequential mechanism?

A

Both substrates must bind to the enzyme to form a ternary complex before the reaction can proceed. This can occur in a random or rodered manner

17
Q

What is the ping-pong mechanism?

A

one subtrate binds and reacts, modifying the enzume. The first product is released before the second substrate binds and reacts

18
Q

What can a Lineweaver-burk plot tell us about 2 substrate?

A

This helps distinguish between sequential and ping-pong mechanism.